Subtract.

3−(−5)−(−2)

Plot the solution on the number line.

Answers

Answer 1

Answer:

Answer: Its 10, so plot it on 10 in the number line

Step-by-step explanation: Since the subtraction signs cancel out, they make a addition sign. Henceforth its " 3+5+2" which would mean the sum is 10.

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Pleeease open the image and hellllp me

Answers

1. Rewrite the expression in terms of logarithms:

$y=x^x=e^(\ln x^x)=e^(x\ln x)$

Then differentiate with the chain rule (I'll use prime notation to save space; that is, the derivative of y is denoted y' )

$y'=e^(x\ln x)(x\ln x)'=x^x(x\ln x)'$

$y'=x^x(x'\ln x+x(\ln x)')$

$y'=x^x\left(\ln x+\frac xx\right)$

$y'=x^x(\ln x+1)$

2. Chain rule:

$y=\ln(\csc(3x))$

$y'=\frac1{\csc(3x)}(\csc(3x))'$

$y'=\sin(3x)\left(-\cot^2(3x)(3x)'\right)$

$y'=-3\sin(3x)\cot^2(3x)$

Since $\cot x=(\cos x)/(\sin x)$ , we can cancel one factor of sine:

$y'=-3(\cos^2(3x))/(\sin(3x))=-3\cos(3x)\cot(3x)$

3. Chain rule:

$y=e^{e^(\sin x)}$

$y'=e^{e^(\sin x)}\left(e^(\sin x)\right)'$

$y'=e^{e^(\sin x)}e^(\sin x)(\sin x)'$

$y'=e^{e^(\sin x)+\sin x}\cos x$

4. If you're like me and don't remember the rule for differentiating logarithms of bases not equal to e, you can use the change-of-base formula first:

$\log_2x=(\ln x)/(\ln2)$

Then

$(\log_2x)'=\left((\ln x)/(\ln 2)\right)'=\frac1{\ln 2}$

So we have

$y=\cos^2(\log_2x)$

$y'=2\cos(\log_2x)\left(\cos(\log_2x)\right)'$

$y'=2\cos(\log_2x)(-\sin(\log_2x))(\log_2x)'$

$y'=-\frac2{\ln2}\cos(\log_2x)\sin(\log_2x)$

and we can use the double angle identity and logarithm properties to condense this result:

$y'=-\frac1{\ln2}\sin(2\log_2x)=-\frac1{\ln2}\sin(\log_2x^2)$

5. Differentiate both sides:

$\left(x^2-y^2+\sin x\,e^y+\ln y\,x\right)'=0'$

$2x-2yy'+\cos x\,e^y+\sin x\,e^yy'+\frac{xy'}y+\ln y=0$

$-\left(2y-\sin x\,e^y-\frac xy\right)y'=-\left(2x+\cos x\,e^y+\ln y\right)$

$y'=(2x+\cos x\,e^y\ln y)/(2y-\sin x\,e^y-\frac xy)$

$y'=(2xy+\cos x\,ye^y\ln y)/(2y^2-\sin x\,ye^y-x)$

6. Same as with (5):

$\left(\sin(x^2+\tan y)+e^(x^3\sec y)+2x-y+2\right)'=0'$

$\cos(x^2+\tan y)(x^2+\tan y)'+e^(x^3\sec y)(x^3\sec y)'+2-y'=0$

$\cos(x^2+\tan y)(2x+\sec^2y y')+e^(x^3\sec y)(3x^2\sec y+x^3\sec y\tan y\,y')+2-y'=0$

$\left(\cos(x^2+\tan y)\sec^2y+x^3\sec y\tan y\,e^(x^3\sec y)-1\right)y'=-\left(2x\cos(x^2+\tan y)+3x^2\sec y\,e^(x^3\sec y)+2\right)$

$y'=-(2x\cos(x^2+\tan y)+3x^2\sec y\,e^(x^3\sec y)+2)/(\cos(x^2+\tan y)\sec^2y+x^3\sec y\tan y\,e^(x^3\sec y)-1)$

7. Looks like

$y=x^2-e^(2x)$

Compute the second derivative:

$y'=2x-2e^(2x)$

$y''=2-4e^(2x)$

Set this equal to 0 and solve for x :

$2-4e^(2x)=0$

$4e^(2x)=2$

$e^(2x)=\frac12$

$2x=\ln\frac12=-\ln2$

$x=-\frac{\ln2}2$

How many groups of 7 are in 21?

Answers

There are 3 groups of 7 in 21.

To find that divide 7 from 21

3. You would divide 7 by 21 and get 3

A basket of fruit contains 4 bananas, 3 apples, and 5 oranges. You intend to draw a piece of fruit from the basket, keep it, and then draw a 2nd piece of fruit from the basket. What is the probability of selecting two oranges in a row from the basket if you are blindfolded?

Answers

Answer: 5/33

Step-by-step explanation: There are 12 fruits and 5 are oranges.

If you draw an orange, then there are 11 fruits and 4 oranges. (5/12)x(4/11)=20/132 or 5/33 in simplest form.

Morningstar tracks the total return for a large number of mutual funds. The following tableshows the total return and the number of funds for four categories of mutual funds
(Morningstar Funds500, 2008).
Type of Fund
Domestic Equity
International Equity
Specialty Stock
Hybrid Number of Funds
9191
2621
1419
2900
Total Return (%)
4.65
18.15
11.36
6.75
a. Using the number of funds as weights, compute the weighted average total return for
the mutual funds covered by Morningstar.
b. Is there any difficulty associated with using the "number of funds" as the weights in
computing the weighted average total return for Morningstar in part (a)? Discuss. What
else might be used for weights?
c. Suppose you had invested $10,000 in mutual funds at the beginning of 2007 and
diversified the investment by placing $2000 in Domestic Equity funds, $4000 in International Equity funds, $3000 in Specialty Stock funds, and $1000 in Hybrid
funds. What is the expected return on the portfolio?

Answers

a. The weighted average total return for the mutual funds covered by Morningstar is 7.81%.

b. A better weight would be the total amount of money invested in each category.

c. The expected return on the portfolio is 12.273%.

a. To compute the weighted average total return for the mutual funds covered by Morningstar, we need to multiply the total return for each category by the number of funds in that category, sum the products, and divide by the total number of funds:

Weighted average total return = [(4.65 x 9191) + (18.15 x 2621) + (11.36 x 1419) + (6.75 x 2900)] / (9191 + 2621 + 1419 + 2900)

Weighted average total return = 7.81%

Therefore, the weighted average total return for the mutual funds covered by Morningstar is 7.81%.

b. Using the "number of funds" as weights in computing the weighted average total return for Morningstar may not be appropriate if the funds in each category have different sizes or investment amounts. In this case, a better weight would be the total amount of money invested in each category. Another possible weight could be the market capitalization of the companies in which the funds are invested.

c. To find the expected return on the portfolio, we need to multiply the amount invested in each category by the expected return for that category, sum the products, and divide by the total amount invested:

Expected return = [(0.2 x 4.65) + (0.4 x 18.15) + (0.3 x 11.36) + (0.1 x 6.75)] / (2000 + 4000 + 3000 + 1000)

Expected return = 12.273%

Therefore, the expected return on the portfolio is 12.273%.

To learn more about weighted averages;

brainly.com/question/35145315

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What is the distance between the points (-4, 7 ) and (2, 7 )

Answers

Answer:

Step-by-step explanation:

Since the y-value is the same, the two points make a horizontal line. You can think of it as a number line, where the first point is at -4 and the second is at 2. So, the distance between -4 and 2 is 6.

1) Two pieces of a pole arle cut into 5 inches each from an original pole that was 20 incheslong. What is the length of the remaining part of the 20 inch pole?
HELP Please