CHEMISTRY HIGH SCHOOL

71. The density of osmium (the densest metal) is 22.57 g/cm². If a1.00-kg rectangular block of osmium has two dimensions of
4.00 cm x 4.00 cm, calculate the third dimension of the block.

Answers

Answer 1
Answer:

Answer:

y = 2.77 cm

Answer: The third dimension is 2.77 cm
Answer 2
Answer:

Final answer:

The question deals with density in physics, specifically regarding the densest metal, osmium. The dimensions of an osmium block are partially given, and the task is to find the third dimension. However, without the mass of the block, it is impossible to give a complete solution.

Explanation:

The subject of the question involves understanding the concept of density, which is the mass of an object divided by its volume. The density of osmium is given as 22.57 g/cm³. The student is also given the dimensions of the osmium block, which forms a rectangular prism with known length and width (4.00 cm x 4.00 cm), but unknown height. D = m/v or v = m/D can be used to find the third dimension of the block (height).

However, to use this formula to get a complete solution, the mass of the block must be known, which is not provided in the question. Without this crucial information, we can't solve this problem correctly.

Learn more about Density here:

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Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).

Answers

Hello!

Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).

We have the following data:

m (mass) = ? 

n (number of moles) = 5.20 moles

MM (Molar mass of C6H12) ≈ 84.2 g/mol

Now, let's find the mass, knowing that:

n = (m)/(MM)

5.20\:\:\diagup\!\!\!\!\!\!\!mol = (m)/(84.2\:g/\diagup\!\!\!\!\!\!\!mol)

m = 5.20*84.2

\boxed{\boxed{m = 437.84\:g}}\end{array}}\qquad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)
Molar mass C₆H₁₂ = 84.2 g/mol

1 mole ---------- 84.2 g
5.20 moles ---- ?

Mass C₆H₁₂ = 5.20 * 84.2 / 1

Mass = 437.84 /1

= 437.84 g

hope this helps!

Explain how methane (ch4) and ethane (c2h6) demonstrate the law of definite composition and the law of multiple proportions

Answers

Methane and ethane demonstrate the law of definite composition and the law of multiple proportions as these both compounds have the exact atoms but in different ratios.  

As for methane, it can be seen that every methane molecule contains 4 hydrogen atoms and 1 carbon atom. Where masses of carbon and hydrogen are in ratio - 12 g C / 4 g H -- reduce to 3g C/ 1 g H .

Ethane contains 2 carbon atoms and 6 hydrogen atom and their mass ratio will be  - 24 g C / 6 g H -- reduce to 4 g C/ 1 g H .

So both ethane and methane demonstrate the law of definite composition and the law of multiple proportions.

Law of definite composition: The elements which are present in the compound is combined in the same proportion by mass.

Law of multiple proportion: When two or more compounds are formed by the combination of two elements then the mass ratio of one element is combined with the fixed mass of the other element.

In case of methane, it consist of one carbon atoms and four hydrogen atoms implies that has definite composition. In terms of mass, in methane, carbon and hydrogen atoms are combined in a definite ratio i.e. 12 g C/ 4 g H. Thus, methane has definite composition.  

Now, carbon and hydrogen combines to give a class i.e. hydrocarbon. In this case, for every constant mass of carbon the ratio of hydrogen will always reduce to 4/3 ratio for the formation of ethane (hydrocarbon). Thus, law of multiple proportion followed.

Similarly, in case of ethane, this compound also consist of exact atoms but in different ratios.

In case of ethane, it consist of two carbon atoms and six hydrogen atoms implies that has definite composition. In terms of mass, in ethane, carbon and hydrogen atoms are combined in a definite ratio i.e. 24 g C/ 6 g H. Thus, methane has definite composition.  

Now, carbon and hydrogen combines to give a class i.e. hydrocarbon. In this case, for every constant mass of carbon the ratio of hydrogen will always reduce to a specific ratio for the formation of methane (hydrocarbon). Thus, law of multiple proportion followed.

Which statement describes a chemical propertyof sodium?
(1) Sodium has a melting point of 371 K.
(2) Sodium has a molar mass of 23 grams.
(3) Sodium can conduct electricity in the liquid
phase.
(4) Sodium can combine with chlorine to produce
a salt.

Answers

Answer;

(4) Sodium can combine with chlorine to producea salt.

Explanation;

Sodium is an alkali metal (group 1 ) in the periodic table. It is a soft metal, reactive and with a low melting point. It has an atomic weight of 23 grams.

Sodium is a good conductor of electricity due to the presence of delocalized electrons in its metallic structure. It reacts vigorously with water to produce sodium hydroxide and hydrogen.

-When exposed to air, metallic sodium recently cut looses its silvery appearance and acquires an opaque grey color due to the formation of a sodium oxide coating.
(4) Sodium can combine with chlorine to produce a salt is the correct answer. The other three are just physical properties~

A potassium ion (K+) would most likely bond with?

Answers

It's most likely to bond with chlorine.

Which statement best explains water’s ability to dissolve covalent compounds?a. Water can dissolve polar covalent compounds through dipole-dipole interactions.
b. Water can dissolve nonpolar covalent compounds through hydrogen-bonding interactions.
c. Water can dissolve polar covalent compounds through ion-dipole interactions.
d. Water can dissolve nonpolar covalent compounds through dipole-dipole interactions.

Answers

The correct answer for the question that is being presented above is this one: "c. Water can dissolve polar covalent compounds through ion-dipole interactions." The statement that best explains water’s ability to dissolve covalent compounds is that Water can dissolve polar covalent compounds through ion-dipole interactions.

Answer:

a. Water can dissolve polar covalent compounds through dipole-dipole interactions.

Explanation:

It's the correct answer on Edge 2021. If anyone asks, you didn't hear it from me ;)

Name the following chemical compound. NaBra. sodium bromite
b. niobium bromite
c. sodium bromide
d. niobium bromide

Answers

The answer is C Sodium Bromide.

Listed in Periodic Table Na is Sodium atomic number 11 and Bromine atomic number 35.

Answer:

C. Sodium Bromide
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