I am really struggling with this question because I can't find anything on aphelion and perihelion, it's not a topic we went over because it is an extra assignment. 4. How far away from the sun was Mercury at aphelion? On what day did aphelion occur?
5. How far away from the sun was Mercury at perihelion? On what day did it occur?
6. How many days elapsed between aphelion and perihelion? What percent of the time to complete one orbit was this?
7. What was the average radius of Mercury in its orbit that you calculated? How does it compare to the accepted value of 0.387 AU? Calculate the percent error using the following equation. Show your work.

If someone could explain it to me I would really appreciate it!

Answers

Answer 1

Answer:
I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.

I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:

Distance at Aphelion (point in it's orbit that's farthest from the sun):
69,816,900 km
0. 466 697 AU

Distance at Perihelion(point in it's orbit that's closest to the sun):
46,001,200 km
0.307 499 AU

Perihelion and aphelion are always directly opposite each other in
the orbit, so the time between them is 1/2 of the orbital period.

Mercury's Orbital period = 87.9691 Earth days

1/2 (50%) of that is 43.9845 Earth days

The average of the aphelion and perihelion distances is

1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
or
1/2 ( 0.466697 + 0.307499) = 0.387 098 AU

This also happens to be 1/2 of the major axis of the elliptical orbit.

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3. Reading the graph, we find the velocity is 8 m/s at t-2 s and 16 m/s at t-4 s. Based on this information,what is the acceleration?

Answers

first take the change in time, which is the difference of 4 & 2, so 2 and that’s that’s denominator, then take the change in velocity, which is the difference of 16 and 8, which is 8 ( ur numerator)

8 / 2 = 4 so ur acceleration should be 4

If a step-up transformer has a primary coil with 15 turns, how many turns would be required in the secondary coil in order to increase the voltage from 80 volts to 160 volts? A. 8 turns B. 30 turns C. 80 turns D. 160 turns

Answers

Answer:

$N_2=30turns$

So option (b) will be correct option

Explanation:

We have given that there is a step up transformer in which number of turns in primary coil is 15

That is, $N_1=15$

Primary voltage $V_1=80volt$ , and secondary voltage $V_2=160volt$

We have to find the number of turns in the secondary \

We know that for the transformer

$(N_1)/(N_2)=(V_1)/(V_2)$

$(15)/(N_2)=(80)/(160)$

$N_2=30turns$

So option (b) will be correct option

Which theory proposes that the moon was a passing asteroid pulled into orbit by Earth's gravity?

Answers

The correct answer to the question above is the capture theory. The capture theory proposes that the moon was a passing asteroid pulled into the orbit by the Earth's gravity. It says that the moon was originally orbiting the sun, not the Earth.

Answer:

Capture Theory

Explanation:

According to capture theory, moon is passing space rock-asteroid which was captured into the orbit around the Earth due to gravity. Other planets have moons which are captured asteroid like Mars has two moons-Phobos and Deimos. Jupiter has many moons which are captured asteroids. Capture theory explains the difference in the composition of Earth and the moon.

Streams of electrically charged particles flowing at high speeds from the sun make up the

Answers

That's the so-called 'solar wind'.

At t = 0, one toy car is set rolling on a straight track with initial position 13.5 cm, initial velocity -4.2 cm/s, and constant acceleration 2.60 cm/s2. At the same moment, another toy car is set rolling on an adjacent track with initial position 8.5 cm, initial velocity 5.20 cm/s, and constant zero acceleration.(a) At what time, if any, do the two cars have equal speeds?

(b) What are their speeds at that time?

(c) At what time(s), if any, do the cars pass each other? ...?

Answers

(a) We must first look at the formulas of the velocities of each toy car. v1 =
-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then
v1 = v2
-4.2 + 2.60t = 5.20
2.60t = 9.40
t = 3.62 s

(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Michelle melted a compound in the lab and performed the same procedure five times. The chart below shows the time it took for the compound to melt during the five trials.Trial Time (min:sec)
1 3:14
2 3:10
3 4:05
4 3:12
5 3:09

After reviewing her data, she realized that trial 3 was vastly different from the other four trial times. Which of the following reasons could explain the radical difference in melting time for trial 3?

A larger quantity of compound was used in trial 3.
The compound started at a lower temperature in trial 3.
The burner was not directly under the compound during trial 3.
all of these

Answers

Answer:

It is actually all of these

Explanation:

Final answer:

Several factors could account for the variance seen in the third trial's melting time. This could be due to using a larger quantity of compound, starting at a lower temperature, or the burner not being directly under the compound.

Explanation:

The radical difference in melting time for trial 3 in Michelle's experiment could be explained by several variables. Given the information present, Michelle could have used a larger quantity of compound in trial 3, thus taking longer to melt. Secondly, the compound may have started at a lower temperature, requiring additional time to reach its melting point. Finally, if the burner was not directly under the compound, this could also explain the longer time as the heat wouldn't be as concentrated on the compound. In other words, the answer could be 'all of these' as they are all potential reasons as to why the third trial had a heavier melting time.

Learn more about Melting Time here:

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