PHYSICS HIGH SCHOOL

Which equation is used to calculate the amount of electrical energy used?a) E = t ÷ P

b) E = t – P

c) E = P + t

d) E = P × t

Answers

Answer 1

Answer:

Answer:

The equation of amount of electrical energy used $E = P* t$ .

d is correct option.

Explanation:

Electrical energy :

The electrical energy is the chemical energy which is consumed in the electric circuit.

Power :

Electric power is the rate at which energy is transferred from one part to another part of electric circuit.

The amount of electric energy is defined as,

The amount of electrical energy is the product of the power and time.

$E = P* t$

Where, E = energy transferred

P = Power

t = time

Hence, The equation of amount of electrical energy is used $E = P* t$ .

Answer 2

Answer: d
cause E=U and in power formula is p=U÷t or E÷t so E=p×t

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In a video game, a flying coconut moves at a constant velocity of 20 meters/second in the positive direction. The coconut hits an obstacle and moves in the opposite direction with a constant velocity of 10 meters/second. What’s the change in velocity of the coconut?

Answers

Answer:

30 negative is the change in velocty

Explanation:

Answer:-30 m/s

Explanation:

Each of us weighs a tiny bit less on the ground floor of a skyscraper than we do on the top floor. One reason for this is that _____. A. the gravitational field is shielded inside the building B. the mass of the building attracts you upward slightly C. both A and B D. none of the above

Answers

B. the mass of the building attracts you upward slightly

An 880 kg cannon at rest fires a 12.4 kg cannonball forward at 540 m/s. What is the recoil velocity of the cannon? (Unit m/s)

Answers

Answer:

The recoil velocity vector of the cannon is $(7.609,0,0)(m)/(s)$

Explanation:

We can solve this problem by applying the Momentum Conservation Principle.

The principle of conservation of momentum states that when you have an isolated system with no external forces, we can use the following equation to calculate the final velocity of one object.

$m1.v1=m2.v2$ (I)

Where '' $m1$ '' and '' $v1$ '' are the mass and velocity of the first object.

And where '' $m2$ '' and '' $v2$ '' are the mass and velocity of the second object.

The momentum is a vectorial magnitude.

If we use the equation (I) with the data given :

$(880kg).v1=(12.4kg).(540(m)/(s))$

$v1=7.609(m)/(s)$

If we considered as negative the sense of the velocity vector from the cannonball, the cannon's velocity vector will have the same direction but opposite sense that the cannonball's velocity vector (It will be positive).

We can give it a vectorial character like this :

$v1=(7.609,0,0)(m)/(s)$

The velocity vector will be entirely in the x-axis.

Answer:

7.61 m/s backwards

Explanation:

Initial momentum = final momentum

0 = (880 kg) v + (12.4 kg) (540 m/s)

v = -7.61 m/s

The cannon's recoil is 7.61 m/s backwards.

As current flows through a series circuit, it is diminished by the work it performs in the resistance(s). TRUE or FALSE

Answers

As current flows through a series circuit, it is diminished by the work it performs in the resistance(s). TRUE or FALSE

The statement “As current flows through a series circuit, it is diminished by the work it performs in the resistance(s)” is true.

A 4-kilogram ball moving at 8 m/sec to the right collides with a 1-kilogram ball at rest. After the collision, the 4-kilogram ball moves at 4.8 m/sec to the right. What is the velocity of the 1-kilogram ball?

Answers

Conservation of momentum: total momentum before = total momentum after

Momentum = mass x velocity

So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32

Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32

Therefore β = 12.8 m/s

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