1. 5 Burgers and 3 orders of fries cost $34. 4 Burgers and 4 orders of fries cost $32. How much does each burger and each order of fries cost?2. A pile of 44 coins is made up of pennies, nickels, and dimes. If the pile is worth $3.07 and there are twice as many nickels as pennies, how many of each coin does the pile contain?

Answers

Answer 1
Answer:

Answer:

1.

a burger costs $5

an order of fries costs $3

2.

7 pennies

14 nickels

23 dimes

Step-by-step explanation:

x = price of a burger

y = price of a order of fries

5x + 3y = 34

4x + 4y = 32

=>

x + y = 8

x = 8-y

5×(8-y) + 3y = 34

40 - 5y + 3y = 34

-2y = -6

y = $3

x = 8 - 3 = $5

x = number of pennies

y = number of nickels

z = number of dimes

0.01×x + 0.05×y + 0.1×z = 3.07

y = 2x

x + y + z = 44

x + 2x + z = 44

3x + z = 44

z = 44 - 3x

0.01×x + 0.05×2x + 0.1×z = 3.07

0.11×x + 0.1×z = 3.07

0.11×x + 0.1×(44-3x) = 3.07

11x + 10×(44-3x) = 307

11x + 440 - 30x = 307

-19x = -133

x = 7

y = 2×7 = 14

z = 44 - 3×7 = 44 - 21 = 23


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Factor 6(2p q)^2 -5(2p q) - 25

Answers

treat the 2p+q as x

6x2-5x-25
trial and error
(2x-5)(3x+5)
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(2(2p+q)-5)(3(2p+q)+5)
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Jonah weighs his puppy each week. The puppy has a mass of 10 kilograms the first time Jonah weighs it. The mass of the puppy increases0.5 kilograms each week until it is fully grown. For each of the answer options, let y represent mass in kilograms, and x represent time in
weeks.
Which equation shows a smaller rate of change than Jonah's puppy?
O A. y = 0.4x + 10
OB. y=0.5x + 9
OC. y = 9x +0.5
D. y = 10x +0.4

Answers

Answer:

y=10x+0.4

Step-by-step explanation:

I did the test too.

Answer:

y=10x+0.4

Step-by-step explanation:

Firm A and Firm B have debt-total assets ratios of 65 percent and 45 percent, respectively, and returns on total assets of 5% and 7%, respectively. Which firm has a greater return on equity

Answers

Answer:

Firm A

Step-by-step explanation:

D = Debt

A= Asset

E = Equity

ROA = Return on assets

ROE = Return on equity

For Firm A:

(D)/(A)=0.65\n(E)/(A)=1-0.65=0.35\nROA = 0.05\nROE=(ROE)/((E)/(A))=(0.05)/(0.35) \nROE=0.1429=14.29\%

For Firm B:

(D)/(A)=0.45\n(E)/(A)=1-0.45=0.55\nROA = 0.07\nROE=(ROE)/((E)/(A))=(0.07)/(0.55) \nROE=0.1273=12.73\%

Therefore, Firm A has a greater return on equity.

A small hard drive measured 0.7553 centimeters across round to the nearest tenth

Answers

Answer:

0.8

Step-by-step explanation:

7 is in the tenth place since there is a 5 in the hundreds we round up to 8.

hope this helped =3

Which expression is equal to “7 times the sum of a number and 4"?

Answers

Answer: 7 (x+4)

Step-by-step explanation: Since the expression asks for 7 times the sum of a number and 4, you would put x + 4 in parentheses since multiplying 7 comes afterwards.

Nondigestible carbohydrates can be used in diet foods, but they may have Problem 7.2 effects on colonic hydrogen production in humans. We want to test to see if inulin, fructooligosaccharide, and lactulose are equivalent in their hydrogen production. Preliminary data suggest that the treatment means could be about 45, 32, and 60 respectively, with the error variance conservatively estimated at 35. How many subjects do we need to have power .95 for this situation when testing at the ????1 = .01 level?

Answers

Answer:

null hypothesis = µ1=µ2=µ3; µ1= popuation mean of inulin µ2 = population mean of fructicoligosaccharide =µ3=population mean of lactulose

alternative hypothesis =µ1≠µ2 ≠µ3

t1= µ-45/s1 / N-1

at the significance level 0.01

t at ᵅ/2 =0.005 and degree of freedom= 35-1=34 is 2.25

t1 = µ-32/s1/N-1

2.25= µ-45/s1/34

= s1/34= µ-45/2.25

=s1 =(µ-45/2.25)*34

t2= µ-32/s2/34

2.25 =µ-32/s2/34

s2/34= µ-32/2.25

s2=µ-32/2.25*34

T= 45-32/s1/sqrt34+s2/sqrt34

t at 0.005 and no of grees of freedom 68 =2.37

2.37=45-32/

or s1/sqrt34+s2/sqrt34 = 13/2.37

s1+s2 = 13/2.37 *5.83

s1+s2= 31.98 or 32

(µ1-45/2.25)*34+µ2-32/2.25*34=32

or µ1+µ2 = 2525

µ1=2525-µ2

µ1 and µ2 are not equal

thus null hypothesis is rejected

conclusion all the three components are not in equal amount in hydrogen production

Explanation : in this experiment we have to prove whether the means of insulin,fructicoligosaccharide and lactulose are equal. so even if we prove that two of them are not equal null hypothesis will be rejected. we use student-t test because we have to compare the means of two population.