The cost of $500,000 worth of 20-year term life insurance for Derek is $96.21 per month. If Derek's employer covers 85% of this cost, how much is deducted from Derek's gross income per year for life insurance?

Answers

Answer 1
Answer: Alright, the first thing we should have to do is find the total cost per year of his insurance. To do that, we multiply $96.21 by the 12 months in a year to get $1154.52. This is the cost of his insurance per year.

Next, we need to find out how much his boss covers, which we know is 85% of the total cost. SO what we can do is multiply the yearly cost ($1154.52) by the percent his boss covers (.85) to get $981.342. This is how much his boss covers per year.

Lastly, to find out how much Derek pays for insurance yearly, we just need to subtract how much his boss pays ($981.342) from the total yearly cost  ($1154.52), which leaves us with $173.178, which is how much Derek pays yearly for his insurance, which should be your answer.


Answer 2
Answer:

Final answer:

Derek pays 15% of the yearly cost of his life insurance, which amounts to $173.18 per year.

Explanation:

The total cost of Derek's life insurance for a year is calculated by multiplying the monthly fee by the number of months in a year (i.e. $96.21 x 12 = $1154.52). As Derek's employer is covering 85% of the cost, Derek is responsible for the remaining 15%. Therefore, the yearly cost deducted from Derek's gross income would be $1154.52 x 15% = $173.18. It's crucial to understand that these costs can vary depending on the insurance coverage, the employee benefits provided by the employer, and the individual's income.

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What does
1/2 and 2/8 =

Answers

(1)/(2) + (2)/(8) = (1 * 4)/(2 * 4) + (2)/(8) = (4)/(8) + (2)/(8) = (6)/(8) = (3)/(4)

There are 3 times as many used bikes in the showroom as there as new bikes. There are 164 bikes total in the showroom. How many new bikes are in the showroom

Answers

Number of new bike in showroom is 41 bikes.

Given that;

Total number of bikes in showroom = 164 bikes

3 times Number of new bike = Number of old bikes

Find:

Number of new bikes in showroom

Computation:

Assume;

Number of new bike = a

So,

Number of old bike = 3a

So,

a + 3a = 164

4a = 164

a = 41

So,

Number of new bike = 41

Learn more:

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Answer:

41

Step-by-step explanation:

There are 3 times as many used bike as new bike.  For the problem to work you have to include the used bikes and the new bikes.  So you divide 164 by 4 instead of three.

So 164/3=41

Find the range of f(x) = 3x - 5 for the domain {-1.5, 2, 4}A) {-8, 10, -1, -1}
B) {-9.5, 1, 7}
C) {8, 10, 1, 1}
D) {9.5, -1, -7}

Answers

For this case we have the following function:

f (x) = 3x - 5

To find the values of the range of the function, we substitute the values of the domain.

We have then:

For x = -1.5:

f (x) = 3 (-1.5) - 5\nf (x) = -4.5 - 5\nf (x) = -9.5

For x = 2:

f (x) = 3 (2) - 5\nf (x) = 6 - 5\nf (x) = 1

For x = 4:

f (x) = 3 (4) - 5\nf (x) = 12 - 5\nf (x) = 7

Therefore, the values of the range are given by:

{-9.5, 1, 7}

Answer:

the range of f (x) = 3x - 5 for the domain {-1.5, 2, 4} is:

B) {-9.5, 1, 7}

B is the answer

Because A and C could not be since the set have 4 results

D could not be because f(4)=. 12-5=7 not -7

What is 5x -2=38
A 36
B 8
C 7
D 13

Answers

move constant over (5x=38+2), combine terms (5x=40), divide both sides by 5 (x=8)

156 inches = how many yards and how many feet

Answers

yards=4.33 repeating 
foot=13 
156 inches equals 13 feet, or 4.333 yards
Hope I helped!

There are 12 inches in each foot, and 156/12=13.
There are 36 inches in each yard, and 156/36=4.333

Brooke has set up 70 chairs in equal rows for the class talent show.But,there is not room for more than 20 rows. What are the possible number of rows that brooke could set up?

Answers

She can not fit more than twenty rows in the class so anything equal to twenty or less (not including zero or negative numbers) would be fine. We don't have a limit for how many chairs in a row so I'm answering assuming that is not a problem so 20,19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2, or 1 row(s) would be possible