What is (24 times 25)50 50=?

Answers

Answer 1

Answer: the answer to this is 600

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The distance between Vancouver and Winnipeg is approximately 1850 km in a straight line. The distance on a map is 3.7 cm. Write a scale statement for the map. What scale factor was used to make the map.

Answers

3.7cm on the map represents 1850km in reality

3.7cm : 1850km

1cm : 1850/3.7 km

1cm : 500km

Scale statement for map is : 1cm : 500km.

That is 1cm on map represents 500km.

1cm : 500km. Recall 1km = 1000m = 100 000cm

1cm : 500* 100000cm

1cm : 50 000 000cm

1: 50 000 000.

Scale factor is 50 000 000.

Final answer:

The scale of the map is 1 cm : 500 km, meaning 1 cm on the map corresponds to an actual distance of 500 km on the ground. This is the scale factor used to create the map.

Explanation:

The scale of a map is a ratio that represents the relationship between the distance on the map and the actual distance on the ground. In this case, the actual distance between Vancouver and Winnipeg is 1850 km, while the distance on the map is 3.7 cm. Therefore, the scale of the map can be represented as 1 cm : 500 km (because 1850 km / 3.7 cm = approximately 500 km).

This means that 1 cm on the map represents an actual distance of 500 km on the ground, which is the scale factor used to create the map. Therefore, the scale statement for the map would be "1 cm on the map represents 500 km on the ground" or it can be written shorthand as 1:50,000,000 (considering 1 km = 1,000,000 cm).

Learn more about Map Scale here:

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Find the 50th term of 0,3,6,9....

Answers

Answer:

The 50th term is 147

Step-by-step explanation:

The nth term of an AP can be find as:

$a_n=a+(n-1)d$

Where, a is the first term, d is the common difference, n is the number of term and $a_n$ is the nth term.

Now consider the provided AP: 0,3,6,9...

Here, the first term is 0, common difference is 3 and n is 50.

Substitute a = 0, d = 3 and n =50 in above formula.

$a_(50)=0+(50-1)3$

$a_(50)=0+(49)3$

$a_(50)=147$

Hence, the 50th term is 147

147 is the fiftieth term just multiply 3 by 50 and subtract 3

The coordinates of the vertices of ANGLE PQR are P(-3,3), Q(2,3), and R(-3,-4). Find the side lengths to the nearest hundredth and the angle measures to the nearest degree.

Answers

Answer: PQ=5, QR=radical 61= 7.81, angle: 50degrees,Why:PQ=|-3|+2=5PR=6angle Alfa, so there is right angle triangle PQR so I can use following formula:PQ^2 + RP^2=QR^2;25 + 36=QR^2;QR=radical 61also I can use: sinus (angle)=PR/QR;sin(angle)=6/radical61=0.76822 which gives angle to be little bit more than 50 degrees{sinus 50 degrees=0,7660}.

Solve each of the following equations for x.a) 3x - 8 =29 b) 3 ( x - 8 ) = 28

c) 3 (x - 8) + 17 =29 d) 7x + 12 = 3x - 8

Answers

$3x - 8 =29 \n \n 3x = 29 + 8 \ / \ add \ 8 \ to \ each \ side \n \n 3x = 37 \ / \ simplify \n \n x = (37)/(3) \ / \ divide \ each \ side \ by \ 3 \n \n Answer: \fbox {x = 37/3} \ or \ \fbox {x = 12.3333}$

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$3 ( x - 8 ) = 28 \n \n x - 8 = (28)/(3) \ / \ divide\ each \ side \ by \ 3 \n \n x = (28)/(3) + 8 \ / \ add \ 8 \ to \ each \ side \n \n x = (52)/(3) \ / \ simplify \n \n Answer: \fbox {x = 52/3} \ or \ \fbox {x = 17.3333}$

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$3 (x - 8) + 17 =29 \n \n 3(x - 8) = 29 - 17 \ / \ subtract \ 17\ from \ each \ side \n \n 3(x - 8) = 12\ / \ simplify \n \n x - 8 = (12)/(3) \ / \ divide \ each \ side \ by \ 3 \n \n x - 8 = 4 \ / \ simplify \n \n x = 4 + 8 \ / \ add \ 8 \ to \ each \ side \n \n x = 12 \ / \ simplify \n \n Answer: \fbox {x = 12}$

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$7x + 12 = 3x - 8 \n \n 7x + 12 - 3x = -8 \ / \ subtract \ 3x \ from \ each \ side \n \n 4x + 12 = -8 \ / \ simplify \n \n 4x = -8 - 12 \ / \ subtract \ 12 \ from \ each \ side \n \n 4x = -20 \ / \ simplify \n \n x = - (20)/(4) \ / \ divide \ each \ side \ by \ 4 \n \n x = -5 \ / \ simplify \n \n Answer: \fbox {x = -5}$

given the equation of a circle x^2+y^2-10x+4y+13=0. find its center and radius. i am having trouble please help

Answers

$x^2+y^2-10x+4y+13=0\n x^2-10x+25+y^2+4y+4-16=0\n (x-5)^2+(y+2)^2=16\n\n \hbox{center}=(5,-2)\n r=4$

A candle manufacturer sells cylindrical candles in sets of three. Each candle in the set is a different size. The smallest candle has a radius of 0.5 inches and a height of 3 inches. The other two candles are scaled versions of the smallest, with scale factors of 2 and 3. How much wax is needed to create one set of candles? in cubic inches

Answers

To find out how much wax is needed for the candles we need to figure out the volume of each candle. We know radius r=0.5 inches and height h=3 inches of the smallest candle and we know that the middle candle has r2=2r=1 inch and h2=2h=6 inches and the biggest candle has r3=3r=1.5 inches and h3=3h=9 inches. So now we need the formula for volume: V=pi*r^2*h and we simply plug in the numbers. First candle is V=3.14*(0.5^2)*3=2.355 inches^3. Middle candle: V2=3.14*(1^2)*6=18.84 inches^3. Biggest candle: V3=3.14*(1.5^2)*9=63.585 inches^3. So overall wax needed to create all three candles is V+V2+V3=2.355 inches^3 + 18.84 inches^3 + 63.585 inches^3=84.78 inches^3.

Answer:

First candle is V=3.14*(0.5^2)*3=2.355 inches^3. Middle candle: V2=3.14*(1^2)*6=18.84 inches^3. Biggest candle: V3=3.14*(1.5^2)*9=63.585 inches^3. So overall wax needed to create all three candles is V+V2+V3=2.355 inches^3 + 18.84 inches^3 + 63.585 inches^3=84.78 inches^3.

Step-by-step explanation:

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