CHEMISTRY HIGH SCHOOL

Which change occurs during a nuclear fission reaction? (1) Covalent bonds are converted to ionic bonds.
(2) Isotopes are converted to isomers.
(3) Temperature is converted to mass.
(4) Matter is converted to energy

Answers

Answer 1

Answer:

Answer;

Matter is converted to energy

Explanation;

Nuclear fission is a type of nuclear reaction in which a nuclei of an atom splits or breaks down into two or more smaller nuclei.
It involves subdivision of heavy nucleus of an atom such as Uranium into two or more fragments which has almost the same equal mass.
Nuclear fission is accompanied by release of large amount of energy, thus we can say that matter is converted to energy.

Answer 2

Answer: Matter is converted to energy

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There are three stable atoms of Argon (Atomic Number 18): Argon-36, Argon-38 andArgon-40. What would the atoms of these isotopes have in common? What would be different about their atoms? (4 points) HELP ASAP
Which statement describes what occurs as two atoms of bromine combine to become a molecule of bromine?(1) Energy is absorbed as a bond is formed.(2) Energy is absorbed as a bond is broken.(3) Energy is released as a bond is formed.(4) Energy is released as a bond is broken.
The tetragonal crystal system below possesses how many faces?2 faces 4 faces 6 faces 8 faces
When placed in a freezer, liquid water turns into solid ice. What best describes this change?The water molecules slow down, bonds are broken, and the separated atoms spread out. The water molecules slow down, stronger attractions form between them, and the molecules stop flowing around. The water molecules speed up, attractions between them become weaker, and the molecules spread out. The water molecules speed up, new bonds are formed, and the new molecules are pulled closer together.

In an exothermic reaction, an increase in temperature favors the formation of products. a. True
b. False?

Answers

False, in an exothermic reaction, an increase in temperature does not favor the formation of products. Instead, it favors the backward reaction. An exothermic reaction is a reaction where energy is transferred from the system out to the environment.

Answer:

The correct answer is option b.

Explanation:

Exothermic reactions are defined as the reactions in which energy of reactants is more than the energy of the products. In these reactions, energy is released by the system. The total enthalpy of the reaction $(\Delta H)$ comes out to be negative.

In these reaction , products are favored when temperature is kept low. And when we allow these reaction to take place at higher temperature they favor reactant side.

Endothermic reactions are defined as the reactions in which energy of products is more than the energy of the reactants. In these reactions, energy is absorbed by the system. The total enthalpy of the reaction $(\Delta H)$ comes out to be positive.

Speed of sound is greater in aluminum or steel quora . True or False

Answers

Answer:

False.

Explanation:

False. The speed of sound is greater in aluminum than in steel.

Matter is anything that has what?

Answers

Matter is anything that has mass and occupies space.

Anything that has physical or real existence is matter. Everything that exists in the known universe manifests itself as matter or energy.
Matter can be liquid, solid or gaseous. Examples of raw: paper, wood, air, water, stone.

Matter is anything that has mass and occupies space.

What is matter?

In science, matter is anything that has mass and occupies space. This means that matter has volume and mass.

Matter is made up of tiny particles called atoms. Atoms are the basic building blocks of matter. They are the smallest units of matter that can exist independently.

The properties of matter are determined by the composition of the atoms that make up the matter. For example, the boiling point of a liquid is determined by the strength of the intermolecular forces between the molecules of the liquid.

Learn about matter here brainly.com/question/3998772

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Which of the following is the most electronegative element? a. He
b. I
c. N
d. O
e. C

Answers

none of these; the most electronegative element is fluorine because an atom of fluorine needs an additional electron to join it's outer membrane, so the atom can achieve stability.

a flourine atom on its own is always a negative ion.

Erythrocytes, neurons, skeletal cells, and columnar cells are examples of _____ cells.plant
bacterial
immunity
specialized

Answers

Erythrocytes, neurons, skeletal cells, and columnar cells are examples of specialized cells. All these cells have differentiated from embryonic stem cells and specialized for different functions. Therefore, they are specialized cells. They have specific structures that allow them to perform their specialized functions.

the answer is SPECIALIZED

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An equilibrium mixture contains 0.600 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the reactants (carbon monoxide and water vapor) in a 1.00-L container. This is the equation: CO(g)+H2O(g)--><-- CO2(g) + H2(g). How many moles of carbon dioxide would have to be added at constant temperature and volume to increase the amount of carbon monoxide to 0.300 mol?

Answers

Answer : The moles of $CO_2$ added will be 1.12 mole.

Solution : Given,

Moles of $CO$ and $H_2O$ at equilibrium = 0.200 mol

Moles of $CO_2$ and $H_2$ at equilibrium = 0.600 mol

First we have to calculate the concentration of $CO,H_2O,CO_2\text{ and }H_2$ at equilibrium.

$\text{Concentration of }CO=(Moles)/(Volume)=(0.200mol)/(1L)=0.200M$

$\text{Concentration of }H_2O=(Moles)/(Volume)=(0.200mol)/(1L)=0.200M$

$\text{Concentration of }CO_2=(Moles)/(Volume)=(0.600mol)/(1L)=0.600M$

$\text{Concentration of }H_2=(Moles)/(Volume)=(0.600mol)/(1L)=0.600M$

Now we have to calculate the value of equilibrium constant.

The given equilibrium reaction is,

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

The expression of $K_c$ will be,

$K_c=([H_2][CO_2])/([CO][H_2O])$

$K_c=((0.600)* (0.600))/((0.200)* (0.200))$

$K_c=9$

Now we have to calculate the moles of $CO_2$ added.

Let the moles of $CO_2$ added is 'x'.

The given equilibrium reaction is,

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

Initially 0.200 0.200 0.600 0.600

Added moles 0 0 x 0

Change +0.1 +0.1 -0.1 -0.1

Final 0.3 0.3 (0.5+x) 0.5

The expression of $K_c$ will be,

$K_c=([H_2][CO_2])/([CO][H_2O])$

$9=((0.5)* (0.5+x))/((0.3)* (0.3))$

$x=1.12mol$

Therefore, the moles of $CO_2$ added will be 1.12 mole.

$\boxed{0.{\text{3 mol}}}$ of ${\text{C}}{{\text{O}}_{\text{2}}}$ are added at constant temperature and volume to increase the amount of carbon monoxide to 0.300 mol.

Further Explanation:

Chemical equilibrium is the state in which the concentration of reactants and products become constant and do not change with time. This is because the rate of forward and backward direction becomes equal. The general equilibrium reaction is as follows:

${\text{P(g)}} + {\text{Q(g)}} \rightleftharpoons {\text{R(g)}} + {\text{S(g)}}$

Equilibrium constant is the constant that relates to the concentration of product and reactant at equilibrium. The formula to calculate the equilibrium constant for the general reaction is as follows:

${\text{K}}=\frac{{\left[ {\text{R}}\right]\left[ {\text{S}}\right]}}{{\left[{\text{P}} \right]\left[ {\text{Q}} \right]}}$

Here,

K is the equilibrium constant.

P and Q are the reactants.

R and S are the products.

The given reaction is as follows:

${\text{CO}}\left(g\right) + {{\text{H}}_2}{\text{O}}\left( g \right)\rightleftharpoons {\text{C}}{{\text{O}}_2}\left( g \right) + {{\text{H}}_2}\left( g \right)$

The expression for the equilibrium constant for the given reaction is as follows:

${\text{K = }}\frac{{\left[ {{\text{C}}{{\text{O}}_{\text{2}}}} \right]\left[ {{{\text{H}}_{\text{2}}}} \right]}}{{\left[ {{\text{CO}}} \right]\left[ {{{\text{H}}_2}{\text{O}}}\right]}}$ ......(1)

Here,

K is the equilibrium constant.

$\left[ {{\text{C}}{{\text{O}}_{\text{2}}}} \right]$ is the concentration of carbon dioxide.

$\left[{{{\text{H}}_{\text{2}}}} \right]$ is the concentration of hydrogen.

$\left[ {{\text{CO}}}\right]$ is the concentration of carbon monoxide.

$\left[ {{{\text{H}}_2}{\text{O}}}\right]$ is the concentration of water.

Substitute 0.600 mol/L for $\left[ {{\text{C}}{{\text{O}}_{\text{2}}}} \right]$ , 0.600 mol/L for $\left[ {{{\text{H}}_{\text{2}}}} \right]$ , 0.200 mol/L for $\left[ {{\text{CO}}}\right]$ and 0.200 mol/L for $\left[ {{{\text{H}}_2}{\text{O}}} \right]$ in equation (1).

$\begin{aligned}{\text{K }}&=\frac{{\left( {{\text{0}}{\text{.600 mol/L}}}\right)\left( {{\text{0}}{\text{.600 mol/L}}}\right)}}{{\left( {{\text{0}}{\text{.200 mol/L}}}\right)\left( {{\text{0}}{\text{.200 mol/L}}}\right)}}\n&= 9\n\end{aligned}$

The value of equilibrium constant comes out to be 9 and it remains the same for the given reaction.

Rearrange equation (1) to calculate .

$\left[{{\text{C}}{{\text{O}}_{\text{2}}}} \right]=\frac{{{\text{K}}\left( {\left[ {{\text{CO}}} \right]\left[ {{{\text{H}}_2}{\text{O}}} \right]} \right)}}{{\left[ {{{\text{H}}_{\text{2}}}} \right]}}$ ......(2)

Substitute 9 for K, 0.300 mol/L for $\left[{{\text{CO}}}\right]$ , 0.200 mol/L for $\left[{{{\text{H}}_2}{\text{O}}}\right]$ and 0.600 mol/L for $\left[ {{{\text{H}}_{\text{2}}}}\right]$ in equation (2).

$\begin{aligned}\left[ {{\text{C}}{{\text{O}}_{\text{2}}}} \right]&=\frac{{{\text{9}}\left( {{\text{0}}{\text{.300 mol/L}}} \right)\left( {{\text{0}}{\text{.200 mol/L}}} \right)}}{{{\text{0}}{\text{.600 mol/L}}}}\n&= 0.{\text{9 mol/L}}\n\end{aligned}$

Initially, 0.6 moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ were present in a 1-L container. But now 0.9 moles of ${\text{C}}{{\text{O}}_{\text{2}}}$ are present in it. So the extra amount of ${\text{C}}{{\text{O}}_{\text{2}}}$ can be calculated as follows:

$\begin{aligned}{\text{Amount of C}}{{\text{O}}_{\text{2}}}{\text{ added}} &= 0.{\text{9 mol}} - 0.{\text{6 mol}}\n&= 0.{\text{3 mol}}\n\end{aligned}$