What is the solution to the following inequality X/-2 > 5

Answers

Answer 1
Answer:

Answer:

x < -10

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify

x/-2 > 5

Step 2: Solve for x

  1. [Multiplication Property of Equality] Multiply -2 on both sides:                     x < -10
Answer 2
Answer:

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x > - 10

\large \mathtt \green{Step-by-step  \: explanation : }

\small \sf (x)/( - 2) > 5 \n

Solve forx

\small \sf (x)/( - 2) > 5 \n

common denominator is 2

\small \sf  ➪ (2x)/( - 2) >2 *  5 \n

\small \sf ➪  \frac{ \cancel{2}x}{  - \cancel{ 2}}  >2 *  5 \n

➪ - x > 2 × 5

➪ - x > 10

multiply by - 1

➪ - x × - 1 > 10 × - 1

x > - 10


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Determine whether the lines L1 and L2 are parallel, skew, or intersecting. L1:x=9+6t,y=12-3t,z=3+9t L2:x=4+16s, y=12-8s, z=16+20s parallel skew intersecting If they intersect, find the point of intersection. (If an answer does not exist, enter DNE.)

Answers

Answer:

L1 and L2 are skew

Step-by-step explanation:

Since the equation of the line is

L1:x=9+6t,y=12-3t,z=3+9t

L2:x=4+16s, y=12-8s, z=16+20s

then if they intersect each other , they will have both in that point P=(xp , yp ,zp) then

1)9+6t = 4+16s

2) 12-3t =2-8s

3) 3+9t = 16+20s

adding 2*2) to 1)

9+6*t + 24-6t  = 4+16*s + 4-16*s

33 = 8

since this is not possible , the error comes from our assumption that the lines intersect each other

then they are skew or parallel. They are parallel if their corresponding vectors are parallel , that is

L1 (x,y,z) = (9,12,3) + (6,-3,9)*t

L1 (x,y,z) = (4,2,16) + (16,-8,20)*t

then if they are parallel

(16,-8,20)= k*(6,-3,9)

16=6*k

-8 = -3*k

20= 9*k

since there is no k that satisfy for x , y and z simultaneously then L1 and L2 are not parallel

therefore L1 and L2 are skew

Final answer:

The lines L1 and L2 are neither parallel nor intersecting. Upon comparing their direction vectors and attempting to find a common solution, it is determined that they are skew.

Explanation:

In order to determine whether two lines in three dimensions are parallel, skew, or intersecting, we compare their direction vectors. The given lines L1 and L2 are in the form of parametric equations. The direction vectors for the lines are d1 = <6, -3, 9> for L1 and d2 = <16, -8, 20> for L2. To determine if they are parallel, we check if there is a constant ratio between the corresponding terms. This isn't the case here, so the lines are not parallel.

For skew lines, they neither intersect or are parallel. Since we have already confirmed the lines are not parallel, to confirm if they are skew we must try to find a common solution (point of intersection). If we cannot, then they are skew. However, solving the equations does not give a common solution, so they do not intersect either. Hence, the lines are skew.

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Product of 6 and 6r and the product of 8s and 4

Answers

The product of the numbers are 36r and 32s.

What is product?

When we multiply two numbers the resultant is called their product.

Given that, what can be the products of 6 and 6r and 8s and 4

a) 6 and 6r =

We can write it as =

6 x 6 x r

now multiply the numeric parts,

36 x r

= 36r

Similarly,

b) 8s and 4 =

We can write it as,

8 x s x 4

= 8 x 4 x s

now multiply the numeric parts,

= 32 x s

= 32s

Hence, the products are 36r and 32s.

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Product tells us we’re going to multiply.

6 x 6r = 36r

8s x 4 = 32s

We don’t have a number value to substitute in for r or s, so we just leave those variables as they are.

LMK if you have questions

Solve the equation 15.6 + (-1.8) =

Answers

The solution to the equation 15.6 + (-1.8) is 13.8.

The equation to solve is 15.6 + (-1.8).

First, add the two numbers: 15.6 + (-1.8) = 13.8.

The result is 13.8.

In this equation, you're adding a positive value (15.6) and a negative value (-1.8), which results in a smaller positive value. When you add a positive number and a negative number, you can think of it as moving to the right on the number line (positive direction) but not as far as you would if you were only considering the positive value.

So, the solution to the equation 15.6 + (-1.8) is 13.8.

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Since +(-) becomes (-) we can write the given problem as

15.6-1.8

Subtraction gives us 13.8

:)

The Range of both functions will be ?A)the set of natural numbers
B)the set of integers
C)all real numbers
D)the set of whole numbers
E)the set of rational numbers

Answers

Answer:

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b

b

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b

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b

b

it is b

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Step-by-step explanation:

A 15° sector in a circle has an area of 11.9 m2. What is the area of the circle?

Answers

A 15° sector in a circle has an area of 11.9 m2. What is the area of the circle?
The area of the circle will be found as follows:
the fraction of the sector=15/360=1/24
the area of the circle will be:
area=(fraction of the circle)/(fraction of the sector)*(area of the sector)
=1/(1/24)
×11.9
=285.6 m²

A conical paper cup has a radius of 2 inches. Approximate, to the nearest degree, the angle β (see the figure) so that the cone will have a volume of 60 in3.β = °

Answers

The angle β (see the figure) so that the cone will have a volume of 60 in3 is 82.05 degrees

Volume of a cone

The formula for calculating the volume of a cone is expressed as:

V = 1/3πr²h

where

r is the radius

h is the height

Given the following

volume = 60

radius = 2

h = r tanβ

Substitute

V = 1/3πr²(r tanβ)

Substitute

60 = 1/3(3.14)(2)³tanβ

180 = 25.12tanβ

tanβ = 180/25.12

β = 82.05 degrees

Hence the angle β (see the figure) so that the cone will have a volume of 60 in3 is 82.05 degrees

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I don't know where the angle β is, so I will make the assumption that tanβ = h/r
V = (1)/(3) \pi r^(2) h

V volume = 60
r radius = 2
h = r tanβ

tan \beta = (3V )/( \pi  r^(3) ) = ( 180)/(25,1) = 7,17 \n  \n  \beta = 82