the editor of the school newspaper must reduce the size of a graph to fit in one column. The original graph is 2 inches by 2 inches, and the scale factor from the original to the reduced graph is 8:3. Find the dimensions of the graph as it will appear in one column in the newspaper

Answers

Answer 1

Answer: $(2)/(8) : (2)/(3) \n \n (1)/(4) : (2)/(3)$

$(1)/(4)$ inches by $(2)/(3)$ inches

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Louis wants to carpet the rectangular floor of his basement.The basement has a area 432 square feet,The width of the basement is 1/3 its length.What's the length of Louis's basement.

Please answer this question and thank you for your help

Answers

He would give about 100 balls out to every game.

Choose the correct solution in roster form.S is the set of prime numbers that are less than 15.

A- { 2, 3, 5, 7, 11, 13 }
B- { 2, 3, 5, 7, 9, 11, 13 }
C- { 1, 3, 5, 7, 9, 11, 13 }
D- { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 }

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Write the solution to the inquality in set-builder notation.

9t - 4 >32

A- { t | t > 4 }
B- { t | t > 6 }
C- { t | t > 28 }
D- { t | t > 36 }

Answers

Mathematically speaking, roster form of a set is a list of elements that are in the set.

Basically, to represent a set in roster form, we simply list the elements of the set, separated by commas, within braces.

as per the question, consider the set, S, described verbally:

S = {all prime numbers less than 15}

To write this in roster form, we would first identify all the elements in the set. Let's see. . . the integers that are strictly greater than 0 and less than or equal to 4 would be the integers that are between 0 and 4, not including 0, but including 4, so 1, 2, 3, and 4.

Now we just write these integers, separated by commas, within braces.

S = {2, 3, 5, 7, 11, 13}. So answer is option A

Set notation is a representation of a set of the form {element | properties of that element}.

To represent the inequality in set builder notation, we will first have to solve for the inequality as follows:

9t - 4 >32

Step 1: Add 4 on LHS(Left hand side) and RHS(right hand side) of the inequality.

9t > 36

Step 2: Divide LHS and RHS by 9

t > 4

This means that the inequality holds for all values of t greater than 4 i.e.

{ t | t > 4 }. so answer is option A

Taylor earned $48 for 6 hours of babysitting and $68 for 8.5 hours of babysitting. How long would she have to babysit to earn $32

Answers

4 hours))

68/8.5 = 8
48/6 = 8
That means 32/8 = 4

There was a plate of cookies on the table. Amanda was hungry because she hadn't had breakfast, so sheate half the cookies. Then Beth came along and noticed the cookies. She thought they looked good, so she
ate a third of what was left on the
plate. Christine came by and decided to take a fourth of the remaining cookies with
her to her next class. Then Daniel came dashing up and took a cookie to munch on.
When Eva looked at the plate, she saw that there were two cookies left. She wondered how many cookies
were on the plate to begin with?

Answers

Answer:

10 2/3

Step-by-step explanation:

So in order to figure this out you have to work backwards. First, Daniel came and took a cookie. So when he took 1 there were 3 cookies available. Next Christine took one fourth of the cookies, meaning that the 3 available cookies are the remaining 3/4's. When she got there she took 1. Then Beth came and took 1/3. For it to be 3/3 there has to be 1 and 1/3 more cookies. Now there are 5 and 1/3 cookies. Amanda came and ate half of the cookies meaning that the amount of cookies we have now is the other half that she didnt eat. 5 and 1/3 plus 5 and 1/3 is 10 and 2/3. I hope this is correct.

How many different integers can have the same absolute

Answers

All positive integers...

ramona had 8 3/8 in. of ribbon. she used 2 1/2 in. for an art project. how many does she have left? find the difference in simplest form.

Answers

the answer is 5 7/8
b/c 2 1/2 = 2 4/8
so then convert 8 3/8 as an improper fraction which is 67/8
and do the same w/ 2 4/8 which is 20/8
the do: 67/8 - 20/8 = 47/8
simplify 47/8 = 5 7/8.
Your answer is 5 7/8 inches of ribbon left.

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