As viewed from a cliff 340 feet above sea level, a ship is 450 feet from the shore. What is the angle of depression from the cliff to the ship on the water below?

Answers

Answer 1
Answer: the angle of depression is equal to angle of elevation at ship
let m be the angle
tan m=340/450=0.76
therefore m=37.073 degrees



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What is the missing exponent?

(2^-5) ____= 2^-15

Answers

remmember
(x^m)^n=x^(mn)

(x^-5)^n=2^-15

-5 times n=-15
divide both sides by -5
n=3
(x^-5)^3=2^-15


answe is 3

A bicycle tyre has a diameter of 14 cm. John decides to cut the tube to see how long the rubber is.a. What is John trying to find? _____________________________________________
b. Calculate the circumference of the tyre.
c. If John should place the tyre on the ground and fill the space inside with paint, how much space would be occupied by the paint?

Answers

Answer:

A:He is trying to find the diameter

B: 3.14*14=43.96

C: 3.14*14^2=615.44

Hope This Helps!!!

In ∆MNP, m∠N = 90º, NH – altitude, m∠P = 21º, PM = 4 cm. Find MH.

Answers

Answer:

0.51 cm

Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

\sin \angle P=\frac{\text{Opposite leg}}{\text{Hypotenuse}}=(MN)/(MP)\n \nMN=MP\sin \angle P\n \nMN=4\sin 21^(\circ)\approx 1.43\ cm

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

\cos \angle M=\frac{\text{Adjacent leg}}{\text{Hypotenuse}}=(MH)/(MN)\n \nMH=MN\cos \angle M

In the right triangle, two acute angles are always complementary, so

m\angle M=90^(\circ)-m\angle P=90^(\circ)-21^(\circ)=69^(\circ)

Thus,

MH=1.43\cos 69^(\circ)\approx 0.51\ cm

Find the slope of the line between y = 1/8x -1

Answers

Answer:

x/8 -1

Step-by-step explanation:

. Write the equation in slope intercept form for the line that goes through point (−10, 8) with slope =6.

Answers

y = mx + b is slope intercept form

x = -10
y = 8
m = 6

1. Solve for b

8 = (6)(-10) + b
b = 68

2. Plug m and b back into your slope intercept equation

y = 6x + 68

The quantity n varies jointly with the product of z and the square of the sum of x and y. When n is 18, x = 2, y = 1, and z = 3. What is the constant of variation?

Answers

Answer:

Constant of variation is,(2)/(3)

Step-by-step explanation:

Joint Variation states that it is jointly proportional to a set of variables i.e, it means that z is directly proportional to each variable taken one at a time.

Given the statement: The quantity n varies jointly with the product of z and the square of the sum of x and y.

"The square of sum of x and y" means (x+y)^2

"Product of z and the square of the sum of  x and z" means z * (x+y)^2

then; by definition we have;

n \propto z * (x+y)^2

our equation will be of the form of:

n = k \cdot z(x+y)^2   ......[1] ; where k is constant of Variation.

Given: n =18 , x =2 , y= 1 and z = 3

Solve for k;

Substitute these given values in [1] we have;

18= k \cdot 3(2+1)^2

Simplify:

18= k \cdot 27

Divide both sides by 27 we get;

k = (18)/(27) = (2)/(3)

therefore, the constant of variation is, (2)/(3)

Hello,

n=k*z*(x+y)²
with n=18,x=2,y=1 and z=3
==>18=k*3*(2+1)²
==>k=18/27=2/3