MATHEMATICS HIGH SCHOOL

The function f(x)=60(1.5)xf(x)=60(1.5)x models an animal population after x years.How does the average rate of change between Years 3 and 6 compare to the average rate of change between Years 0 and 3?

The average rate of change is 1.5 times as fast.

The average rate of change is 3 times as fast.

The average rate of change is 3.375 times as fast.

The average rate of change is 2.25 times as fast.

Answers

Answer 1
Answer:

Answer:

The average rate of change is 3.375 times as fast.

Step-by-step explanation:

The given function is f(x)=60(1.5)^x

The average rate of change of a function f(x) is given by

(f(b)-f(a))/(b-a)

Thus,  average rate of change between Years 3 and 6 is given by

(f(6)-f(3))/(6-3)\n\n=(\left(60\left(1.5\right)^6-60\left(1.5\right)^3\right))/(3)\n\n=160.3125

Now, average rate of change between Years 0 and 3

(f(3)-f(0))/(3-0)\n\n(\left(60\left(1.5\right)^3-60\left(1.5\right)^0\right))/(3)\n\n=47.5

The ratio of these average rate of change is given by

=(160.3125)/(47.5)\n\n=3.375

Therefore, the average rate of change is 3.375 times as fast.
Answer 2
Answer: C.The average rate of change is 3.375 times as fast.You add them up and subract

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Answers

You have 2.50.
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he bought twice as many six cent stamps as ten cent stamps.
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Answers

5a^2 + 4ab \n \n gcf = a \n \n a( (5a^2)/(a) + (4ab)/(a) ) \n \n a(5a + 4b) \n \n

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Answers

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Answers

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Q-QP

Answers

alright, here it is
w=(q+p)/(q-pq)
factor out the q in the bottom part

w=(q+p)/[(q)(1-p)]
multiply both sides by q
wq=(q+p)/(1-p)
add 1 to both sides, but add (1-p)/(1-p) to the right side since that equals 1
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multiply both sdies by (1-p)
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divide both sdies by (wq+1)
1-p=(q+1)/(wq+1)
subtract 1 from both sdies
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multiply by -1
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Remove the extra parentheses.
w=q+p/q−qp

Since p is on the right-hand side of the equation switch the sides so it is on the left-hand side of the equation.
q+p/q−qp=w

Factor q out of q−qp. 
q+p/q⋅(1−1p)=w 

Rewrite −1p as −p. 
q+p/q⋅(1−p)=w 

Multiply q by 1−p to get q(1−p).
q+p/q(1−p)=w

Multiply each term in the equation by (1−p).
q+p/q(1−p)⋅(1−p)=w⋅(1−p) 

1+p/q=w−wp

Since −wp contains the variable to solve for, move it to the left-hand side of the equation by adding wp to both sides.
1+p/q+wp=w

Find the LCD of the terms in the equation.
It is q

Multiply each term in the equation by q in order to remove all the denominators from the equation.
p+wpq=−q+wq

Solve the equation.
p=q(w−1)/qw+1


Answer:
p=q(w−1)/qw+1

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Answers

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