1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride ? atoms of boron. 2. How many MOLES of fluorine are present in 5.35*1022 molecules of boron trifluoride ? moles of fluorine.​

Answers

Answer 1
Answer:

Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in  of boron trifluoride? moles of fluorine.​

Explanation:

The molecular formula of boron trifluoride is BF_3.

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- 6.023x10^2^3 atoms.

Then, 2.20 moles of boron has

-=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\n=13.25x10^2^3 atoms

2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\n=0.0888mol

One mole of boron trifluoride has three moles of fluorine atoms.

Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

=0.266mol of fluorine atoms.


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Answers

Answer:

OBSERVING AND QUESTIONING

Explanation:

when you use the scienfic method the first thing you have to do is question you theory and coming up with a hypothesis which is what you expect to happen

Answer:

make an observation

Explanation:

Unrestricted populations of organisms experience _____.a. exponential growth
b. linear growth
c. fertility
d. biotic growth
User: As a population reaches its carrying capacity, there is an increase in competition for
a. food.
b. shelter.
c. mates.
d. All of the above

Answers

Answer:

1. A

2. D

Explanation:

1. If a population is left unrestricted, meaning it is not limited to anything, then the population will continue to increase exponentially due to there being no limits.

2. If a population is limited, and it has reached its carrying capacity, then the essential needs of life are being competed for. Things like food, shelter, and mates are now a limited resource, and hence the option would be "all of the above".

Unrestricted populations of organisms experience Exponential growth. 

As a population reaches is carrying capacity there is an increase in competition for All of the above.
 Hope I helped. 

Nitrogen gas is being held in a 14.3 L tank at a temperature of 62°C. What will the volume be when the temperature drops to 24°C?

Answers

I think the volume should be still 14.3L. In this question, the gas is being held in a tank. The tank has a constant volume. The gas in the tank has the property to fill the space. So when the temperature changes, the pressure changes too. But the volume doesn't change.

What are two ways in which minerals can form from a solution?

Answers

They could react to form an insoluble precipitate, or they could come out of solution as the solvent evaporates.
heat i think is one e wrongbut i could b

Calculate the molar mass
FeCl3
Fe2(SO4)3
PbO
PbO2
Pb3O4

Answers

To find molar mass: look for each element on the table and find their atomic masses. Then add each atomic mass to find the molar mass. If there is a subscript then that means that there is 3 of that number. For atomic mass round to the nearest hundredths
FeCl3= 162.2
Fe2(SO4)3= 354.88
PbO=223.2
PbO2 = 239.2
Pb3O4=685.6

Which of the following cn be observed when 20,0 of 1.0 M NaOH (aq), 10.0 mL of 1.0 M HCL(aq), and a few drops of phenolphthalein are combined and react?

Answers

Answer:

The final solution will be clear and colorless.

Explanation:

The balanced reaction equation is:

NaOH + HCl ⇒ H₂O + NaCl

The amount of NaOH that is added is calculated as follows:

(20.0mL)(1.0mol/L) = 20 mmol NaOH

Similarly, the amount of HCl that is added is as follows:

(10.0mL)(1.0mol/L) = 10 mmol HCl

Since HCl and NaOH react in 1:1 proportions, the HCl is the limiting reaction. 10 mmmol of HCl will neutralize 10 mmol of NaOH, leaving 10 mmol of NaOH. The volume of the mixed solution is 30.0 mL, so the concentration of NaOH in the final solution is:

(10 mmol)/(30.0mL) = 0.3333 M NaOH

The pOH of the final solution is:

pOH = -log([OH⁻) = -log(0.3333) = 0.477

The pOH is related to the pH as follows:

pH = 14 - pOH = 14 - 0.477 = 13.5

At a pH of 13.5, phenolphthalein is colorless. The final solution will be observed as clear and colorless.