Answer:
Given :-
Initial Velocity (u) = 5 m/s
Final Velocity (v) = 15 m/s
Time (t) = 7.5 seconds
To Find :-
Distance (s) = ?
Solution :-
First of all we will find the acceleration of car :
→ Acceleration = Final Velocity - Initial Velocity ÷ Time
→ Acceleration = 15 - 5 ÷ 7.5
→ Acceleration = 10 ÷ 7.5
→ Acceleration = 1.3 m/s²
Now, by using Second equation of motion we can find distance travelled by the car :
→ s = ut + ½ at²
→ s = 5 × 7.5 + ½ × 1.3 × (7.5)²
→ s = 37.5 + ½ × 1.3 × 56.25
→ s = 37.5 + 1.3 × 28.125
→ s = 37.5 + 29.425
→ s = 66.925 m
Therefore,the distance travelled by the car is 66.925 m.
1
I REALLY NEED HELP !
Answer:
c = 894.90 m/s
Explanation:
Given data:
Frequency of wave = 471 Hz
Wavelength of wave = 1.9 m
Speed of wave = ?
Solution:
Formula:
Speed of wave = frequency × wavelength
c = f×λ
c = 471 Hz × 1.9 m
Hz = s⁻¹
c = 471s⁻¹ × 1.9 m
c = 894.90 m/s
The speed of wave is 894.90 m/s.
b: v0 = v2 > v1 = 0
c: v0 = v2 > v1 > 0
d: v0 > v1 > v2 > 0
e: v0 > v2 > v1 = 0
The correctanswer between all the choices given is the third choice or letter C. I amhoping that this answer has satisfied your query and it will be able to helpyou in your endeavor, and if you would like, feel free to ask another question.
Answer: option c: v₀ = v₂ > v₁ > 0
Explanation:
1) Velocity is the rate of change of the position with time. Therefore, in a graph of position vs time, the velocity is the slope of the path that describes the motion.
2) In this case you are requested to compare the speeds, i.e. just the magnitudes of the velocities. You can perform that by comparing the slopes in the three positions (x₀, y₀), (x₁, y₁), and (x₂, y₂).
3) Regarding v₁, since it corresponds to the peak of the curve (x₁.y₁), the vertical component of the velocity is zero (the horizontal component is constant, since there is not any horizontal force acting), so at this point the speed reaches its minimum value, then v₁ > 0, and v₁ is less than any other speed.
4) Regarding v₀ and v₂, at (x₀, y₀) and (x₂, y₂), note that those are points at the same distance from the axis of symmetry of the curve (assuming it is perfect parabola, which is what the graph intends to show).
That means that the velocities at those points are equal in magnitude but opposite in signs. Since, you are asked about the speed, which is magnitude, you conclude v₀ = v₂.
In conclusion v₀ = v₂ > v₁ > 0, which is the option c.
Explanation:
When a charged object is brought near a neutral object without touching each other a charge arises on the neutral object. This method of charge development is known as induced charge.
On the other hand, when a charged object touches a neutral object and then the charged object is removed will lead to the development of a charge on the neutral object. This charge is known as residual charge.
Thus, we can conclude that when a charged body is brought close to an uncharged body without touching it, an induced charge may result on the uncharged body. When a charged body is brought into contact with an uncharged body and then is removed, a residual charge may result on the uncharged body.