If I had seventeen 1/3s of pizza how many full pizzas could I make and how many thirds would be left over?

Answers

Answer 1
Answer: You would make 5 full pizzas and there would be 2/3 left over!

Related Questions

PROVE: ((1+cosx)/sinx)+(sinx/cosx)=((cosx+1)/(sinx+cosx)). Idk what to do because I'm pretty sure the way I did it was wrong...
5 schools sent some students to a conference.One of the schools sent both boys and girls. This school sent 16 boys. The ratio of the number of boys it sent to the number of girls it sent was 1 : 2 The other 4 schools sent only girls. Each of the 5 schools sent the same number of students. Work out the total number of students sent to the conference by these 5 schools.
On field trips, there must be 2 chaperones for every 15 students. Which ratio correctly expresses the ratio of students to chaperones? 2:15 15:17 17:15 15:2
Find the coordinates of the midpoint of the segment given the endpoints p( -3,-7) and q (3, -5)
Determine whether the following problem involves a permutation or combination.​ (It is not necessary to solve the​ problem.) How many different 33​-letter passwords can be formed from the letters Upper QQ​, Upper RR​, Upper SS​, Upper TT​, Upper UU​, Upper VV​, and Upper WW if no repetition of letters is​ allowed?

The time it takes for an object stopped from a certain speed can be modeled by the equationt=1/2 square root v, where v is the speed of object in meters per second. if it takes 3 seconds for the object to stop, what is the speed of object in meters per second?

Answers

Given: 
t = 1/2 √v
v = speed of object meters per second

t = 3 seconds

3 = 1/2 √v
3 * 2 = √v
6 = √v
6² = √v²
36 meters = v

v = 36 meters per second

Define a function. Describe what the vertical line test is used for. Describe a real life situation that can be represented by a function.

Answers

A function is a relationship with a quantity (number). For example, if you made a table, and had one side be 1 2 3 4 5 (X axis) and then the y axis (other side) be 5, 10, 15, 20, 25, the function (rule) would be y= x5. The vertical line test is used to see if a graph has a function or not, so if it creates a vertical line on a graph, it has a function.
A real life situation would be miles per hour, so, for the x axis (hours) it said 1, and for the y axis (miles) it would be 60, this means in a duration of 1 hour you went 60 miles. Well, lets say you went 2 hours driving, the miles would be 120. 
For 3 hours, it would be 180. The function here is y= x60!
If you have any questions ask me!

Which one of the following is not equal to 100 meters? 0.100 kilometers 10 hectometers 10,000 centimeters 100,000 millimeters

Answers

Situation: Which one of the following is not equal to 100 meters?
We were given 4 different choices with corresponding values, not let's start finding the correct answer.
=> 0.100 kilometers
1 meter = 0.001 km 
100 meters = 0.1 km
=> 10 hectometers
1 meter = 0.01 hm
100 meters = 1 hm
=> 10,000 centimeters
1 meter = 100 centimeters
100 meters = 10 000 cm
=> 100,000 millimeters
1 meter = 1000 mm
100 meters = 100 000 mm
thus the not equal answer is hectometer

Final answer:

When converted to meters, 0.100 kilometers, 10,000 centimeters, and 100,000 millimeters all equal 100 meters. However, 10 hectometers equals 1000 meters, hence it does not equate to 100 meters.

Explanation:

The units you provided for comparison are 0.100 kilometers, 10 hectometers, 10,000 centimeters, and 100,000 millimeters. Let's convert them all to meters using the following metric conversions:

  • 1 kilometer = 1,000 meters
  • 1 hectometer = 100 meters
  • 1 centimeter = 0.01 meters
  • 1 millimeter = 0.001 meters

So, based on the metric conversions:

  • 0.100 kilometers = 100 meters
  • 10 hectometers = 1000 meters
  • 10,000 centimeters = 100 meters
  • 100,000 millimeters = 100 meters

As such, 10 hectometers does not equal 100 meters. Instead, it amounts to 1000 meters.

Learn more about Metric Conversions here:

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Which of the following represents the zeros of f(x) = x3 − 12x2 + 41x − 42?7, −3, 2
7, −3, −2
7, 3, 2
7, 3, −2

Answers

Given the polynomial function f(x)=x^3-12x^2+41x-42.

The integer zeros should be divisors of free term -42.

The divisors of -42 are:

\pm 1, \pm 2, \pm 3, \pm 6, \pm 7, \pm 14, \pm 21, \pm 42.

If some of these number is zero of f(x), then f takes 0 value at this point.

Check them:

f(1)=1^3-12\cdot 1^2 + 41\cdot 1-42=1-12+41-42=-12\neq 0;

f(-1)=(-1)^3-12\cdot (-1)^2 + 41\cdot (-1)-42=-1-12-41-42=-96\neq 0;

f(2)=2^3-12\cdot 2^2 + 41\cdot 2-42=8-48+82-42=0;

f(-2)=(-2)^3-12\cdot (-2)^2 + 41\cdot (-2)-42=-8-48-82-42=-180\neq 0;

f(3)=3^3-12\cdot 3^2 + 41\cdot 3-42=27-108+123-42=0;

f(-3)=(-3)^3-12\cdot (-3)^2 + 41\cdot (-3)-42=-27-108-123-42=-300\neq 0;

f(6)=6^3-12\cdot 6^2 + 41\cdot 6-42=216-432+246-42=-12\neq 0;

f(-6)=(-6)^3-12\cdot (-6)^2 + 41\cdot (-6)-42=-216-432-246-42=-936\neq 0;

f(7)=7^3-12\cdot 7^2 + 41\cdot 7-42=343-588+287-42=0.

Since the third degree polynomial function may have only 3 zeros, then you can end this process and state that zeros are 2, 3 and 7, because f(2)=0, f(3)=0 and f(7)=0.

Answer: correct choice is C

Answer: Zeroes are,

7, 3, 2

Step-by-step explanation:

Here, the given cubic equation,

f(x) = x^3 - 12x^2 + 41x - 42

Since, at x = 7,

f(7)=(7)^3-12* 7^2+41* 7 - 42 = 343 - 12* 49 +287 - 42 = 343 - 588 + 245=0

Thus, 7 is one of the zeroes of f(x),

⇒ x - 7 is a factor of f(x),

By the long division method ( shown below ),

We found that,

x^3 - 12x^2 + 41x - 42=(x-7)(x^2-5x+6)

=(x-7)(x^2-3x-2x+6) ( By middle term splitting )

=(x-7)(x(x-3)-2(x-3))

=(x-7)(x-3)(x-2)

For finding the zeroes, f(x) = 0,

(x-7)(x-3)(x-2)=0

⇒ x -7 =0 or x-3 =0 or x-2 =0

x = 7 or 3 or 2

Tran is solving the quadratic equation 2x2 – 4x – 3 = 0 by completing the square. His first four steps are shown in the table.

Answers

The following steps of solving for the roots of 2x² - 4x -3 = 0 were retrieved from another source Step 1 2x² - 4x = 3 Step 2 2(x² - 2x) = 3 Step 3 2(x² - 2x + 1) = 3 + 1 Step 4 2(x - 1)² = 4 From this, we can see that on Step 3, Tran made a mistake of adding 1 to 3. As we can see, 2(x² - 2x + 1) = 2x² - 4x + 2. That means, instead of adding 1, it should have been 2. Therefore, the step that Tran first made an error is Step 3.

How do you solve this rational equation
4/3(c+4) + 1 = 2c/c+4

Answers

4/3(c+4) + 1 = 2c/c+4 , where c is not -4 <=>
4 / [3(c + 4)] + 3( c + 4) /[ 3( c + 4)] = 6c / [3( c + 4)] <=>
4 + 3c + 12 = 6c <=>
16 = 3c <=>
c = 16 / 3.