Part of your electrical load is a 60-W light that is on continuously. By what percentage can your energy consumption be reduced by turning this light off

Answers

Answer 1
Answer:

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete question in the attached file.

The cost after 30 days is 60 dollars. As energy remains constant, the cost per hour over 30 days will be decreased.

\to (\$60)/((30 \ days)/(24\ hours)) = \$0.08 / kwh.

Thus, (\$0.08)/(\$0.12) = 0.694 \ kW *  0.694 \ kW  * 1000 = 694 \ W.

The electricity used is continuously 694W over 30 days.

If just resistor loads (no reagents) were assumed,

\to I = (P)/(V)= (694\ W)/(120\ V) = 5.78\ A

Energy usage reduction percentage = ((60\ W)/(694\ W) * 100\%)

This bulb accounts for 8.64\% of the energy used, hence it saves when you switch it off.


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With what speed must a ball be thrown vertically from ground level to rise to a maximum height of 41 m

Answers

Answer:

The speed must a ball be thrown vertically from ground level to rise to a maximum height is 28.35 m/s.

Explanation:

Given;

maximum vertical height of the throw, H = 41 m

Apply the following kinematic equation;

V² = U² + 2gH

where;

V is the final speed with which the ball will rise to a maximum height

U is the initial speed of the ball = 0

g is acceleration due to gravity = 0

V² = U² + 2gH

V² = 0² + 2gH

V² =  2gH

V = √2gH

V = √(2 x 9.8 x 41)

V = 28.35 m/s

Therefore, the speed must a ball be thrown vertically from ground level to rise to a maximum height is 28.35 m/s.

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Swinging a tennis racket against a ball is an example of a third class lever.
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Please select the best answer from the choices provided.
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Answers

Final answer:

Swinging a tennis racket against a ball as a third class lever in physics.


Explanation:

Swinging a Tennis Racket as a Third Class Lever

A tennis racket swinging against a ball is indeed an example of a third class lever in physics. In a third class lever, the effort is situated between the fulcrum and the load. In this case, the effort is provided by the player's hand gripping the racket handle, the fulcrum is the wrist joint, and the load is the ball being struck by the racket.

When a player swings the racket, the force applied by the player's hand exerts an effort on the handle of the racket. This causes the racket to rotate about the wrist joint acting as the fulcrum. The ball serves as the load, receiving the force and accelerating in the opposite direction.


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(a) How many kilograms of water must evaporate from a 60.0-kg woman to lower their body temperature by 0.750ºC?

Answers

Answer:

69.69 g

Explanation:

Evaporation of water will take out latent heat of vaporization.  Let the mass of water be m and latent heat of vaporization of water be 2260000 J per kg

Heat taken up by evaporating water

= 2260000 x m J

Heat lost by body

= mass x specific heat of body x drop in temperature

60 x 3500 x .750  ( specific heat of human body is 3.5 kJ/kg.k)

= 157500 J

Heat loss = heat gain

2260000 m= 157500

m = .06969 kg

= 69.69 g

Final answer:

Approximately 78 grams of water would need to evaporate from a 60.0-kg person to lower their body temperature by 0.750ºC. This calculation is based on the principles of thermodynamic heat transfer and the specific body temperature, latent heat of water vaporization, and specific heat capacity of the human body.

Explanation:

To calculate the amount of water mass from an individual's body that would need to evaporate to reduce their body temperature, we can use the principle of thermodynamic heat transfer. The basic equation is Q = mLv, where Q is the heat absorbed or lost, m is the mass, and Lv is the latent heat of vaporization.

In this case, knowing that at body temperature of 37.0°C, the latent heat of water vaporization (Lv) is approximately 2430 kJ/kg, we substitute these numbers. Given our desire to reduce body temperature by 0.750°C in a 60 kg human, we first calculate the amount of heat to dissipate (Q) using Q = mcΔT, where c is the specific heat capacity of the human body (roughly equivalent to that of water, 4.184 kJ/kg°C), m is the mass, and ΔT is the change in temperature.

The calculation is as follows:

Q = (60 kg)(4.184 kJ/kg°C)(0.750°C) = ~189 kJ

Next, we substitute Q into the Q = mLv equation to determine the mass m:

m = Q / Lv = 189 kJ / 2430 kJ/kg = 0.078 kg, or 78 grams

Hence, around 78 grams of water would need to evaporate from a 60.0-kg person to lower their body temperature by 0.750ºC.

Learn more about Heat Transfer here:

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While leaning out a window that is 6.0 m above the ground, you drop a 0.60-kg basketball to a friend at ground level. Your friend catches the ball at a height of 1.6 m above the ground. Determine the following.(a) the amount of work done by the force of gravity on the ball.(b) the gravitational potential energy of the ball-earth system, relative to the ground when it is released.(c) the gravitational potential energy of the ball-earth system, relative to the ground when it is caught.

Answers

Answer:

a) W = 25.872 J

b) - 35.28 J

c) - 9.408

Explanation:

a) The amount of work done by the force of gravity on the ball = Change in potential energy between the two vertical points = - mg (H₂ - H₁)

F = - mg (gravity is acting downwards)

F = - 0.6 × 9.8 = - 5.88 N

(H₂ - H₁) = (1.6 - 6) = - 4.4 m

W = (-5.88)(-4.4) = 25.872 J

b) Gravitational-potential energy of the ball when it was released relative to the ground = (- mg) H₁ = (- 0.6 × 9.8) × 6 = - 35.28 J

c) Gravitational-potential energy of the ball when it is caught relative to the ground = (-mg)(H₂) = -0.6 × 9.8 × 1.6 = - 9.408 J

How does the force of gravity change as the mass of one object doubles?

Answers

The force of gravity changes as the mass of one object doubles. As the mass of one object is doubled then the force between the objects also gets doubled.

What is Force?

Force is an influence which can change the motion of an object through the application of an external force. A force can cause an object with the mass to change its velocity, that is the object undergo acceleration.

Force is directly proportional to the mass of the object and the acceleration of the object. If we double the mass of one of the objects, then we double the strength of the force. If we double the masses of both the objects, then we quadruple the strength of force.

Learn more about Force here:

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If the mass of one of the objects is doubled, then the force of gravity between them is doubled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

Name at 2 areas of physics that make video games possible

Answers

Answer:

projectiles

electromagnetic

Answer:

Explanation:

física cuántica y  Quantum Moves