PHYSICS HIGH SCHOOL

I need help on (a)
I don't know what equation to use?
I need help on (a) I don't know what equation - 1

Answers

Answer 1
Answer:
Impulse = (force) x (length of time the force lasts)

I see where you doodled  (60)(40)  over on the side, and you'll be delighted
to know that you're on the right track !

Here's the mind-blower, which I'll bet you never thought of:
On a force-time graph, impulse (also change in momentum)
is just  the area that's added under the graph during some time !

From zero to 60, the impulse is just the area of that right triangle
under the graph.  The base of the triangle is  60 seconds.  The
height of the triangle is  40N .  The area of the triangle is not
the whole (base x height), but only 1/2 (base x height).

  1/2 (base x height) = 1/2 (60s x 40N) = 1,200 newton-seconds

That's the impulse during the first 60 seconds.  It's also the change in
the car's momentum during the first 60 seconds. 

Momentum = (mass) x (speed)

If the car wasn't moving at all when the graph began, then its momentum is  1,200 newton-sec after 60 seconds.  Through the convenience of the SI system of units, 1,200 newton-sec is exactly the same thing as 1,200 kg-m/s .  The car's mass is 3 kg, so after 60 sec, you can write

    Momentum = M x V = (3 kg) x (speed) = 1,200 kg-m/s

and the car's speed falls right out of that. 

From 60to 120 sec, the change in momentum is the added area of that
extra right triangle on top ... it's 60sec wide and only 20N high.  Calculate
its area, that's the additional impulse in the 2nd minute,  which is also the
increase in momentum, and that'll give you the change in speed.

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A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3 m/s2? F=
M=
A=

Answers

The force to accelerate down an alley way will be "30 N".

In the given question, the values are:

Mass,

  • m = 10 kg

Acceleration,

  • a = 3 m/s²

As we know the formula for finding the force will be:

→ Force = Mass* Acceleration

or,

→       F = m* a

By putting the given values in the formula, we get

→           = 10* 3

→           = 30 \ N

Thus the above answer is correct.  

Learn more about mass here:

brainly.com/question/12195736

Hello!

A 10 kg bowling ball would require. What force to accelerate down an alleyway at a rate of 3 m/s²  ?

We have the following data:

F (force) = ? (in N or kg.m/s²)

m (mass) = 10 kg

a (acceleration) = 3 m/s²

We apply the data to the Net force formula, we have:

F =m*a

F = 10\:kg * 3\:(m)/(s^2)

F = 30\:kg*(m)/(s^2) \to \boxed{\boxed{F = 30\:N}}\:\:\:\:\:\:\bf\green{\checkmark}

Answer:

The force is 30 Newton

______________________

\bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

( Pennfoster plz help ) Which of the following does not accurately describe the forces that exist with an atom? A. Electrons closer to the nucleus and electrons farther from the nucleus repel due to like charges. B. Electrons positioned farther away from the nucleus are less attracted to the nucleus than are electrons positioned closer to the nucleus. C. Electrons positioned closer to the nucleus have a greater attraction to the protons and are more likely to be discharged from the atom than electrons farther away. D. Electrons in an atom are attracted to the protons within the nucleus due to opposite charges.

Answers

I would say C i'm not 100% sure

Choice-C is nonsense.

Electrons positioned closer to the nucleus are closer to the protons in the nucleus and more strongly attracted to them.  Therefore these electrons are LESS likely to be discharged from the atom than electrons farther away from the nucleus are.

The period of an ocean wave is 4 seconds. What is the waves frequency?

Answers

Frequency= 1/period
Frequency=1/4
Frequency= 0.25Hz

Who first introduced the idea that the Sun is the center of the universe?A. Albert Einstein
B. Edwin Hubble
C. Johannes Kepler
D. Nicolaus Copernicus

Answers


I'm not sure that Copernicus was the 'first', but he was
certainly before any of the other names on that list.

Also, to be technical about it, none of those other choices
would agree that the sun is the center of the "universe" ...
only the center of the solar system.
           Your answer would be D. Nicolaus Copernicus, he introduced this idea in a pamphlet that he published in 1514.

The Nazca Seafloor Plate Pushes Into The South American Continental Plate. What Is The Most Likely Result?

Answers

the Nazca plate will move under the south american plate. i know its late but it will help others!

Maria throws an apple vertically upward from a height of 1.3 m with an initial velocity of +2.8 m/s. Will the apple reach a friend in a tree house 5.9 m above the ground? The acceleration due to gravity is 9.81 m/s 21. No, the apple will reach 5.27136 m below the tree house2. Yes, the apple will reach 5.27136 m above the tree house3. No, the apple will reach 1.43117 m below the tree house4. No, the apple will reach 1.5289 m below5. Yes, the apple will reach 1.5289 m above the tree house6. Yes, the apple will reach 1.43117 m above the tree house

Answers

Answer:

No, the apple will reach 4.20041 m below the tree house.

Explanation:

t = Time taken

u = Initial velocity = 2.8 m/s

v = Final velocity = 0

s = Displacement

g = Acceleration due to gravity = -9.81 m/s² = a (negative as it is going up)

Equation of motion

v^2-u^2=2as\n\Rightarrow s=(v^2-u^2)/(2a)\n\Rightarrow s=(0^2-2.8^2)/(2* -9.81)\n\Rightarrow s=0.39959\ m

The height to which the apple above the point of release will reach is 0.39959 m

From the ground the distance will be 1.3+0.39959 = 1.69959 m

Distance from the tree house = 5.9-1.69959 = 4.20041 m

No, the apple will reach 4.20041 m below the tree house.

The values in the option do not reflect the answer.

Final answer:

The apple will not reach the friend in the tree house as it will only reach a height of approximately 1.527 m.

Explanation:

To determine whether the apple will reach a friend in a tree house 5.9 m above the ground, we can use the equations of motion. Since the apple is thrown vertically upward, it will experience a negative acceleration due to gravity. Using the equation h = vo*t + (1/2)*a*t^2, where h is the final height, vo is the initial velocity, a is the acceleration, and t is the time, we can calculate the time it takes for the apple to reach a height of 5.9 m. Plugging in the values, we get:

5.9 = 2.8*t + (1/2)*(-9.81)*t^2

Simplifying the equation, we have:

-4.905*t^2 + 2.8*t - 5.9 = 0

Using the quadratic formula, we can solve for t. The quadratic formula is t = (-b ± sqrt(b^2 - 4ac)) / (2a), where a = -4.905, b = 2.8, and c = -5.9.

Plugging in the values, we get:

t = (-2.8 ± sqrt(2.8^2 - 4*(-4.905)*(-5.9))) / (2*(-4.905))

After evaluating the formula, we find that the apple will take approximately 1.527 seconds to reach a height of 5.9 m. Since the apple continues to rise after reaching this height, it will not reach the friend in the tree house.
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