CHEMISTRY HIGH SCHOOL

Which type of bond forms between atoms of iron (Fe)?A. ionic
B. Metallic
C. Polar covalent
D. Nonpolar covalent

Answers

Answer 1

Answer:

Answer:

Metallic

Explanation:

Iron is a metal

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Which property is true for metals

Answers

The true property of metals is metals have low ionization energies.

(Option 3).

What are the characteristics of metals?

Metals are characterized by their ability to conduct electricity and heat, malleability, and ductility.

These properties are primarily due to the behavior of their electrons. In a metal, the valence electrons are not tightly held by the individual atoms but rather form a "sea" of delocalized electrons that can move freely throughout the metallic lattice.

One of the key factors that contribute to the delocalization of electrons in metals is their low ionization energies.

Ionization energy is the amount of energy required to remove an electron from an atom, specifically from the outermost shell.

Learn more about Ionization energy here: brainly.com/question/30831422

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The complete question is below:

Which property is true for metals?

1. localized electrons

2. high electronegativity

3. low ionization energies

4. tightly held valence electrons

metals are solid, shiny, and good conductors of electricity and heat
hope this helps :)

Within each energy level there are different sublevels that are created. Those electrons that have the lowestamount of energy follow paths that are spherical in shape. Which sublevel is associated with this shape?
A)
d.
B)
f
C)
р
D)
S

Answers

It’s option D cause we know that S orbital is spherical

In the compound MgCl2, the subscript 2 indicates thata. there are two magnesium ions for each ion of chlorine
b. the chloride ion is twice the size of the magnesium ion.
c. magnesium and chlorine form a double covalent bond.
d. there are two chloride ions for each magnesium ion.

Answers

The correct answer is answer choice D, there are two chloride ions for each magnesium ions. Subscripts always indicate the number of atoms, or ions, present in the molecule. The 2 refers to the element directly to its left, so answer choice A is reversed; there are 2 chloride ions for each magnesium ion, not the other way around. Answer choice B and C are incorrect because the subscript refers to the number of atoms, not the size of the atoms or the type of bond.

Answer:

The chloride ion accepted two electrons from the magnesium ion.

Explanation:

in a school’s laboratory, students require 50.0 mL of 2.50 M H2SO4 for an experiment, but the only available stock solution of the acid has a concentration of 18.0 M. What volume of the stock solution would they use to make the required solution? Use mc018-1.jpg.

Answers

Ans: Volume of stock H2SO4 required = 6.94 ml

Given:

Concentration of stock H2SO4 solution M1 = 18.0 M

Concentration of the final H2SO4 solution needed M2 = 2.50 M

Final volume of H2SO4 needed, V2 = 50.0 ml

To determine:

Volume of stock needed, V1

Explanation:

Use the dilution relation:

$M1V1 = M2V2\n\nV1 = (M2V2)/(M1) \n\nV1 = (2.50 M * 50.0 ml)/(18.0 M) = 6.94 ml$

Hello!

In a school’s laboratory, students require 50.0 mL of 2.50 M H2SO4 for an experiment, but the only available stock solution of the acid has a concentration of 18.0 M. What volume of the stock solution would they use to make the required solution?

We have the following data:

M1 (initial molarity) = 2.50 M (or mol/L)

V1 (initial volume) = 50.0 mL → 0.05 L

M2 (final molarity) = 18.0 M (or mol/L)

V2 (final volume) = ? (in mL)

Let's use the formula of dilution and molarity, so we have:

$M_(1) * V_(1) = M_(2) * V_(2)$

$2.50 * 0.05 = 18.0 * V_(2)$

$0.125 = 18.0\:V_2$

$18.0\:V_2 = 0.125$

$V_2 = (0.125)/(18.0)$

$V_2 \approx 0.00694\:L \to \boxed{\boxed{V_2 \approx 6.94\:mL}}\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:

The volume is approximately 6.94 mL

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Calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH–] is 1 x 10–11 mol/L. Is this solution acidic, basic, or neutral? Show all work.

Answers

If we have $[H+][OH-]= Kw = 1.0 x 10^-14$
Then $[H+]= Kw/ [OH-]= 1.0x 10^-14$ $/ 1 x 10^-11 =1 x 10^-3 mol/L$
And here is the solution - as you can see it is an acidic one :
$pH = - log [H+]= - log 1 x 10^-3 = 3 \ \textless \ 7$

I am pretty sure this answer will help you! Regards.

What is released when the chemical bond is broken between the second and third phosphates of an atp?

Answers

The question was "What is realesed when the chemical bond is broken between the second and third phosphates of an atp?" The answer is hydrolysis.

Final answer:

The breaking of the chemical bond between the second and third phosphates of ATP (Adenosine triphosphate) releases significant energy, transforming ATP into adenosine diphosphate (ADP) and an inorganic phosphate group. The energy released powers various biological processes and reactions within cells. This cycle of breaking and reforming ATP, often referred to as hydrolysis, is crucial to cellular function.

Explanation:

Adenosine triphosphate (ATP) is a high-energy molecule that powers cellular processes. When the chemical bond between the second and third (or beta and gamma) phosphates of ATP is broken, it releases significant energy. This reaction, known as hydrolysis, transforms ATP into adenosine diphosphate (ADP) and an inorganic phosphate group (P;), both of which have lower free energy than the reactants. Here is the specific reaction: ATP + H₂O → ADP + P¡ + free energy.

The breaking of phosphates' strong bonds (phosphoanhydride bonds) releases enough energy to power various cellular reactions and processes. These bonds are considered 'high-energy' due to the amount of energy they release upon breaking.

This continuous cycle of ATP breaking down into ADP and phosphate, followed by their recombination, effectively powers the life processes within cells.