If you knew that f(-4)=8, then what (x,y) coordinate point must lie on the graph of y=f(x)?

Answers

Answer 1
Answer:

If we know that f(-4) = 8, then what (x, y) point must lie on the graph y = f(x)?.

The point is (-4, 8)

For a given function y = f(x), all the points (x, y) on the graph are of the form:

(x, y) = (x, f(x))

So if we know that:

f(-4) = 8

Then we know that the point:

(-4, f(-4))  = (-4, 8)

Must lie on the graph of y = f(x)

Then the correct answer is (-4, 8)

If you want to learn more, you can read:

brainly.com/question/17641264

Answer 2
Answer: I believe it would be (-4, 8); because when x = -4, y = f(x) = 8.

Related Questions

Solving eqations4c=16
Please do the area and perimeter and show your work!
Write all names that apply to 121/√121
What is the median? 34,71,45,21,88,53
In the las 30 school days, a school bus has been late 24 times. What is the unit rate of days the bus is late to total numbers of school days? And describe what this means in words.

Type of triangles Q. What does each type mean?
Write definition for each one and draw the triangle .
1) Right-angled triangle:



2) Acute:



3) Obtuse:

Answers

Answer:

right angle triangle 90 degrees

scute less than 90 degrees

obtuse over 90 degrees

Step-by-step explanation:

Here are the drawings

SOLVE BY SUBSTITUTION:3x-2y=14
y=5x
solve by substitution
x-2y=-2
y=2x+4
solve by elimination
x+2y=-7
x-5y=7
PLEASE HELP WORTH 10 POINTS! AKA SHOW WORK:)

Answers

1)
3x-2y=14
y=5x

So we plug in y=5x into 3x-2y=14

We get:

3x-2(5x)=14
3x -10x=14
-7x=14
x=-2

So we found x, now we need to find y. We can simply plug in x into the equation and get y.

y=5x
y=5(-2)
y=-10

So your answer will be (-2,-10).

2) 
x-2y= -2
y= 2x+4

Once again plug in y=2x+4 into x-2y=-2

x-2(2x+4) = -2
x-4x-8=-2
-3x-8=-2
-3x = 6
x= -2

Now we plug back in x and solve for y :)

y=2x+4
y=2(-2)+4
y=-4+4
y=0

So our solution would be (-2,0).

3)
x+2y=-7
x-5y=7

Multiply the second equation by -1

-x+5y=-7

Now add that equation with the other one:

   x+2y=-7
+
   -x+5y=-7
-----------------
7y=-14
y=-2

Now plug in y=-2 and solve for x

x+2y=-7
x+2(-2)=-7
x+(-4)=-7
x-4=-7
x=-3

So your solution would be (-3,-2).

1)

3x-2y=14\n \n y=5x

We know y's value. Let's plug it in the equation.

y=5x\n \n 3x-2\cdot (5x)=14\n \n 3x-10x=14\n \n -7x=14

Divide both sides by -7.

x=-2

Now we have x's value. Let's plug it in the equation to find y.

x=-2\n \n y=5x\n \n y=5\cdot -2\n \n y=-10

Solution,

(-2, -10)

2)
x-2y=-2\n \n y=2x+4

Again we have y's value. Let's plug and solve.

y=2x+4\n \n x-2\cdot (2x+4)=-2\n \n x-(2\cdot 2x+2\cdot 4)=-2\n \n x-4x-8=-2\n \n -3x-8=-2\n \n -3x=-2+8\n \n -3x=6\n \n x=\frac { 6 }{ -3 } \n \n x=-2

Now we have x's value let's solve for y.

x=-2\n \n y=2x+4\n \n y=2\cdot (-2)+4\n \n y=-4+4\n \n y=0

Solution,

(-2, 0)

3)

x+2y=-7\n \n x-5y=7

Let's first multiply the first equation by -1

-1\cdot (x+2y)=-1\cdot -7\n \n -x-2y=7

Then let's add these new equation and the second equation.

-1\cdot (x+2y)=-1\cdot -7\n \n -x-2y=7\n \n x-5y=7\n \n (-x-2y)+(x-5y)=7+7\n \n -x+x-2y-5y=14\n \n -7y=14\n \n y=\frac { 14 }{ -7 } \n \n y=-2

Now we have y's value let's plug it and solve for x.

y=-2\n \n x+2y=-7\n \n x+2\cdot (-2)=-7\n \n x-4=-7\n \n x=-7+4\n \n x=-3

Solution,

(-3, -2)


Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)3 tan(θ) sin(θ) − 2 tan(θ) = 0

Answers

Answer:

Note from question, Let K be any integer.  Integer = 1

θ = πk

  θ = 3.142 * 1

  θ = 3.142 in three decimal places

θ = sin⁻¹ (2/3) + 2kπ

   θ = sin⁻¹0.667 + 2*1*3.142

   θ = 0.718 + 6.284

   θ = 7.002 in three decimal places

7.002 , 3.142

Step-by-step explanation:

Considering the equation

3 tan(θ) sin(θ) − 2 tan(θ) = 0

The objective is to solve the equation.

First solve the equation in one period.

3 tan(θ) sin(θ) − 2 tan(θ) = 0

( 3sinθ − 2 ) tanθ = 0

Therefore, 3sinθ − 2 = 0    also   tanθ = 0

            =>  sinθ = 2/3        ,        tanθ = 0

Pick the right equation.

tanθ = 0

    θ = tan⁻¹ 0

    θ = 0

Using the unit circle, the period of tangent functions is π

Then the general solution of the equation is θ = 0 + πk ==> θ = πk

Pick the left equation.

3sinθ − 2 = 0

3sinθ = 2

sinθ = 2/3

    θ = sin⁻¹ (2/3)

As the sine function has period 2π

Then the general solution is θ = sin⁻¹ (2/3) + 2kπ

Which one is smallest to largest
0,5,-3,-7

Answers


-7, -3, 0 and then 5 would be the order from least to greatest.
-7 , -3 , 0 , 5 is the order from least to greatest

What is k+3 3/4 = 5 2/3 - 1 1/3

Answers

k+3 3/4=5 2/3-1 1/3
k+3 3/4=4 1/3
lets find the lcm first then multiply both sides by it but first change it to improper fraction
LCM is  12

[k+15/4]=[13/3]12
12k+45=52
12k=7
k=7/12

My decimal is seven-tenths greater than 46%

Answers

percent means parts out of 100
46%=46/100
7/10=70/100
7/10 more than 46%=70/100+46/100=116/100=1.16