What is the use if having a control condition in an investigation​

Answers

Answer 1
Answer:

Answer:

Thus, including a control condition allows researchers to compare the way things are in the presence of an independent variable with the way things would have been in the absence of an independent variable.

Explanation:

Thus, including a control condition allows researchers to compare the way things are in the presence of an independent variable with the way things would have been in the absence of an independent variable.


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A beta particle is identical to _____ the nucleus of a helium atom an electron a proton a neutron

Answers

A beta particle is identical to : an electron

Both of beta particle and electron are high in energy and move in high speed.
hope this helps

A beta particle is identical to an electron  so A I think

What is the potential energy of a 30 Newton ball that is on the ground

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The potential energy of a 30N ball on the ground will be zero. With respect to height, h. Potential energy will be calculated like this. P=mgh. So if its on the ground relatively speaking the h=0. Thus inputting into the above formula. P=0.

A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (2.50 m, 2.50 m) with a velocity of -5.00i hat m/s and an acceleration of -10.0j m/s2. What are the coordinates of the center of the circular path?

Answers

Answer:

(2.5,0)

Explanation:

The particle can be described by the following equations:

x=Rsin(-\omega t)+2.5\ny=Rcos(-\omega t)\n(dx)/(dt)=-\omega Rcos(-\omega t)\n(dy)/(dt)=\omega Rsin(-\omega t)\n(d^2x)/(dt^2)=-\omega^2Rsin(-\omega t)\n(d^2y)/(dt^2)=-\omega^2Rcos(-\omega t)

For R = 2.5, ω = 2 and t = 0:

x=2.5\ny=2.5\n\n(dx)/(dt)=-5\n (d^2y)/(dt^2)=-10

The center of the circle would be at point (2.5,0)

Explain why dogs pant during hot summer days using the concept of evaporation?

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Dogs pant because they can't sweet out their heat so they pant it out (and drink water) to cool themselves down.

What is the new weight of a 10kg object on a planet that has twice the earths mass. (assume that the radius of the planet is the same as earths)

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Weight = (mass) x (acceleration of gravity) .

Acceleration of gravity on a planet's surface is proportional to

                         (planet's mass) / (planet's radius)² .

On Earth's surface, acceleration of gravity is 9.8 m/s² .

Weight of 10 kg mass = (10 kg) x (9.8 m/s²) = 98 newtons.

On the surface of a planet with twice the Earth's mass
all stuffed into the same radius, the acceleration of gravity
would be 19.6 m/s² ... double what it is on Earth.

Weight of 10 kg would be (10 kg) x (19.6 m/s²) = 196 newtons ...
double its Earth weight.

What is the power of 10 when 157,821 is written in scientific notation?

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Answer: The power of 10 in the given value is 5.

Explanation:

Scientific notation is defined as the representation in which a number is expressed in the decimal form. That means always written in the power of 10 form. The decimal place is put after 1 digit.

We are given a numerical value of 157,821

Converting this into scientific notation, we get:

157,821=1.57821* 10^5

Hence, the power of 10 in the given numerical value is 5.

1.57821 * 10^5 
so answer is 5