PHYSICS HIGH SCHOOL

State two examples for each of the four states of matter

Answers

Answer 1
Answer:

Answer:

1. Solid- rock, shoe

2. Liquid- water, dish soap

3. Gas- oxygen, carbon dioxide

4. Plasma- lightning, stars

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Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first object. they both slide up the same frictionless incline plane. which object rises to a greater height?

Answers

Answer:

They both rises to same height.

Explanation:

When an object is sliding up in friction less surface than according to conservation of energy its potential energy will be converted into kinetic energy.

mgH=(1)/(2)mv^(2)\n v=√(2gH)

Here, m is the mass, v is the velocity, g is the acceleration due to gravity and H is the height.

Here the height is independent on the mass of an object and its only depend on velocity.

Now according to the question, two objects have same velocity but they have different masses.

Therefore, they rises to the same height because  height will not change with mass.

Both objects rise to the same height

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Further explanation

Let's recall Kinetic Energy Formula as follows:

\large {\boxed{Ek = (1)/(2)mv^2} }

Ek = Kinetic Energy ( Joule )

m = mass of the object ( kg )

v = speed of the object ( m/s )

Let us now tackle the problem !

\texttt{ }

Given:

initial speed of first object = initial speed of second object = v

final speed of first object = final speed of second object = 0

mass of first object = m

mass of second object = 2m

Asked:

height = H = ?

Solution:

We will use Conservation of Energy to solve this problem:

Ep_1 + Ek_1 = Ep_2 + Ek_2

0 + (1)/(2)mv^2 = mgH + 0

(1)/(2)v^2 = gH

v^2 = 2gH

\boxed {H = (v^2)/(2g)}

\texttt{ }

H_1 : H_2 = (v_1^2)/(2g) : (v_2^2)/(2g)

H_1 : H_2 = v_1^2 : v_2^2

H_1 : H_2 = v^2 : v^2

H_1 : H_2 = 1 : 1

\boxed{ H_1 = H_2 }

\texttt{ }

Conclusion:

Both objects rise to the same height

\texttt{ }

Learn more

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Answer details

Grade: High School

Subject: Physics

Chapter: Energy

4 points Two cylindrical resistors R, and R2 made from the same material are connected in parallel in a circuit. Both resistors are at the same temperature when the circuit is operational. Resistor R, has length and diameter d. Resistor R has length 8l and has a diameter d/1. Determine by what factor is the resistance R greater than R.St. your answer as an integer with no decimal place. Type your answer...

Answers

To determine the factor by which the resistance of resistor R2 is greater than resistor R1, we can use the formula for resistance of a cylindrical resistor:

R = ρ * (L/A)

Where R is the resistance, ρ is the resistivity of the material, L is the length of the resistor, and A is the cross-sectional area of the resistor.

Since both resistors are made from the same material and are at the same temperature, the resistivity ρ is the same for both resistors.

Let's calculate the resistance for R1 and R2 separately.

For resistor R1 (length = L and diameter = d), the cross-sectional area A1 is given by:

A1 = π * (d/2)^2

For resistor R2 (length = 8L and diameter = d/1), the cross-sectional area A2 is given by:

A2 = π * ((d/1)/2)^2

Simplifying the equations:

A1 = π * (d/2)^2 = π * (d^2/4)

A2 = π * ((d/1)/2)^2 = π * (d^2/4)

As we can see, both resistors have the same cross-sectional area A.

Now, let's calculate the resistance for R1 and R2:

R1 = ρ * (L/A1) = ρ * (L / (π * (d^2/4)))

R2 = ρ * (8L/A2) = ρ * (8L / (π * (d^2/4)))

Simplifying the equations further:

R1 = (4ρL) / (πd^2)

R2 = (32ρL) / (πd^2)

Now, let's find the factor by which the resistance R2 is greater than R1:

Factor = R2 / R1 = ((32ρL) / (πd^2)) / ((4ρL) / (πd^2))

Canceling out common terms:

Factor = (32ρL * πd^2) / (4ρL * πd^2)

Factor = 32 / 4

Factor = 8

Therefore, the resistance R2 is 8 times greater than the resistance R1.

The resistance of second resistor R2, is 16 times greater than the resistance of the first resistor R1.

The resistance of a cylindrical resistor is given by R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area (which is πd²/4 for a cylinder). For R1, it has length L and diameter d. For R2, it has length 8L and diameter d/1. The resistance of R2 is therefore:

R2 = ρ(8L)/(π(d/1)²/4)

By comparing R2 to R1, we find that R2 is 16 times the resistance of R1.

The resistance of second resistor R2, is 16 times greater than the resistance of the first resistor R1.

To know more about resistor, visit:

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when the lowest frequency above the fundamental is played, at what height will the particles' displacement be out of phase and have the same amplitude as that of the particles 8.0cm above the surface of the water? give your answer as a distance above the surface of the water.

Answers

Answer:

theg watte wil shajka

Explanation:

bshswu

A strand of 10 lights is plugged into an outlet. How can you determine if the lights are connected in series or parallel?A) Unscrew one light. If the other lights stay on, it's a series circuit.
B) Unplug the strand. If the first light stays on, it's a series circuit.
C) Unscrew one light. If the other lights turn off, it's a series circuit.
D) Cut the strand in half. If the plugged in half stays on, it's a series circuit.

Answers

series circuits, the current runs through all of them and they are conncted by the bulbs, so if you unscrew one, all light turn off

paralell, they are kinda independent, if you unscrew one, nothing happens to others

look at options
A. unscrew 1 light, if stay on, it's series, false, that's paralell

B. unplug, if stay  on (then you have pozessed lights)

C. unsrew light, if stays on, it's parlell RIGHT ANSWER

D. cut strand in half (will cut power) if the plugged half stays on, then (pozessed circuit)

answer is C

Is radioactivity on the Earth something relatively new?

Answers

naturally occurring radioactive elements have been around since the Earth's formation

A ball is at rest at the top of a hill. It rolls down the hill. At the bottom of the hill the ball hits a wall and stops. Which energy changes occur? A) Gravitational potential energy, internal energy, kinetic energy B) Gravitational potential energy, kinetic energy, internal energy C) Kinetic energy, gravitational potential energy, internal energy D) Kinetic energy, internal energy, gravitational potential energy

Answers

Final answer:

The correct answer is C) Kinetic energy, gravitational potential energy, internal energy.

Explanation:

When the ball is at the top of the hill, it has gravitational potential energy because of its position. As it rolls down the hill, this potential energy is converted into kinetic energy, which is the energy of motion.

When the ball hits the wall at the bottom of the hill and stops, some of the kinetic energy is transformed into internal energy, which is the energy associated with the motion of particles within the ball.

Learn more about energy changes here:

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