What is your preferred method to construct parallel lines? Explain why your method works by describing what construction properties guarantees that they are parallel. You may upload any diagrams to support your thinking.

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

hug js at Udinehebdg sorry this is for points , lol I wish I knew but sorry I dontbut good luck !

Related Questions

Find the product.(7x - 6)2A. 49x2 + 36 B. 49x2 - 84x + 36 C. 7x2 - 84x + 36 D. 7x2 + 36
Devaughn is 9 years younger than Sydney. The sum of their ages is 61. What is Sydney's age?
Which category does each card go into?
Select the correct difference. -3z 7 - (-5z 7)
What is an equation in slope intercept form for the line perpendicular to y = - 2x + 5that contains (-8, 1)?1A.Oy - 8 = 2 (x + 1)B. O y=-2x - 1C.O. 1=0:0 x = žy + 14

The trees at a national park have been increasing in numbers. There were 1,000 trees in the first year that the park started tracking them. Since then, there have been as many new trees each year. Create the sigma notation showing the infinite growth of the trees and find the sum, if possible. Year New trees 1 1000 2 200 3 40

Answers

Answer:

Step-by-step explanation:

There were 1000 trees in the first year and every year new trees are getting added.

The sequence formed for the new trees every year is

Year 1 2 3

New trees 1000 200 40

We see a geometric sequence has been formed by the new trees added

Ratio of the second year and 1st year trees added = $(200)/(1000)=(1)/(5)$

Similarly ratio of trees added in 3rd year to 2nd year = $(40)/(200)=(1)/(5)$

So there is a common ratio of $(1)/(5)$

Explicit formula of a geometric sequence representing growth of the trees by

$T_(n)=a(r)^(n-1)$

where a = number of trees grown first year

r = common ratio

n = number of years

Explicit formula showing the growth of the trees using sigma notation will be

$\sum_(n=1)^(\infty)1000((1)/(5))^(n-1)$

And Formula for number of trees every year will be

$\sum_(n=1)^(\infty)1000+1000((1)/(5))^(n-1)$

$\sum_(n=1)^(\infty)1000[1+((1)/(5))^(n-1)]$

Sum of the trees will be

$S=(a)/(1-r)$

= $(2000)/(1-(1)/(5))$

= $(2000)/((4)/(5) )$

= $(2000* 5)/(4)$

= 2500

A student runs 100 meters in 11 seconds. What is the speed of the student? 9.1 miles per hour 16miles per hour 20.3miles per hour 24miles per hour

Answers

The answer is 20.3 miles per hour. First, you need to change meter and second to mile and hour. The 100 meter equals 100/1609 mile. 11 seconds equals 11/3600 hour. Then using mile number divides by hour you can get the answer.

What is greater 4 yards or 13 feet?

Answers

1 yard = 3 feet

4 yards = 3 × 4 = 12 feet

13 feet is greater than 4 yards

A sequence is defined recursively by the formula f(n + 1) = f(n) + 3 . The first term of the sequence is –4. What is the next term in the sequence?

Answers

Translate the equation to math.
It says the term after the current term is the current term plus 3.
Next term = this term + 3
Next term = -4+3
The next term is then -4+3 or -1.

Answer= - 1

Hope this helps :)

Which fraction is greatest 5/6 7/9 2/3 or 9/12