If a substance has a half life of 850 years, and there are 35 milligrams present now, how long will it take for the substance to be reduced to 10 miligrams calculus

Answers

Answer 1
Answer: This is a problem involving differential equation. The rate of decaying substance is directly proportional to the amount of substance.
dP/dt = kA
where k = proportionality constant, A = amount of subtance.

Integrating that equation yields,
A = ce^(kt)
where c = constant of integration.
The constant of integration is represented mostly as an initial amount of substance.

We have given two initial condition:
(1) t = 0, A = 35 milligrams (present)
(2) t = 850 years, A = 35/2 milligrams (half-life)

We are going to solve for c:
35 = ce^0
c = 35

Next, solving for k:
35/2 = 35e^(k*850)
1/2 = e^(k*850)
Multiplying natural logarithm on both sides to bring down k:
ln (1/2) = k*850
k = ln (1/2) / 850
k = -0.00081547

Finally, the time when the amount of substance has 10 milligrams remaining is:
10 = 35e^(-0.00081547*t)
10/35 = e^(-0.00081547*t)
Multiplying natural logarithm on both sides to bring down t:
ln (2/7) = -0.00081547*t
t = ln (2/7) / -0.00081547
t = 1536.25 years (ANSWER)

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A. -49/4
B. -7/2
C. 49/4
D. 7/2

Answers

The letter a ..... ......

You have invested 50,000 dollars to start a donut shop. Your cost for raw materials is 0. 65 dollars per dozen and your overhead costs are 0. 55 dollars per dozen. How many dozen must you produce before your average cost per dozen drops to 2. 45 dollars?

Answers

50 dozen donuts should be produced before your average cost per dozen drops to $2.45

Let x be the number of dozen donuts produced.

The total cost to produce x dozen donuts is:

Total cost = cost of raw materials + overhead costs

Total cost = 0.65x + 0.55x

Total cost = 1.20x

The average cost per dozen can be expressed as:

Average cost per dozen = Total cost / number of dozens

2.45 = 1.20x / x

To solve for x, we can cross-multiply and simplify:

2.45x = 1.20x

x = 50

Therefore, you must produce 50 dozen donuts before your average cost per dozen drops to $2.45.

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What is |5.4|?
What is the opposite of 10?

Answers

Answer:

-10

Step-by-step explanation:

Answer:

1. 5.4

2. The additive inverse is the negative value, -10.

The multiplicative inverse (reciprocal) is 1/10.

Step-by-step explanation:

1. Since the value within the absolute value is not negative then the value remains the same.

2, The opposite of positive 10 could be -10. The reciprocal is 1/10.

The weights of tennis balls are normally distributed, with the mean being 5.15 ounces and the standard deviation being 0.10. what percentage of the balls weigh within one standard deviation of the mean? 50% 68% 95% 99.7%

Answers

68% percentage of the balls weigh within one standard deviation of the mean. Option b is correct.

The weights of tennis balls are normally distributed, with the mean being 5.15 ounces and the standard deviation being 0.10. what percentage of the balls weigh within one standard deviation of the mean to be determined.

What is the empirical rule?

Empirical Rule is defined as an elongation of the prior reading Understanding the Normal Distribution. In the prior reading, the aim was to develope an instinct of the relations between lowered probability and expanded distance from the mean.

Since, from the empirical rule, it can be said that 68% percent of the balls weigh within one standard deviation of the mean because Approx 68% of the data occurs within 1 Standard Deviation of the mean.

Thus, 68% percentage of the balls weigh within one standard deviation of the mean. Option b is correct.

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The empirical rule for normal distributions states that approximately 68% of the data points lie within the range plus and minus one standard deviation of the mean.
The answer is 68%.

Slope intercept form of (3,5) and (0,4)

Answers

Two points are just two points. They have no slope/intercept form. But the line that joins them has.
Y=1/3x+4
(Apparently the answer has to be 20 long so im judt adding in this note, hi!)

Rationalise:
(1)              4/(2+root3+root7)
(2)              4/(2root3+root5)

Answers

(4)/(2+\sqrt3+\sqrt7)\cdot(2-(\sqrt3+\sqrt7))/(2-(\sqrt3+\sqrt7))=(8-4\sqrt3-4\sqrt7)/(2^2-(\sqrt3+\sqrt7)^2)=(8-4\sqrt3-4\sqrt7)/(4-3-2√(3\cdot7)-7)\n\n=(8-4\sqrt3-4\sqrt7)/(-6-2√(21))=(-2(2\sqrt3+2\sqrt7-4))/(-2(3+√(21)))=(2\sqrt3+2\sqrt7-4)/(3+√(21))\cdot(3-√(21))/(3-√(21))\n\n=(6\sqrt3-2√(63)+6\sqrt7-2√(147)-12+4√(21))/(3^2-(√(21))^2)=(6\sqrt3-2√(9\cdot7)+6\sqrt7-2√(49\cdot3)-12+4√(21))/(9-21)

=(6\sqrt3-6\sqrt7+6\sqrt7-14\sqrt3-12+4√(21))/(-12)=(-8\sqrt3+4√(21)-12)/(-12)=(-4(2\sqrt3-√(21)+3))/(-12)\n\n=(2\sqrt3-√(21)+3)/(3)

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(4)/(2\sqrt3+\sqrt5)\cdot(2\sqrt3-\sqrt5)/(2\sqrt3-\sqrt5)=(8\sqrt3-4\sqrt5)/((2\sqrt3)^2-(\sqrt5)^2)=(8\sqrt3-4\sqrt5)/(4\cdot3-5)=(8\sqrt3-4\sqrt5)/(12-5)\n\n=(8\sqrt3-4\sqrt5)/(7)
(1) (4)/(2+√(3) +√(7)) \n \n or, (4)/(2+√(3) +√(7)) * (2 - √(3) -√(7))/(2-√(3)-√(7)) \n \n => \frac{ \sqrt[2]{3} - √(21)+3}{3} \n \n \n (2) \frac{4}{\sqrt[2]{3} + √(5)} \n \n or, \frac{4}{\sqrt[2]{3} + √(5)} * \frac{\sqrt[2]{3}-√(5)}{\sqrt[2]{3}-√(5)} \n \n => \frac{\sqrt[8]{3}-\sqrt[4]{5}}{7}