MATHEMATICS HIGH SCHOOL

26 past due! last question!! ty for all you guys' help!!

Answers

Answer 1

Answer:

Answer:

Slope = 3/2, or 1.5

Step-by-step explanation:

Pick out the lattice points ( points that intersect the graph markings)

I see 2 points, ( 3, 1), and ( 5, 4)

Slope = Δy/xΔ = 4 - 1/5 - 3 = 3/2

Slope is 3/2, or 1.5

-Chetan K

Answer 2

Answer: Slope is 3/2
You rise 3 and then go right 2
Rise over run!;D

Related Questions

(02.02 HC)Andrew makes $6 an hour plus $9 an hour for every hour of overtime. Overtime hours are any hours more than 40 hours for the week. Part A: Create an equation that shows the amount of wages earned, W, for working x hours in a week when there is no overtime. (3 points) Part B: Create an equation that shows the amount of wages earned, S, for working y hours of overtime. Hint: Remember to include in the equation the amount earned from working 40 hours. (3 points) Part C: Andrew earned $330 in 1 week. How many hours (regular plus overtime) did he work? (4 points)
GIVEN:MN is an angle bisector of ∠JMKProve:m∠JMN=1/2m∠JMK
Find the total amount you will pay given an original price of $24.99 and tax rate of 5%.Enter the correct answer in the box.
I need help please :)Answer opts.35302228
Sara borrows $56 from her mother to buy a new pair of jeans. If she decreases her debt by $4 each week, how many weeks will it take her to pay off the whole amount she owes her mother? A. 15 weeks B. 16 weeks C. 12 weeks D. 14 weeks

3/4 (h + 20) in distributive property

Answers

Answer:

3/4h + 15

Step-by-step explanation:

3/4 (h+20)

= 3/4h + 3/4 * 20

= 3/4h + 15

2sin²(x)-5cos(x)+1=0

Answers

Remember the basic trig identity

$\sin^2 x + \cos^2 x = 1$

We can move the cosine term to the right side to get

$\sin^2 x = 1 - \cos^2 x$

We can then replace $\sin^2 x$ in the original equation and basically factor the resulting equation like a quadratic:

$2(1 - \cos^2 x) - 5 \cos x + 1 = 0$
$(2 - 2 \cos^2 x) - 5 \cos x + 1 = 0$
${-2} \cos^2 x - 5 \cos x + 3 = 0$
$2 \cos^2 x + 5 \cos x - 3 = 0$
$(2 \cos x - 1)(\cos x + 3) = 0$

Then, we can see that $\cos x$ either equals $(1)/(2)$ or $-3$ . But since the range of cosine is only from $[-1, 1]$ , cosine can't equal $-3$ at all! So, you just have to solve for x when $\cos x = (1)/(2)$ , which is when

$x = \{ (\pi)/(3), (5\pi)/(3) \} + 2 \pi k | k \in \mathbb{Z}$
(The last part of the solution says that k can be any integer.)

If you only want solutions in the range $[0, 2\pi)$ , then your answer is just

$x = (\pi)/(3), (5\pi)/(3)$

Sean has 1/5 of a cupcake and 1/5 of a large cake. are the wholes the same?

Answers

yes they are because its the same two numbers.

Yes they are the same...

Two triangles that have the same side lengths will always be congruent.A. True
B. False

Answers

True, this is in accordance to the side-side-side postulate.

A local cinema found that if the price of admission was $17the attendance was about 1900 customers per weekWhen the price of admission was dropped to $9. Attendance increased to about 3050 per week. Write a equation for the attendance in terms of the price. P i (A=mp+b )

Answers

Answer:

f(A)= -143.75p + 4343.75

Step-by-step explanation:

Let price be x, and attendance, y

According to the given data,

admission was $17 the attendance was about 1900 customers

admission was $9 the attendance was about 3050 customers

Therefore, the points in terms of e and y coordinates would be , (17, 1900) --> (x1,y1)

& (9, 3050)---->(x2,y2)

Next is to calculate slope of linear equation i.e

m= (y2-y1)/(x2-x1)

m=(3050-1900)/(9-17)

m= -143.75

Now in order to find the equation, we use point-slope

y-y1= m (x-x1)

considering the coordinates (17, 1900) and slope -143.75

Equation becomes

y-1900 = -143.75( x- 17)

y-1900= -143.75x + 2443.75

y= -143.75x + 4343.75

or can be written as,

f(A)= -143.75p + 4343.75

Answer:

Step-by-step explanation:

From the question, A local cinema found that if the price of admission was $17the attendance was about 1900 customers per weekWhen the price of admission was dropped to $9. Attendance increased to about 3050 per week. Write a equation for the attendance in terms of the price. P i (A=mp+b )

Let price be a,and attendance, b

Attendance: 1,900 customers, when PRICE = $17

Attendance: 3,050 customers, when PRICE = $9

We then get the points,

(17, 1,900) & (9, 3,050)

Slope of linear equation,

(17,1900) (9, 3050)

find the slope m

(3050-1900)/(9 - 17)

1150/-8

-143.75=m

A=mp+b

A=-143.75p+b

using Attendance as a function of ticket price.

A(p) = mp + b

We have two points (p, A): (17, 1900), (9, 3050)

Slope: m = (2800-1500)/(7-17) = 1300/-10 = -130

A = -130p + b

Using (17, 1900) as (p, A) find b

1900 = -143.75(17) + b

1900 = -2443.75 + b

4343.75 = b

A = -143.75p + 4343.75

60 POINTS !!!!!! PLEASE HELP

Answers

Answer:

Step-by-step explanation:

1) S

2) Line

3) Point

4) All coplanar points equidistant from a given point

5) 3rd one or C

Answer:

1. S

2. Line

I'm not sure about the rest...sorry

Step-by-step explanation:

Other Questions

For f(x)=3x+4, find f(2) and find x such that f(x)=17

Solve using substitution, y=2x+5 y=6x+1

5 books and 9 magazines cost $150.50 altogether. 9 books and 5 magazines cost $175.70. How much does 1 book and 1 magazine cost?

Use long division to find the quotient below.(4x² - 7x-2) + (x-2)