Determine the volume of this object 1) 113 mm
2) 226.1 mm
3) 339.1 mm
4) 450 mm

Answers

Answer 1

Answer:

Answer:

I think it would be 450 mm.

Answer 2

Answer: I believe 2 (226.1 mm) is the correct answer.
Step 1.

Find the circumference of the circle.
6(2)•3.14
37.68

Step 2. Multiply the circumference with the height (12mm)
37.68•12=452.16.

Final step: Divide your final answer by 2 because this object shown above is a cone.
452.16/2=226.08

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Find the rectangular coordinates of the point ( -3, 1/2 π)

Answers

Answer:

$x = -3 cos ((\pi)/(2))= 0$

$y = -3 sin ((\pi)/(2))= -3$

And then the rectangular coordinates for this case are :

$(x = 0 , y = -3)$

Step-by-step explanation:

We have the following point given $P = (-3, (\pi)/(2))$ and we want to conver from polar to rectangular coordinates and we need to use the following formulas:

$x = r cos \theta$

$y = r sin \theta$

For this case we have that:

$r = -3$

And:

$\theta = (\pi)/(2)$

Replacing we got:

$x = -3 cos ((\pi)/(2))= 0$

$y = -3 sin ((\pi)/(2))= -3$

And then the rectangular coordinates for this case are :

$(x = 0 , y = -3)$

Find 10th term of a geometric sequence whose first two terms are 2 and -8. Please answer!!

Answers

Answer:

The 10th term is -524,288

Step-by-step explanation:

The general format of a geometric sequence is:

$a_(n) = r*a_(n-1)$

In which r is the common ratio and $a_(n+1)$ is the previous term.

We can also use the following equation:

$a_(n) = a_(1)*r^(n-1)$

In which $a_(1)$ is the first term.

The common ratio of a geometric sequence is the division of the term $a_(n+1)$ by the term $a_(n)$

In this question:

$a_(1) = 2, a_(2) = -8, r = (-8)/(2) = -4$

10th term:

$a_(10) = 2*(-4)^(10-1) = -524288$

The 10th term is -524,288

A 40 N force is applied to an object with a mass of 0.1 kg on a frictionless surface. What is the acceleration of the object?

Answers

The acceleration of the object is 400 m/s²

What is the acceleration of the object?

To find the acceleration of an object when a 40 N force is applied to it with a mass of 0.1 kg on a frictionless surface, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

The formula for Newton's second law of motion is:

F = ma

where:

F is the net force,

m is the mass of the object,

a is the acceleration.

In this case, the net force is 40 N and the mass of the object is 0.1 kg.

Substituting these values into the formula, we get:

40 N = (0.1 kg) a

Solving for a, we get:

a = 400 m/s²

Therefore, the acceleration of the object is 400 m/s²

Read more about acceleration of object at: brainly.com/question/605631

#SPJ3

Answer:

400

Step-by-step explanation:

40 divided by .1

Answers

Answer:

i know its a bit late but the answer below

Step-by-step explanation:

e/f

Could u be more specific

What are the domain and range of the function represented by the set ofordered pairs?
{(-16, 0), (-8, -11), (0, 12), (12,4)}

Answers

Answer:

domain:-16,-8,0,12

range:0,-11,12,14

Assume that a lost treasure will be in a certain area of the ocean with probability 0.4, and that a search of that area will find the treasure with probability 0.9 if it is there. What is the conditional probability of the treasure being in the area if the area is searched and no treasure is found?

Answers

Answer:

the probability of the treasure being in the area given that no treasure is found is 0.0625 (6.25%)

Step-by-step explanation:

denoting the event N= no treasure is found , then

P(N) = probability that the lost treasure is in the area* probability that the lost treasure is not found in the treasure's area + probability that the lost treasure is not in the area* probability that the lost treasure is not found in other areas = 0.4*0.1 + 0.6*1 = 0.64

P(N) = 0.64

then we can get the conditional probability using the theorem of Bayes . Denoting the event A= the treasure being in the area

P(A/N) = P(A∩N)/P(N) = 0.4*0.1/0.64 = 0.0625 (6.25%)

where

P(A∩N) = probability of the treasure being in the area and no treasure is found

P(A/N) = probability of the treasure being in the area given that no treasure is found

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