Which of the following planets has the lowest average density?1) Venus
2) Mercury
3) Earth
4) Mars

Please explain

Answers

Answer 1

Answer:

The planet that has the lowest average density is Mars. The correct option is 4.

What is average density?

The entire mass of a region divided by the total volume of that region yields the mean or average density.

By multiplying each compound's density by its volume and then dividing the result by the sum of all the volumes, one can determine the mixture's average density.

The average density of different planets is:

Venus; 5.2

Mercury; 5.4

Earth; 5.5

Mars; 3.9

So, the lowest density out of these planets is Mars. Density is something's concentration. If the density is low, the weight of the object will be low. When placed in water, an object will float if its density is lower than that of the water, whereas it will sink if its density is higher.

Therefore, the correct option is 4) Mars.

To learn more about average density, refer to the below link:

brainly.com/question/18767401

#SPJ2

Answer 2

Answer: Mars because it has low levels of gravity and if given the oppurtunity could float on water.

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Where does surface water collect if it does not flow to the ocean?

Answers

in lakes or wetland such as marshes or swamps

The carbon cycle involves an exchange of carbon between the atmosphere and geosphere only.

Answers

The correct answer for the question that is being presented above is this one: "FALSE." The carbon cycle involves an exchange of carbon between the atmosphere and geosphere only. This statement is false -- as well as the geosphere, the carbon cycle also moves carbon between the atmosphere, the biosphere, and the hydrosphere.

Answer:

false

Explanation:

Well, one must be serious about something, if one wants to have any amusement in life.The literary device used in this line is a(n):

A. understatement.
B. pun.
C. paradox.
D. epigram.

Answers

I think it's a paradox

Why can a heavy rain shower cause a large amount of erosion in a desert area

Answers

roots of trees and vegetation hold the earth together and prevent it from eroding

in the desert, there aren't as many roots to keep the sand/soil from moving so when it rains, te soil is free to move, it moves much more than in a forest or on a mountain.

There is a lack of vegetation to hold the soil in place.

Monohybrid Mice, i need help

Answers

Answer/Explanation:

See attached images showing the crosses on a Punnett square as well as the genotype and phenotypes of each cross.

I. Cross between a female Gg with a male gg (GG X gg):

1. Probability of getting gray offspring (Gg) = 2/4 (¼+ ¼) = ½

2. Probability of getting albino offspring (gg) = 2/4 (¼+ ¼) = ½

3. There are 2 possible genotypes among the offspring, which are Gg and gg.

4. There are 2 possible phenotypes among the offspring, which are gray and albino coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = 2/4 = ½

6. Probability of getting homozygous offspring (i.e. GG or gg) = Probability of getting GG + Probability of getting gg = ½ + 0 = ½

7. The color of the female that was crossed (i.e. Gg), is gray color. The allele for gray coat color (G) is dominant over the allele for albino coat color (g).

8. The color of the male (gg) that was crossed is albino. The recessive allele (g) for albino coat color, in its homozygous state would express itself in the absence of the dominant G allele for gray color.

II. Cross between homozygous gray female with a heterozygous male (GG X Gg):

1. Probability of getting gray offspring (GG or Gg) = 4/4 (i.e. ¼+ ¼ + ¼ + ¼ ) = 1

2. Probability of getting albino offspring (gg) = 0

3. There are only 2 possible genotypes among the offspring, which are GG and Gg.

4. There is only 1 possible phenotype among the offspring, which is gray coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = 2/4 (i.e. ¼+ ¼ ) = ½

6. Probability of getting homozygous offspring (i.e. GG or gg) = Probability of getting GG + Probability of getting gg = 0 + ½ = ½

7. The genotype of the female that was crossed is GG, given that the female is homozygous gray.

8. The male crossed is a heterozygous male (Gg), the male is gray.

III. Cross between a gray female, whose father was albino, with a heterozygous male (Gg X Gg):

We can make a good guess of the genotype of the female, given that gray color is dominant over albino, and the father was albino (gg). The father can only contribute sperm having only (g) allele, while the mother must contribute only a (G) allele to give a gray offspring. The gray female is definitely heterogyzous female i.e Gg

1. Probability of getting gray offspring (Gg or GG) = ¾ (½ + ¼)

2. Probability of getting albino offspring (gg) = ¼

3. There are 3 possible genotypes among the offspring, which are GG, Gg, and gg.

4. There are 2 possible phenotypes among the offspring, which are gray and albino coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = 2/4 = ½

6. Probability of getting homozygous offspring (i.e. GG or gg) = Probability of getting GG + Probability of getting gg = ¼ + ¼ = ½

7. The genotype of the female is Gg. We know this because we were given that it is gray in color, and gray is dominant over albino. Also, given that the father was albino (gg), a (g) allele can only be contributed by the father to combine with the dominant (G) allele to give us a female that has heterozygous gray coat color (Gg).

8. The genotype of the male is Gg. We know this because we were given that it was a heterozygous male. If an organism is heterozygous, it has different alleles controlling that trait.

IV. Cross between an albino female, whose father was gray, with a gray male, whose mother was albino (gg X Gg):

The albino female’s genotype is gg, because the g allele is recessive. The gray male’s genotype, whose mother was albino (gg) is definitely Gg, because gray is dominant, and to get a gray offspring, a G allele from the mother of the male must combine with the g allele that the albino father can only contribute i.e. Gg or GG from mother X gg from father = Gg (the gray male offspring).

1. Probability of getting gray offspring = ¼ + ¼ = ½

2. Probability of getting albino offspring (gg) = ¼ + ¼ = ½

3. There are 2 possible genotypes among the offspring, which are Gg, and gg.

4. There are 2 possible phenotypes among the offspring, which are gray and albino coat color.

5. Probability of getting heterozygous offspring (i.e. Gg) = ¼ + ¼ = ½

6. Probability of getting homozygous offspring (i.e. gg or GG) = ½ + 0 = ½

7. The genotype of the gray father of the albino female (gg) is Gg. Of the two possible genotypes of the gray father (i.e. GG or Gg), Gg is the most likely genotype to contribute the recessive g allele that would pair up with another g allele from the mother to give an albino female (gg), i.e. Gg (father) X Gg (Mother) or Gg (Father) X gg (Mother) = gg (albino female)

Final answer:

A monohybrid cross is a genetic cross that considers only one trait. Results from these crosses led to the concept of dominant and recessive traits and Mendel's Law of Segregation. Punnett squares visually present the likely outcomes of these crosses.

Explanation:

A monohybrid cross involves the mating of individuals who have two different alleles for a single trait. For example, Mendel ran several monohybrid crosses using pea plants. The trait being examined was the color of the pea—the parent plants had either green or yellow peas. After breeding a purebred yellow pea plant with a purebred green pea plant, all offspring were yellow, showing that yellow is the dominant trait and green the recessive.

Monohybrid crosses are useful tools in predicting the outcome of genetic crosses because they follow Mendel's Law of Segregation. According to this law, during the formation of reproductive cells, pairs of genetic traits separate, and offspring receive one factor from each parent.

A Punnett square is a tool that provides a visual representation of the possible combinations of genetic traits the offspring could inherit. For monohybrid crosses, a Punnett square will give a 3:1 ratio, representing the likelihood of the offspring expressing the dominant trait over the recessive trait, given that both parents are heterozygous.