Find the inverse function of h(x) = - 2/3x + 6. h -1(x) = -x + 9 h -1(x) = -x - 6 h -1(x) = -x + 9 h -1(x) = -x - 6

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Answer 1

Answer: I hope this helps you

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Evaluate the function f(x)=3x+12 with x+6. f(x+6) = 6x + 60 f(x+6) = 2x - 30 f(x+6) = 3x + 30 f(x+6) = 30
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In Bear Creek Bay in July, high tide is at 1:00 pm. The water level at high tide is 7 feet at high tide and 1 foot at low tide. Assuming the next high tide is exactly 12 hours later and the height of the water can be modeled by a cosine curve, find an equation for Bear Creek Bay's water level in July as a function of time (t).

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Final answer:

The equation for Bear Creek Bay's water level in July as a function of time (t) is h = 3*cos(2*pi*t/12) + 4.

Explanation:

To find an equation for Bear Creek Bay's water level in July as a function of time (t), we can use a cosine curve since the height of the water can be modeled by it.

Based on the given information, we know that the water level is 7 feet at high tide and 1 foot at low tide. We also know that the next high tide is exactly 12 hours later.

Using the cosine function, where the amplitude (A) is (7 - 1)/2 = 3 and the period (T) is 12 hours, the equation for Bear Creek Bay's water level (h) as a function of time (t) is:

h = 3*cos(2*pi*t/12) + 4

Learn more about Equation for water level in Bear Creek Bay in July here:

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Based on the diagram, which statement is NOT true

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Answer:

Where's the diagram?.....

Solve for x: x to the negative 3rd power is equal to 27 over 64

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Remember what a negative exponent means ... it's just a positive exponent
in the denominator of a fraction. 'x' to negative 3rd power is the same as 1/x³ .

1/x³ = 27/64

Take the reciprocal of each side:

x³ = 64/27

x= ∛64/27 = ∛64 / ∛27.

64 is the perfect cube of 4.
27 is the perfect cube of 3.

x = 4/3 .

1. 360 miles in 6 hours

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Answer:

60mph

Step-by-step explanation:

Polygons ABCD and EFGH are similar. What is the perimeter of EFGH?

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If polygons ABCD and EFGH are similar, then their perimeters most likely are also similar. Polygon EFGH also have the same perimeter with polygon ABCD. Having similar polygons is referred as congruent polygons. Two figures are said to be congruent when they have the same shape and size or if one object is a mirror image of the other object.

Find the missing value of a triangle one leg is 12 and the long side is 20 what is the other leg?

Answers

Simple,

using the Pythagorean Theorem...

$a^(2) + b^(2) = c^(2)$

You have the hypotenuse (C) and one of the legs (A)

So, plug in what you know...

$12^(2)+ b^(2) = 20^(2)$

144+ $b^(2)$ =400

Now,isolate $b^(2)$

$144+ b^(2) =400$
-144 -144

Leaving you with...

$b^(2) =256$

So, now, $√(256)$ , to find what b is..

b=16

Thus, your answer.

IF this is a 'right' triangle, then we can calculate an answer.
If it's NOT a right triangle, then no answer is possible.

I'm going to assume that it's a right triangle, because you did say
that one 'leg' is 12, and you want the length of the other 'leg'. It's
common to refer to the two short sides of a right triangle as 'legs'.

In "Tales of Pythagoras", we learned that in a right triangle ...

(Longest side)² = (one leg)² + (the other leg)²

In your triangle ...

   (20)²       = (12)² + (the other leg)²

      (400)    = (144) + (the other leg)²

Subtract 144 from each side: (The other leg)² = (400 - 144) = 256

   The other leg    = √256 = 16 .

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