MATHEMATICS HIGH SCHOOL

the lenghtvof each side of a square is 2.5 meter. if each side is doubled in length, what is the effect on the perimeter of the square? a.it remain the same b.it is one half the original perimeter c. it is four time the original perimeter d. it is twice the original perimeter.

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

Alright, lets get started.

The side length of square is given as 2.5.

So, the perimeter if square will be : $4*2.5=10.0$

Once the side is doubled, means new dimension of side of square will be : $2*2.5=5$

So the new perimeter will be : $4*5=20$

The original perimeter is 10.

The new perimeter is 20.

It means the perimeter is twice the original perimeter. : Answer D

Hope it will help :)

Answer 2

Answer: T=4.5

Simplifying3t + 4 = t + 13
Reorder the terms:4 + 3t = t + 13
Reorder the terms:4 + 3t = 13 + t
Solving4 + 3t = 13 + t
Solving for variable 't'.
Move all terms containing t to the left, all other terms to the right.
Add '-1t' to each side of the equation.4 + 3t + -1t = 13 + t + -1t
Combine like terms: 3t + -1t = 2t4 + 2t = 13 + t + -1t
Combine like terms: t + -1t = 04 + 2t = 13 + 04 + 2t = 13
Add '-4' to each side of the equation.4 + -4 + 2t = 13 + -4
Combine like terms: 4 + -4 = 00 + 2t = 13 + -42t = 13 + -4
Combine like terms: 13 + -4 = 92t = 9
Divide each side by '2'.t = 4.5
Simplifyingt = 4.5

I got help from a website called geteasysolution

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Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will last 10 years. The rules of the competition are simple. Each child can split up his or her $2000 into as many separate investments as they please. The children are encouraged to do their research on types of investments. The initial investments made may not be changed at any point during the 10 years; no money may be added and no money may be moved. Whichever child has made the most money after 10 years will be awarded an additional $10,000. Child Performance of investments over the course of the competition Albert $1000 earned 1.2% annual interest compounded monthly $500 lost 2% over the course of the 10 years $500 grew compounded continuously at rate of 0.8% annually Marie $1500 earned 1.4% annual interest compounded quarterly $500 gained 4% over the course of 10 years Hans $2000 grew compounded continuously at rate of 0.9% annually Max $1000 decreased in value exponentially at a rate of 0.5% annually $1000 earned 1.8% annual interest compounded biannually (twice a year) 1. What is the balance of Albert’s $2000 after 10 years? 2. What is the balance of Marie’s $2000 after 10 years? 3. What is the balance of Hans’ $2000 after 10 years? 4. What is the balance of Max’s $2000 after 10 years? 5. Who is $10,000 richer at the end of the competition?

Answers

The balance of Albert is $2159.07; the balance of Marie is $2244.99, the balance of Hans is $2188.35, and the balance of Max is $2147.40. Marie is $10,000 richer at the end of the competition.

What is Compound interest?

Compound interest is defined as interest paid on the original principal and the interest earned on the interest of the principal.

To determine the balance of Albert’s $2000 after 10 years :

If the amount of $1000 at 1.2 % compounded monthly,

A = P(1 +r/n)ⁿ n = 10 years

here P = $1000 and r = 1.2

A = 1000(1 + 0.001)¹²⁰

A = $1127.43

If Albert $500 losing 2%

So 0.98 × 500 = $490

If $500 compounded continuously at 0.8%

So A = P $e^(rt)$

A = 500 $e^(0.008* 10)$

A = 541.6

So the balance of Albert’s $2000 after 10 years :

Total balance = 1127.43 + 490.00+ 541.64 = $2159.07

To determine the balance of Marie’s $2000 after 10 years:

If 1500 at 1.4 % compounded quarterly,

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

If $500 Marie’s gaining 4 %

So 1.04 × 500 = $520.00

So the balance of Marie’s $2000 after 10 years

Total balance = 1724.99 + 520.00 = $2244.99

To determine the balance of Hans’ $2000 after 10 years:

If $2000 compounded continuously at 0.9%

So A = 2000 $e^(0.009* 10)$

A = $2188.3

To determine the balance of Max’s $2000 after 10 years :

If $1000 decreasing exponentially at 0.5 % annually

So A = 1000(1 - 0.005)¹⁰= $951.11

If $1000 at 1.8 % compounded bi-annually

So A = 1000(1 + 0.009)²⁰ = $1196.29

So the balance of Max’s $2000 after 10 years

Total balance = 951.11 + 1196.29 = $2147.40

Therefore, Marie is $10,000 richer at the end of the competition.

Learn more about Compound interest here :

brainly.com/question/25857212

#SPJ2

Answer:

Step-by-step explanation:

Albert:

$1000 earned 1.2% annual interest compounded monthly

= 1000 (1+.001)120

(periodic interest = .012/12 ,n is periods = 10yr x 12 mos)

$500 lost 2% over the course of the 10 years

= 500 (.98)

$500 grew compounded continuously at rate of 0.8% annually

= 500 e^008(10) 10 years interest .008 (in decimal form)

Add these three to see how Albert did with his investments

Given: AB is the perpendicular bisector of IK.What statement can you conclude is true from the given information

BI=BK
B is the midpoint of IK
BK=AK

Answers

BI = BK bc bisecting it means cutting it in half

A cone has a volume of 5 cubic inches. What is the volume of a cylinder that the cone fits exactly inside of?15 in3
20 in3
25 in3
30 in3

Answers

The answer is 15 in³.

The volume of the cone is:
$V_1= \pi r_1 ^(2) (h_1)/(3) = ( \pi r_1^(2) h_1)/(3)$
where:
V₁ - the volume of the cone
r₁ - the radius of the cone
h₁ - the height of the cone

The volume of the cylinder is:
$V_2= \pi r_2h_2^(2)$
where:
V₂ - the volume of the cone
r₂ - the radius of the cone
h₂ - the height of the cone

Since the cone fits exactly inside of the cylinder, they have the same radius and the height:
r₁ = r₂
h₁ = h₂

Also:
V₁ = 5

Now, let's write two volume formulas together:
$V_1= ( \pi r^(2) h)/(3)$
$V_2= \pi rh^(2)$

We can include V₂ into V₁:
$V_1= (V_2)/(3)$

⇒ $V_2=3*V_1$
$V_2=3*5 in^(3)$
$V_2=15 in^(3)$

Helpppp Pleaseee....

Answers

Answer:

$(4 √(10) )/(5)$

Step-by-step explanation:

$(8)/( √(10) ) * ( √(10) )/( √(10) )$

$\frac{8 √(10) }{ {√(10)}^(2) }$

$(8 √(10) )/(10)$

$(4 √(10) )/(5)$

Answer:

4√10/5

Step-by-step explanation:

8/√10

=8/√10 ×√10/√10

=8√10/√10√10

=8√10/10

=4√10/5 (ans)

=2.53 (approximately)

4. Mr. Ramos notices a pattern in the number of people attending the weekly students governing. For weeks 1,2,3,4, and 5, the number of students attending the meetings was 31, 43, 55, 67, and 79, respectively. Write an explicit equations that models the pattern Mr. Ramos notices

Answers

$s=12x+19$ , where s is equal to the number of students attending and x is equal to the week number.

Using the drawing, how would you classify angles 9 and 10? A. Reflex

B. Obtuse

C. Adjacent

D. Vertical

Answers

The answer is D, I guess. Hope this helps
:)

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