Eduardo is building a sandbox that has an area of 84 square feet. what are the possible whole number measurements for the length and width of the sandbox?

Answers

Answer 1

Answer: 1x84, 2x42, 3x28, 4x21, 6x14, and 7x12.

Related Questions

Solve using substitution or elimination. Remember, you must check your work.10x -15y = 104x + 6y = 0
Please help! 50 points and i'll give brainliest!
What is the area of the triangle? 126 km2 252 km2 222 km2 444 km2
Helppppp asappppp!!!!
Ross found 5 ladybugs each is 0.8 centimeter long If he lays the ladybugs in a row what is the total length in milimeters

Phillips saves $8 each month. how many months will it take him to save at least $60

Answers

1st month = $8
2nd Month = $16
3rd Month = $24
4th month = $32
5th Month = $40
6th Month = $48
7th Month = $56
8th Month - $64

After 7 months he only has $56 bucks, not enough to hit $60, but after 8 months he finally has at least $60 (in fact, he has $64)

Answer:8 months

Step-by-step explanation:8x1= 8 8x2=16 8x3= 24 8x4= 32 8x5= 40 8x6= 48 8x7= 56 and 8x8= 64 Remember, it said “ at least”

A jogger weighing 800 N is running along at a constant velocity of 6 m/s. What is the kinetic energy ofthe jogger?

Answers

Step-by-step explanation:

KE = ½ mv²

KE = ½ (800 N / 10 m/s²) (6 m/s)²

KE = 1440 J

GrossIncome
Standard
Deduction
Number of Exemptions at
$3650 Each
Delaney $77,568
$8350
Jamie
$71,234
$5700
Oliver
$74,872
$8350
Thomas $77,623
$5700
Assuming that each worker used the standard deduction and that none of the
workers had any additional adjustments, which worker had the lowest taxable
income last year?
O
A. Jamie
O
B. Oliver
O
C. Delaney
O
D. Thomas

Answers

If each worker used the standard deduction and no worker had any additional adjustments, the worker with the lowest taxable income last year was A. Jamie.

What is taxable income?

The taxable income is the difference between a worker's gross income and the total deductions (standard or itemized).

Data and Calculations:

Gross Income Standard Number of Taxable

Deduction Exemptions at Income

$3,650 Each

Delaney $77,568 $8,350 $69,218 ($77,568 - $8,350)

Jamie $71,234 $5,700 $65,534 ($71,234 - $5,700)

Oliver $74,872 $8,350 $66,522 ($74,872 - $8,350)

Thomas $77,623 $5,700 $71,923 ($77,623 - $5,700)

Thus, if each worker used the standard deduction and no worker had any additional adjustments, the worker with the lowest taxable income last year was A. Jamie.

Learn more about taxable income at brainly.com/question/2743145

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Answer: Thomas

Step-by-step explanation:

What is the common difference in the arithmetic sequence 10, 8, 6, 4, ...?

20pts

Answers

Answer:common difference is -2

Step-by-step explanation:

Answer:common difference is -2

Step-by-step explanation:

The sequence is arithmetic if the difference between consecutive terms is constant.

A laboratory technician can clean 34 pipettes every hour with an automatic washer. How many can he clean in 12 minutes? (Hint: Both time periods must be in the same unit of measurement)

Answers

Answer: 6.8

Step-by-step explanation:

34 in 60 minutes

In 12 minutes = ( 12/60) * 34

Answer:

Step-by-step explanation:

you can do a ratio where you have 34 over 60 then cross multiply that ratio with x over 12 and 60x=408 and it equals 6.8 but I am assuming you have to round up.

Solve irrational equation pls

Answers

$\hbox{Domain:}\nx^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\nx^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\nx(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\n(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\nx\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\nx\in(-\infty,-2\rangle\cup\langle3,\infty)$

$√(x^2+x-2)+√(x^2-4x+3)=√(x^2-1)\nx^2-1=x^2+x-2+2√((x^2+x-2)(x^2-4x+3))+x^2-4x+3\n2√((x^2+x-2)(x^2-4x+3))=-x^2+3x-2\n√((x^2+x-2)(x^2-4x+3))=(-x^2+3x-2)/(2)\n(x^2+x-2)(x^2-4x+3)=\left((-x^2+3x-2)/(2)\right)^2\n(x+2)(x-1)(x-3)(x-1)=\left((-x^2+x+2x-2)/(2)\right)^2\n(x+2)(x-3)(x-1)^2=\left((-x(x-1)+2(x-1))/(2)\right)^2\n(x+2)(x-3)(x-1)^2=\left((-(x-2)(x-1))/(2)\right)^2\n(x+2)(x-3)(x-1)^2=((x-2)^2(x-1)^2)/(4)\n4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\n$
$4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\n(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\n(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\n(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\n(x-1)^2(3x^2-28)=0\nx-1=0 \vee 3x^2-28=0\nx=1 \vee 3x^2=28\nx=1 \vee x^2=(28)/(3)\nx=1 \vee x=\sqrt{(28)/(3)} \vee x=-\sqrt{(28)/(3)}\n$

There's one more condition I forgot about
$-(x-2)(x-1)\geq0\nx\in\langle1,2\rangle\n$

Finally
$x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{(28)/(3)}, -\sqrt{(28)/(3)}\}\n\boxed{\boxed{x=1}}$

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