If an organism had 200 atoms of carbon-14 at death, how many atoms will be present after 14,325 years? Round the answer to the nearest hundredth.

Answers

Answer 1

Answer:

Answer:

35.34 atoms will be present after 14,325 years.

Step-by-step explanation:

Given : Carbon-14 has a half-life of approximately 5,730 years. This exponential decay can be modeled with the function N(t) = N0. If an organism had 200 atoms of carbon-14 at death.

To find : How many atoms will be present after 14,325 years?

Solution :

The half-life exponential function modeled is $N=N_o((1)/(2))^{(t)/(h)}$

Where, $N_o=200$ is the initial atoms

N is the total number of atoms.

t=14,325 years is the time

h=5,730 years is the half-life time

Substitute the value in the formula,

$N=200((1)/(2))^{(14325)/(5730)}$

$N=200((1)/(2))^(2.5)$

$N=200(0.1767)$

$N=35.34$

Therefore, 35.34 atoms will be present after 14,325 years.

Answer 2

Answer:

Answer:

35.36 atoms

Step-by-step explanation:

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Answers

Answer:

$600

Step-by-step explanation:

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Answers

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Answers

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Since we cannot have a negative answer, we must cancel out the other answer, which I did not include.

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~Cam943, Junior Moderator

l×b=area
l=2+3b
2+3b ×b=165
3b²=163
b²=54.3
b=√54.3
b=7.37 or 7.4=7
b=7ft
l=2+3(7.4)
l=2+ 22.2
l=24.2=24
l=24ft

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Answers

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