Two species have homologous structures. What do these homologous structures show about the evolutionary relationship between the two species?

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Answer 1
Answer: Two species have homologous structures. What do these homologous structures show about the evolutionary relationship between the two species? (3 points) The homologous structures show that the two species followed up the evolutionarypath up to the structure. They may have branched off right after that trait.
Answer 2
Answer:

Final answer:

Homologous structures in two species indicate that they share a common ancestor. These structures, although they may serve different functions in adult organisms, have a similar form and the same embryonic origin. They provide key evidence for evolution and development of various species from common ancestors.

Explanation:

The presence of homologous structures in two different species often demonstrates an evolutionary relationship, indicating they share common ancestry. Homologous structures are those that have a similar form or function and share a similar embryonic origin, although they may appear different and perform different functions in the adult organisms. An example of this could be the bone structure in a human arm, cat leg, whale flipper, and bat wing which, despite serving different purposes, all have a similar arrangement of bones.

The presence of such structures suggests that these species have evolved from a common ancestor that had this structure. Over time, as the species evolved and adapted to their specific environments or lifestyles, these structures may have developed different functions. Therefore, homologous structures are key evidence for the theory of evolution and help in developing phylogenetic relationships. They help us understand how different species have evolved and diversified from common ancestral forms.

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A student studies art and learned that he has several layers including inner and outer cores the student will make a model of the inner and outer cores of earth which model would be most like earths actual inner and outer cores A: A pool of liquid inside a solid metal ball. B: Metal ball with a slightly smaller solid metal ball inside it. C: A solid metal ball in the middle of a pool of liquid. D: A pool of one type of liquid in the middle of a pool of another type of liquid

Answers

Answer:

C: A solid metal ball in the middle of a pool of liquid.

Explanation:

Since the student is studying the earth, the core area is made up of a solid metal ball in the middle of a pool of a liquid.

  • The core is the inner most part of the earth.
  • It exists in the middle of the earth.
  • The core is divide into two layers; inner core and outer core.
  • The inner core is a solid ball of metal.
  • The outer core is a liquid metal under high temperature and pressure.

Which factors are included in a forest community? Select ALL that apply.• every squirrel in the forest

• all forests populations

• plants fungi and microbes in the forest

• rushing stream

• rock on which turtles and
frogs sit

please i am really confused and my test is timed so please can someone answer fast :(

Answers

Answer:

every squirrel in the forest

all forests populations

plants, fungi and microbes in the forest

Explanation:

In ecology, a community refers to a population of different species of organisms occupying a particular area at a particular time. In other words, community is a group of living organisms of different species interacting with one another in a given habitat.

According to the question, a forest community will contain all plants, animals and microbes in the forest involved in a series of interaction with one another. This includes every squirrel in the forest, all population of organisms in the forest and all plants, fungi and microbes in the forest.

N.B: If the abiotic components are included to the living ones, they will together make up an ECOSYSTEM.

50 points and brainliest'!!!!!!!!!!!!!!!!!!!!!!!!Reliability and probability in forensic tests are important. When you look at matching a paint chip to a specific car, you are working to increase the probability that the right car matching your paint chip evidence will be found. Reliability means you have practiced and applied the correct procedures and processes for all your evidence testing, and you know you can trust the results. Some forensic tests are more reliable than others, and the best type of test or tests to use will usually depend on the kind of evidence that is present. If all types of evidence were present at a crime scene, which type of test would you choose based on its reliability and probability of accuracy? Identify which test you would choose and provide a detailed argument as to why you feel it has a high level of reliability in comparison to other types of evidence. Your answer should be at least two paragraphs in length and should include solid arguments for your choice. There is no wrong choice, just be sure to provide a convincing argument.

Answers

Answer:

Explanation:

everything must match up inorder to find anyone accountiable

Final answer:

For forensic science, the Gas Chromatography-Mass Spectrometry (GC-MS) is highly reliable and accurate for identifying specific materials. In a case involving a paint chip, it accurately identifies the various elements and compounds in the paint and discriminates between different paint brands and types.

Explanation:

In the entire arsenal of forensic tests, one test stands out for its high reliability and accuracy in identifying specific materials: the Gas Chromatography-Mass Spectrometry (GC-MS). It has two main components: Gas Chromatograph, which separates the different components in a substance, and Mass Spectrometer, which identifies each of these components.

The GC-MS test is particularly effective when analyzing biological materials like blood, saliva, and even paint fragments. When dealing with a case involving a paint chip, for instance, GC-MS can not only identify the various elements and compounds in the paint but can discriminate between different paint brands and types, thereby increasing the probability of accurately matching the paint chip to a specific car.

Learn more about Gas Chromatography-Mass Spectrometry (GC-MS) here:

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In peas, the round allele (r) is dominant to the wrinkled allele (r), and tall (t) is dominant to short (t). a pure-breeding round, tall strain is crossed to a wrinkled, short strain, and the f1 plants are crossed back to the wrinkled, short strain. what proportion of the offspring will be wrinkled and tall

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The round allele is dominant (R)
The wrinkled allele is recessive (r)
The tall allele is dominant (T)
The short allele is recessive (t)

The genotype of the f1 generation would be RrTt.So if you cross that back to the wrinkled short then the Punnet of that cross would look like this:

RrTt x rrtt

      RT           Rt           rT          rt
rt   RrTt       Rrtt          rrTt        rrtt
rt   RrTt       Rrtt          rrTt        rrtt
rt   RrTt       Rrtt          rrTt        rrtt
rt   RrTt       Rrtt          rrTt        rrtt

The genotype for a wrinkled tall should be rrTt at least in this case because neither of the parents are pure-breed. 

The proportion would then be then 4/16 or 1/4. There is a 25% chance of  yielding a wrinkled tall. 

Final answer:

When crossing a heterozygous round, tall F1 pea plant with a homozygous wrinkled, short pea plant, the probability of the offspring being wrinkled and tall is 1/4.

Explanation:

In pea plants, we have two traits where round seed shape (R) is dominant to wrinkled seed shape (r), and tall height (T) is dominant to short height (t). When a homozygous round, tall plant (RRTT) is crossed with a homozygous wrinkled, short plant (rrtt), the resulting F1 generation will all have the genotype RrTt (heterozygous for both traits). If these F1 plants are then crossed back to the wrinkled, short strain (rrtt), we need to look at each trait separately to determine the phenotype ratios.

For the seed shape, the F1 plants (Rr) crossed with the wrinkled, short (rr) can produce offspring with either Rr or rr genotype. Therefore, the probability of having a wrinkled (rr) offspring is 1/2. For height, the F1 plants (Tt) crossed with the wrinkled, short (tt) can also produce offspring with either Tt or tt genotype. The probability of having a tall (Tt) offspring is 1/2 as well. To find the proportion of offspring that are wrinkled and tall, we multiply the probabilities of the independent events: 1/2 (chance of being wrinkled) × 1/2 (chance of being tall) which equals 1/4.

Therefore, the proportion of offspring that will be wrinkled and tall from this cross is 1/4.

Which of the following represents a genotype that is homozygous recessive

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There are many, and since you didn't specify the choices, some examples include "ff" or "dd" or just two lowercase letters.

Explanation:

The difference between the cellular make-up of a living organism and an aluminum can is the

Answers

the ability to use energy