CHEMISTRY COLLEGE

What is the covalent bond for CO?​

Answers

Answer 1
Answer:

Answer:

Covalent bond or common bond is one of the types of chemical bonds. This connection arises from electronic participation. In fact, atoms that need to receive electrons to achieve stable electron arrangement (noble gas electron arrangement or octagonal arrangement) share electrons in their valence layer with other atoms. In this case, the transfer of electrons from one atom to another does not take place, but only a pair of electrons, called a bonded or shared electron pair, belongs to the nucleus of two atoms.

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Calculate the number of C atoms in 9.837 x 1024 molecules of CO2. Please help
Unknown A melts at 113- 114oC. Known compounds 3-Nitroaniline and 4-Nitrophenol both melt at 112-114 oC. If A is mixed with 3-Nitroaniline and the melting point becomes broad and depressed, what must A be __________A) 3-Nitroaniline B) 4-Nitrophenol C) Both
Calculate the molar mass of the following:(a)the anesthetic halothane, C2HBrClF3(b)the herbicide paraquat, C12H14N2CL2(c)caffein, C8H10N4O2(d)urea, CO(NH2)2(e)a typical soap,C17H35CO2Na

Ne ( g ) effuses at a rate that is ______ times that of Cl 2 ( g ) under the same conditions.

Answers

Answer: 1.88times as that of Cl2

Explanation:

According to Graham law of effusion , the rate of effusion is inversely proportional to the square root of the molar mass

Rate= 1/√M

R1/R2 =√M2/M1

Let the rate of diffusion of Ne= R1

And rate of diffusion of Cl2 = R2

M1 ,molar mass of Ne= 20g/mol

M2,molar mass of Cl2 =71g/mol

R1/R2 = √ (71/20)

R1/R2 = 1.88

R1= 1.88R2

Therefore the Ne effuses at rate that is 1.88times than that of Cl2 at the same condition.

A construction worker is transporting pieces of plastic in two stacks with touching pieces. In Stack 1, both pieces of plastic are the same size. In Stack 2, the bottom piece is the same size as those in Stack 1, and the top piece is larger. The diagram above shows the energy of the molecules in the pieces of plastic before they touched.After a while, which of the two top plastic pieces will be cooler, and why?

Answers

Answer:

The larger top plastic piece will be cooler than the smaller top plastic piece, because the energy that transferred to it was spread out over more molecules.

Explanation: I did the test

What is the empirical formula of a compound that is 64.3 % c, 7.2 % h, and 28.5 % o by mass?

Answers

Asnwer : Empirical formula of a compound is : C_(3)H_(4)O

Given information : C = 64.3 % , H = 7.2 % , O = 28.5 %

Step 1 : Convert the given percentage (%) to grams.

Explanation : Let the total mass of the compound be 100 grams.

Mass of C = 64.3 g

(100g)* ((64.3percent))/((100percent)) = 64.3g

Mass of H = 7.2 g

(100g)* ((7.2percent))/((100percent)) = 7.2g

Mass of O = 28.5 g

(100g)* ((28.5percent))/((100percent)) = 28.5g

Step 2 : Convert the grams of each compound to moles.

Moles = (Grams)/(Molar mass)

Molar mass of C = 12.0g/mol  

Molar mass of H = 1.0 g/mol

Molar mass of O = 16.0g/mol

Moles of C = (64.3g)/(12.0(g)/(mol))

Moles of C = 5.36 mol

Moles of H = (7.2g)/(1.0(g)/(mol))

Moles of H = 7.2 mol

Moles of O = (28.5g)/(16.0(g)/(mol))

Moles of O = 1.78 mol

Step 3 : Find the mole ratio of C , H and O

Mole ratio is calculated by dividing the mole values by the smallest value.

Mole of C = 5.36 mol , Mole of H = 7.2 mol , Mol of O = 1.78 mol

Out of the three mole values , mole value of O that is 1.78 mol is less , so we divide all the mole values by 1.78 mol.

Mole of C = (5.36mol)/(1.78mol) = 3.0

Mole of H = (7.2mol)/(1.78mol) = 4.0

Mole of O = (1.78mol)/(1.78mol) = 1.0

C : H : O = 3 : 4 : 1

So empirical formula of the compound is C_(3)H_(4)O_(1) or C_(3)H_(4)O

Explain how paper chromatography could be used to separate a mixture of different coloured inks

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The mobile phase is a suitable liquid solvent or mixture of solvents. You probably used paper chromatographyas one of the first things you ever did in chemistry to separate out mixturesof coloured dyes - for example, the dyes which make up a particular ink

I hope that this answer helps you out

Study the image. Which image best describes what the arrows represent?

Answers

i’m pretty sure it’s d, please let me know !

Identify each element below, and give the symbols of the other elements in its group. a. [Ar] 4s23d104p4
b. [Xe] 6s24f145d2
c. [Ar] 4s23d5.

Answers

Answer:

Explanation:

the electron configuration is defined as the distribution of electrons of an atom or molecule in atomic or molecular orbitals. It is

used to describe the orbitals of an atom in its ground state

The valence electrons, electrons in the outermost shell, can be used to know the chemical property

a)

Chemical Name of the Element: Selenium

Chemical Symbol: Se

Group it belong in periodic table:6A

Other Element in the same group:tellurium(Te),,sulfur(S)

atomic number = 34

Selenium is a chemical element that has symbol Se It is a nonmetal which is usually classified as metalloid with properties that are intermediate between the elements above and below in the periodic table.

b)Chemical Name of the Element:Hafnium

Chemical Symbol: Hf

Group it belong in periodic table:4B

Other Element in the same group: Titanium( Ti )Rutherfordium

atomic number: 72

Hafnium is a solid at room temperature.

c)Chemical Name of the Element: Manganese

Chemical Symbol:Mg

Group it belong in periodic table:Mn

Other Element in the same group:Bohrium(Bh) ,Technetium(Tc)
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