Simplify i³⁸. [i=√(-1)]

Answers

Answer 1

Answer: for the answer to the question above, the answer is simple, and it is -1 (because even powers of an imaginary number or i will always give a -1).I hope my answer helped you with your problem. Have a nice day!

Answer 2

Answer:

-1 ...................................................................you're welcome.

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1+4=5 2+5=12 3+6=21 8+11=
Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x?
Find the intercepts for the graph of the equation 8x-4y=24. type an ordered pair for y and x
The diagram shows a patio in the shape of a rectangle.The patio is 3.6m long and 3m wide. Mathew is going to cover the patio with paving slabs. Each paving slab is a square of side 60cm. Mathew buys 32 of the paving slabs. A) Does Mathew buy enough paving slabs to cover the patio? The paving slabs cost £8.63 each B) Work out the total cost of the 32 paving slabs.

Using the formula A=l•w solve the following word problem. You have enough wallpaper to cover 240 square feet. If your walls are 8 feet high, what wall length can you paper? a. Wall length of 40 feet
b. Wall length of 30 feet
c. Wall length of 3 feet
d. Wall length of 16 feet

Answers

Hi there! The answer is B.

You have enough wallpaper to cover 240 square feet. If your walls are 8 feet high, what wall length can you paper?

First write down our data:
A = 240 square feet
l = 8 feet

Now we can fill in the formula
240 = 8 × w

Switch sides.
8 × w = 240

Divide both sides by 8.
w = 240 / 8 = 30

Therefore the answer is B.
Wall length of 30 feet

Final answer:

Using the formula A=l•w to solve the wallpaper problem, where the area (A) is 240 square feet and the width (w) is the height of the walls (8 feet), we find that the wall length (length) that you can paper is 30 feet.

Explanation:

The subject of the word problem is finding the wall length you can cover with a given amount of wallpaper. In this case, the area of the wallpaper is 240 square feet, and the height of the walls is 8 feet.

The formula for the area of a rectangle is A=l•w, where A stands for area, l stands for length, and w stands for width. In this case, the 'width' is the height of the walls, which is 8 feet.

To find the length of the wall, we can rearrange the formula to l=A/w and substitute the given values. That means l=240/8, which gives us a wall length of 30 feet.

Therefore, the answer is b. Wall length of 30 feet.

Learn more about Area Calculation here:

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A carpenter uses 9 1/2 ft of cedar wood for every 12 1/3 ft of redwood for a construction project. If the carpenter uses 4 3/4 ft of cedar, how much redwood does he need

Answers

Answer:

your question doesnt make sense specify more

Step-by-step explanation:

Which inequality best models the situation if variable p is the length of a piece of wood in feet?The pieces of wood used in a building project must be less than 15/34 feet long. Show the possible lengths. A.
and
may be a negative number.

B.
and
must be a positive number.

C.
and
must be a positive number.

D.
and
may be a negative number.

Answers

B must be positive number

If f(x) = 2x + 3 and g(x) = x2 + 1,find f(g(3)).

Answers

Answer:

The value of f(g(3)) is 23.

Step-by-step explanation:

The given functions are

$f(x)=2x+3$

$g(x)=x^2+1$

We have to find the value of f(g(3)).

Substitute x=3 in the function g(x) to find the value of g(3).

$g(3)=3^2+1=9+1=10$

$f(g(3))=f(10)$ [g(3)=10]

Substitute x=10 in the function f(x) to find the value of f(10).

$f(10)=2(10)+3=20+3=23$

Therefore the value of f(g(3)) is 23.

Hello,

f(g(3))=f(3²+1)=f(10)=2*10+3=23
===========================

Isabel wants a coat that costs $60. She has saved $42. What fraction of the amount she needs has she saved ?

Answers

Simple.....

you have this fraction...

$(42)/(60)$

simplify...

42/6=7
and
60/7=10

Thus... $(7)/(10)$

Thus, she has saved $(7)/(10)$ of the money.

Find the amplitude, period, and phase shift of the function defined by:
y=3-2cos(3x+pi)

Answers

This is a sinusoidal wave with an amplitude of 2 , riding on a constant value of 3 .
The 3 isn't part of the function's amplitude ... the function wiggles between 2 under it
and 2 over it.

The period of the function is the change in 'x' that adds (2 pi) to the angle.

When x=0, the angle is pi

When the angle is (3 pi) . . .

3 pi = 3x + pi
2 pi = 3x
x = 2/3 pi The period of the function is 2/3 pi .

When x=0, the function is cos(pi) rather than cos(0).
So the function is a cosine with a phase shift of +pi.
It could also be described as a sine with a phase shift of -pi/2 or +3pi/2 .

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