HELP PLEASE???? A walking path across a park is represented by the equation y = –4x + 10. A new path will be built perpendicular to this path. The paths will intersect at the point (4, –6). Identify the equation that represents the new path.

Answers

Answer 1

Answer: If you are given a linear equation and you are trying to find a line perpendicular to that line, you do the negative-reciprocal to your slope. What this means is you flip your slope into a fraction and multiply it by -1. So our slope is -4, so the negative reciprocal is $(1)/(4)$ .

Given our slope is 1/4, we can solve for the line by substituting our given points into point-slope form. So

-6 = (1/4)*4 + b
-6 = 1 + b
-7 = b

So our equation is:

y = (1/4)x -7

So our answer is C
Hopes this helps!

Answer 2

Answer:

Answer:

C. y = 1/4x - 7

Step-by-step explanation:

With perpendicular lines you have to flip

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A bag contains 5 red, 5 blue, 4 green, and 2 yellow marbles. What are the odds of drawing a red marble? *1 point
1:1
5:11
1:3
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Answers

Answer:

5:11

Step-by-step explanation:

you would say 5 marbles to the amount of the other marbles you have which would be 11

Consider the graph of f(x) = 2x 3 – 3x 2 – 14x. On a coordinate plane, a graph increases through (negative 2, 0) to (negative 1, 10), decreases through (0, 0) to (2, negative 24), and then increases through (3.5, 0) through (4, 20). Based on the graph, what is the solution to 2x 3 – 3x 2 ≥ 14x?

Answers

Answer:

Answer D

Step-by-step explanation:

Final answer:

The solution to the inequality 2x³ – 3x² – 14x ≥ 0, as indicated by the graph provided, is given by the intervals of x where the function is increasing. Therefore, the solution is comprised of the intervals [-2, -1] and [3.5, ∞].

Explanation:

The solution to 2x³ – 3x² ≥ 14x can be found by solving the inequality. First, let's rearrange the inequality to: 2x³ – 3x² – 14x ≥ 0. This equation represents where the function is positive (above the x-axis) on the graph. Therefore, we must identify the intervals of x where the function increases or decreases.

Based on the description of the graph, the function increases in the intervals (-2, -1) and (3.5, ∞) and decreases in the interval (-1, 3.5). So, the solution to the inequality would be the union of the intervals where the function increases: [-2, -1] U [3.5, ∞].

Learn more about Inequalities here:

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Complete the synthetic division to find the quotient of 3x^3-25x^2+12x-32 and x-8

Answers

Answer:

Explanation:

Hey there!

Please see your required solution in picture.

Quotient Q(X) = 3x²-x+4

Hope it helps!

Answer:

see image

Step-by-step explanation:

Plato/Edmentum

Find the diagonal of a square with a perimeter of 28 inches

Answers

Perimeter of a square = 4 x the length of one side = 28 in.
Length of one side = 7 in.
Length of the diagonal = square root of (7² + 7²) = 7√2 = 9.899 in (rounded)

$a-side\ of\ square\n\nperimeter\ is\ 28in\n\n4a=28\ \ \ \ /:4\na=7\ (in)\n\nThe\ diagonal\ (d)\ equal\ a\sqrt2\n\nd=7\sqrt2\ inches.$

Find the GCF of the given polynomial.

16a4b4 + 32a3b5 - 48a2b6

Answers

16a^4b^4 + 32a^3b^5 - 48a^2b^6

the GCF would be : 16a^2b^4....because the 16 is the highest coefficient that goes into 16,32,and 48. Then u just take the a with the smallest exponent and the b with the smallest exponent.

Simple.....

once you factor the expression completely you should get...

$16a^(2) b^(4) (a-b)(a+3b)$ ------> $16a^(2) b^(4)$ is your GCF.

Thus, your answer.

Find the quadratic equation whose roots are 3+- i / 2

Answers

(x - root#1) times (x - root#2) = 0 . . . . . This is how to BUILD the quadratic equation.

All the rest is just multiplying out that first line:

(x- (3+i/2)) times (x - (3-i/2)) = 0

x² -x(3-i/2) -x(3+i/2) + (3+i/2)(3-i/2) = 0

x² -3x + ix/2 -3x - ix/2 + 9 -3i/2 + 3i/2 = 0

x² -6x +9 = 0 There it is. That's your quadratic equation.

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