Please help me on my homework
Please help me on my homework - 1

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Answer 1
Answer:

the correct answer is $948


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Please help me in this! you get 30 points!​
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An author argued that more basketball players have birthdates in the months immediately following July​ 31, because that was the age cutoff date for nonschool basketball leagues. Here is a sample of frequency counts of months of birthdates of randomly selected professional basketball players starting with​ January: 390​, 392​, 360​, 318​, 344​, 330​, 322​, 496​, 486​, 486​, 381​, 331 . Using a 0.05 significance​ level, is there sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency? Do the sample values appear to support the​ author's claim?
Hello I am needing help on this word problem please. I think it's 30 but I'm questioning myself
9. What is the valueof the expression?21.3 + (-34.87)

at the same time a 15 foot pole casts a 7.5 foot shadow a nearby tree casts an 11 foot shadow how tall is the tree​

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answer: 22

15/7.5 = x/11

cross multiply

7.5x = 165

divide by 7.5 on both sides to get the x alone

7.5x/7.5 = 165/7.5

x = 22

the tree is 22 feet

sorry if it’s wrong

Please Help!!In 2010, Martin paid $5,518.00 in Social Security tax. The SS tax rate was 6.2%. What was Martin's taxable income in 2010?

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Answer:

$890 or it's $34211.6

Step-by-step explanation:

you divide 5518 by 6.2% or you multiply them

[8 3 2]What are the dimensions of the matrix?

____ * ____ * = multiplication

Answr if only know with solution..or no brainliest answer to u

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The first dimension is the number of rows in the matrix.

There is 1 row.

The second dimension is the number of columns in the matrix.

There are 3 columns.

In conclusion, the dimensions of the matrix are 1 * 3. 
The matrix's dimensions are 1 by 3.
There is one row by three columns.

For a certain​ candy, 15​% of the pieces are​ yellow, 5​% are​ red, 20​% are​ blue, 20​% are​ green, and the rest are brown. ​a) if you pick a piece at​ random, what is the probability that it is​ brown? it is yellow or​ blue? it is not​ green? it is​ striped?

Answers

P(Brown) = 100 - 15 -5- 20 - 20 = 40%

P(yellow or blue) = 15 + 20 = 35%

P(not green) = 100 - 20 = 80%

P(striped) = 0%

Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a standard deviation of 10.2. Construct a 90% confidence interval for the mean test score.

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Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - (1 - 0.9)/(2) = 0.95. So we have T = 2.064

The margin of error is:

M = T(s)/(√(n)) = 2.064(10.2)/(√(25)) = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

the width of a rectangle is fixed at 8ft. what lengths will make the perimeter at least 200 ft at most 200

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 it will be 2(1+8)<=200