Find the sum. Express the answer in scientific notation. (1.54 x 10^6)+(6.15 x 10^6)​

Answers

Answer 1
Answer:

Answer:

{ \tt{(1.54 *  {10}^(6)) + (6.15 *  {10}^(6))  }} \n =  { \tt{(1.54 + 6.15) *  {10}^(6) }} \n  = { \tt{7.69 *  {10}^(6) }}


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When starting a heavy train, why will train engineers sometimes back up, stop, and then proceed forward? (This technique is called "bunching slack.")

Answers

it is kind of in the name. it brings the cars closer together then continues to go forward.
maybe....
when going in reverse it makes a tiny gap between each boxcar, then when going forward it pushes or pulls each car one at a time to build momentum rather than moving them all at once...not sure

How do you calculate the initial speed given time and displacement?The question is: The longest kick in CFL history was 83.2m. If the ball remained in the air for 4.12s, determine its initial speed.
I calculated it several times and got the same answer, 40.38m/s, but the textbook says it's 28.6m/s.

Answers

Let's first find the velocity in the x-direction which is constant.
d = vt \n v = (d)/(t) \nv = (83.2m)/(4.12s) \n v= 20.2m/s

Now, we need the velocity in the y-direction
d = v_(o)t +  (1)/(2)a t^(2) \n d - (1)/(2)at^(2) = v_(o)t\nv_(o) = (0 - (1)/(2)(-9.81)(4.12)^(2))/(4.12)\nv_(o) = 20.2m/s

Finally, we need to put the two velocities together using pythagorean theorem
v_(t)^(2) = v_(x)^(2) + v_(y)^(2)
v_(t) =  \sqrt{20.2^(2) + 20.2^(2)}
v = 28.6m/s

If the rifle is stopped by the hunter’s shoulder in a distance of 3.16 cm, what is the magnitude of the average force exerted on the shoulder by the rifle? Answer in units of N.
mass of bullet= 0.0137 kg
velocity of bullet= 546 m/s to the right
mass of rifle= 3.82 kg
recoil speed of the rifle as the bullet leaves the rifle= 1.958167539 m/s

Answers

Answer:

F = 231.77N

Explanation:

Given the following data

Distance of Hunter's shoulder (d) = 3.16cm = 0.0316m

mass of bullet (m1) = 0.0137 kg

velocity of bullet (v1) = 546 m/s

mass of rifle(m2)= 3.82 kg

Velocity of rifle (V2) = 1.958167539 m/s

Momentum = MV

Momentum is conserved

Since we are looking for the force exerted on the shoulder by the rifle

Work done = Force × distance (F×d)

The rifle possessed kinetic energy = 1/2mV²

Therefore, work done = kinetic energy

F×d = 1/2mv²

F = 0.5mv²/d

By substitution we have

F = 0.5×3.82×1.9582²/0.0316

F = 7.324/0.0316

F = 231.77N

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A girl who is watching a plane fly tells her friend that the plane isn’t moving at all. Describe a frame of reference in which the girl’s description would be true

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In the frame of reference of the passengers, flight attendants,
pilot ... anybody ON the plane ... the plane isn't moving at all.

Why evaporation are called surface phenomenon?

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It is called surface phenomenon because when the molecules at the surface obtain kinetic energy because of heat and light absorption and overcome binding forces and then evaporate out so it is called surface phenomenon....
The water formed on the surface of the water evaporation loss (evaporation), consisting of plant transpiration water loss (transpiration) is called. Soil near the plant and the resulting water loss is called by evapotranspiration.

In a compressional wave the denser the medium is at the compressions the smaller is amplitude?

Answers

Wellll, let me think about that ...

I don't think I'd agree that you can characterize the amplitude of
a wave according to the density at only one point in it.  After all ...
a tiny wave in steel would be much denser at a compression than
a huge wave in air would be.

The amplitude of any wave is described as the difference between
a peak and the resting value.  Or even better ... half of the difference
between a maximum and a minimum.

So if you're looking at a longitudinal wave, like sound, I'd say if you
want to describe its amplitude, then you have to look at the density
at two points ... either the difference between the compression and
the resting densities, or the difference between the greatest compression
and the greatest rarefaction. 

That's my opinion.  I could be wrong.