Find the first derivative for y = f(x). fox ) 3x² -5x-1 at a Pocat where a = 4
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Answer:
Step-by-step explanation:
f(x) = 3x² -5x - 1
f'(x) =2*3x - 5*1 +0
= 6x - 5
f'(4) = 6*4 - 5
= 24 - 5
= 19
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Answer:
there is the answer to do
is so that AP:BP=1:3 and point M is the midpoint of segment
CP
. Find the area of △ABC if the area of △BMP is equal to 21m2.
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Answer:
56 m²
Explanation:
A diagram can be helpful.
Triangles with the same altitude will have areas proportional to the length of their bases.
The altitude from B to PC is the same for triangles BMP and BMC, so they have areas that are in the same proportion as MP : MC. Since M is the midpoint of CP, MP = MC and ABMP = ABMC = 21 m². Then ...
... ACPB = 21 m² + 21 m² = 42 m²
The altitude from C to AB is the same for triangles CPA and CPB, so those triangles have areas in the sampe proportion as AP : BP = 1 : 3. Then ...
... ACPA : ACPB = PA : PB = 1 : 3
... ACPA : 42 m² = 1 : 3
So, the area of ∆CPA is 1/3 of 42 m², or 14 m². The area of ABC is the sum of the areas of CPA and CPB, so is ...
... AABC = ACPA + ACPB = 14 m² + 42 m²
... AABC = 56 m²
:(
Answers
Solution1:-
Statement : corresponding angles in similar triangles must be congruent .
Answer : True
Solution2:-
Statement : The hypotenuse of a right angle triangle has to be opposite of 90 degree .
Answer : True
Reason : We know that the side opposite to largest angle in a triangle is largest . Since in a right angle triangle 90 degree is the largest angle and hypotenuse is the longest side therefore they must be opposite to each other .
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A linear function contains no exponents and is straight. Any function with an exponent is not linear. x^2 is not a linear function; it is a parabola (a curve).
Hope this helps!!
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The answer is 3/20 or 0.15.
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Answer:
The surface area of the balloon is
Step-by-step explanation:
Given;
S(r) = 4πr²
where;
S is the surface area of the balloon
r is the radius of the surface
The radius of the balloon at time "t" is given as;
The surface area of the balloon as a function of time "t" is calculated as;