COMPUTERS AND TECHNOLOGY HIGH SCHOOL

What is the exact number of bits in a memory that contains (a. 96k bits (
b. 640m bits, and (
c. 4g bits?

Answers

Answer 1
Answer:

The exact number of bits in a memory contained in the given sizes of data are;

A) 96K Bits = 98,304 bits

B) 640m bits = 671,088,640 bits

C) 4g bits = 4,294,967,296 bits

From conversion tables, we know that;

1K bit= 1024 bits

1m bit = 1024² bits

1g bit = 1024³ bits

Thus, applying those conversion factors to our question gives;

A) 96K Bits

Converting to bits gives; 96 × 1024

⇒ 98,304 bits

B) 640m bits

Converting to bits gives; 640 × 1024²

⇒ 671,088,640 bits

C) 4g bits;

Converting to bits gives; 4 × 1024³

⇒ 4,294,967,296 bits

Read more at; brainly.com/question/22650206
Answer 2
Answer: 4 bits = a nibble
2 nibbles = a byte
Therefore, 8 bits are on a byte.
1024 bytes = 1 KB
1024 KBs = 1 MB
1024MB = 1 GB

a) 96KB
96 x 1024
=98304x8
=786432bits

b) 640MB
640x1024
=655360x1024
=671088640x8
=5368709120 bits

c) 4GB
4x1024
=4096x1024
=4194304x1024
=4294967296x8
=34359738368 bits

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Answers

Explanation:

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Final answer:

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Explanation:

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Answers

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