An aqueous solution of lithium hydroxide contains hydroxide ions as the only negative ion in the solution. Lithium hydroxide is classified as an
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An Arrhenius acid refers to a component, which dissociates in water to produce hydrogen ions, or it can also be stated as that the acid enhances the concentration of hydrogen ions in an aqueous solution. On the other hand, an Arrhenius base refers to a component, which gets dissociate in water to produce hydroxide ions, or it can be said that a base enhances the concentration of hydroxide ions in an aqueous solution.
Therefore, an aqueous solution of lithium hydroxide comprising hydroxide ions as the sole negative ion in the solution is classified as an Arrhenius base.
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Kw = [ H₃O⁺] [ OH⁻]
1 x 10⁻¹⁴ = [ H₃O⁺] * 4 x 10⁻³
[H₃O⁺] = 1 x 10⁻¹⁴ / 4 x 10⁻³
[H₃O⁺] = 2.5 x 10⁻¹² M
hope this helps!
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Answer:
1.74845
Explanation:
We have the following reaction:
I2 + H2 => 2 HI
Now, the constant Kc, has the following formula:
Kc = [C] ^ c * [D] ^ d / [A] ^ a * [B] ^ b
In this case I2 is A, H2 is B and C is HI
We know that the values are:
H2 = 1 × 10 ^ -3 at 448 ° C
I2 = 2 × 10 ^ -3 at 448 ° C
HI = 1.87 × 10 ^ -3 at 448 ° C
Replacing:
Kc = [1.87 × 10 ^ -3] ^ 2 / {[2 × 10 ^ -3] ^ 1 * [1 × 10 ^ -3] ^ 1}
Kc = 1.87 ^ 2/2 * 1
Kc = 1.74845
Which means that at 448 ° C, Kc is equal to 1.74845
Answer:
Explanation:
[H2] = 10^-3
[I2] = 2*10^-3
[HI] = 0
in equilbiirum
[H2] = 10^-3 - x
[I2] = 2*10^-3 -x
[HI] = 0 + 2x
and we know
[HI] = 0 + 2x = 1.87*10^-3
x = ( 1.87*10^-3)/2 = 0.000935
then
[H2] = 10^-3 - 0.000935 = 0.000065
[I2] = 2*10^-3 -0.000935 = 0.001065
H₂ + I ⇄ 2 HI
Initially 1 × 10⁻³ 2 × 10⁻³
Change -9.35 × 10⁻⁴ -9.35 × 10⁻⁴ +1.87 × 10⁻³
At equil 6.5 × 10⁻⁵ 1.06 5 × 10⁻³ 1.87 × 10⁻³
HI increase by 1.87 × 10⁻³M
b. 3.46 mol
c. 31.2 mol
d. 52.0 mol
just the letter
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The number moles of carbon dioxide 31.2 moles will be produced when 10.4 mol of propane gas is burned in excess oxygen.
What is moles?
A mole would be the amount of a material that includes exactly 6.02214076 × of the particular chemical elementary constituents.
It is known that the formula of propane is .
The chemical reaction of propane.
+
→
It can be understand that, the ratio of propone and carbon di-oxide is 1:3.
The moles of propane = 10.4 mol
So, number of moles of = 10.4 mol × 3 =31.2 mol.
Therefore, the number of moles of carbon di-oxide will be 31.2
Hence, the correct answer will be option (C).
To know more about moles.
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Defined: To spend a hot, dry season in an inactive, dormant state, as certain reptiles, snails, insects, and small mammals.