MATHEMATICS COLLEGE

Suppose that the value of a stock varies each day from $12.82 to $33.17 witha uniform distribution.
Find the third quartile; 75% of all days the stock is below what value?

Answers

Answer 1

Answer:

Answer:

$28.08

Step-by-step explanation:

$33.17 - $12.82 = $20.35

75% of $20.35 = $15.26

$15.26 + $12.82 = $28.08

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I have a 1.5% chance of winning when spinning a roulette. Approximately how many times would I have to spin the roulette to win?

Answers

Answer:

66-67 times

Step-by-step explanation:

i would go with 67

you just divide 1.5 by a 100

There are 45 new houses being built in a neighborhood. Last month, 2/3 of them were sold. This month 2/5, of the remaining houses were sold. How many houses are left to be sold?

Answers

Answer: 9 houses

Step-by-step explanation:

Step 1:

Since 2/3 of the houses were sold last month, 1/3 of them were left.

45 * 1/3 = 15 houses left last month

Step 2:

Since 2/5 of the remaining houses were sold this month, 3/5 of them were left

15 * 3/5 = 9 houses left to be sold

there's your answer hope this helps :)

In addition to specificity, which training principle is included in the SPORT training strategy? 1) Progress 2) Tenacity 3) Retention 4) Overexertion

Answers

Answer:

PROGRESS

Step-by-step explanation:

16 1/9+ -4 2/3 help please??

Answers

Answer:

11 4/9

Step-by-step explanation:

ANDDD the answer is

Tyson and Ariana each invested $2,500 in separate accounts. Tyson’s interest rate is 5.75% and is compounded annually. Ariana’s simple interest rate is 5.75%. Neither will make any additional deposits or withdrawals. At the end of 6 years, how much more has Tyson earned? Round your answer to the nearest cent.

Answers

Answer:

Tyson's account will have $ 133.90 more than Ariana's account.

Step-by-step explanation:

In Tyson's case, he invests $ 2,500 in an account whose interest rate is 5.75% and is compounded annually. In turn, Ariana invests the same amount and for the same interest, but this is not compounded.

Thus, Ariana, at the end of her 6 years, will have a total amount in her account of $ 3,362.5 (((2,500 x 5.75 / 100) x 6) + 2,500), of which $ 862.5 will correspond to the interest generated.

Instead, Tyson's investment interests will be consolidated annually. Thus, in 6 years, this investment will evolve as follows:

-Year 1 --- 2,500 x 1.0575 = 2,643.75

-Year 2 --- 2,643.75 x 1.0575 = 2,795.76

-Year 3 --- 2,795.76 x 1.0575 = 2,956.52

-Year 4 --- 2,956.52 x 1.0575 = 3,126.52

-Year 5 --- 3,126.52 x 1.0575 = 3,306.29

-Year 6 --- 3,306.29 x 1.0575 = 3,496.40

Thus, at the end of the 6 years, Tyson will have $ 3,496.40 in his account. Thus, Tyson's account will have $ 133.90 more than Ariana's account.

The table shows the height of water in feet at different times. The water rises and falls in a cyclical pattern.A 2-column table with 5 rows. Column 1 is labeled x with entries 12 a m, 3 a m, 6 a m, 9 a m, 12 p m. Column 2 is labeled y with entries 6, 10, 6, 2, 6.

Which equation models the data in the table?

y = 6 sine (StartFraction pi Over 6 EndFraction x) + 2
y = 6 sine (StartFraction pi Over 6 EndFraction x) + 4
y = 4 sine (StartFraction pi Over 6 EndFraction x) + 6
y = 4 sine (StartFraction pi Over 6 EndFraction x) + 10

Answers

Modeling the data in the table is done via the equation y = 4 sine (pi/6x) + 6.

What is a cyclic pattern?

Over a period of years, a cyclical pattern recurs with considerable regularity. Cyclical patterns are distinct from seasonal patterns in that they last across a number of years as opposed to only one year for seasonal trends.

Given, The table shows the height of water in feet at different times. The water rises and falls in a cyclical pattern.

Table:

12 AM 6

3 AM 10

6 AM 6

9 AM 2

12 PM 6

from the general formula of wave

y = A sin(bx + c)

Substituting values in the equation from the graph attached below:

6 = A sin(0*b + c)......(1)

10 = A sin3b + c...(2)

6 = A sin6b + c......(3)

2 = A sin9b +c........(4)

Since -c/b is a phase shift of the graph

Thus

-c/b = 6

c = -6b

from equations 2 and 1

2* 6 = Asin(-3b) = -Asin3b

2 * 6 = Asin(-6b) = -Asin6b

2* 6/6 =sin6b/sin3b

1 = Cos3b

Thus b = π/6

from substitution in equations 3

6 = A sin6b + c

=> 6 = Asin 6* pi/6 + c

=> c = 6

$\begin{table}[]\begin{tabular}{ll}12 AM & 6 \n3 AM & 10 \n6 AM & 6 \n9 AM & 2 \n12 PM & 6 \end{tabular}\end{table}$ from substitution in equations 2