What is the percent composition by mass of nitrogen in (NH4)2CO3 (gram-formula mass = 96.0 g/mol)? (1) 14.6%
(2) 29.2%
(3) 58.4%
(4) 87.5%

Answers

Answer 1
Answer:

The percentage composition by mass of nitrogen in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is \boxed{\left( 2 \right){\text{ 29}}{\text{.2 \% }}}.

Further explanation:

The most commonly applied concentration terms are as follows:

1. Molality

2. Mole fraction

3. Molarity

4. Parts per million

5. Mass percent

6. Volume percent

7. Percentage composition

The given compound is {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}. It contains two atoms of nitrogen, eight atoms of hydrogen, one atom of carbon and three atoms of oxygen.

The mass of nitrogen in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} can be calculated as follows:

{\text{Mass of N}} =\left( {{\text{Number of nitrogen atoms}}} \right)\left( {{\text{Molar mass of nitrogen}}} \right)              …… (1)

The number of N atoms in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is 2.

The molar mass of nitrogen is 14.01 g/mol.

Substitute these values in equation (1).

 \begin{aligned}{\text{Mass of nitrogen}} &= \left( {\text{2}} \right)\left( {{\text{14}}{\text{.01 g/mol}}} \right)\n&= 28.02{\text{ g/mol}}\n\end{aligned}

The formula to calculate the percentage composition of N in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is as follows:

{\text{\%  composition of N}} = \left( {\frac{{{\text{Mass of N}}}}{{{\text{Mass of }}{{\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)}_{\text{2}}}{\text{C}{{\text{O}}_{\text{3}}}}}} \right){\text{100 \% }}                                       …… (2)

The mass of N is 28.02 g/mol.

The mass of {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is 96.0 g/mol.

Substitute these values in equation (2).

\begin{aligned}{\text{\%  composition of N}} &= \left( {\frac{{{\text{28}}{\text{.02 g/mol}}}}{{{\text{96}}{\text{.0 g/mol}}}}} \right){\text{100 \% }}\n&= {\text{29}}{\text{.1875 \% }} \n &\approx {\text{2}}{\text{.92 \%}}\n\end{aligned}  

Therefore the percentage composition by mass of nitrogen in {\left( {{\text{N}}{{\text{H}}_{\text{4}}}} \right)_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} is 29.2 %.

Learn more:

  1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: brainly.com/question/3064603
  2. What is the concentration of alcohol in terms of molarity? brainly.com/question/9013318  

Answer details:

Grade: Senior School

Chapter: Concentration terms

Subject: Chemistry

Keywords: (NH4)2CO3, N, nitrogen, mass, 2.92 %, 96.0 g/mol, 28.02 g/mol, nitrogen, hydrogen, carbon, oxygen, mass of N, mass of (NH4)2CO3.

Answer 2
Answer:

The % composition of nitrogen is 29.166% ~ 29.2%. Thus option 2 is correct.

The percent composition of nitrogen in ammonium carbonate can be calculated as:

% Composition = \rm (mass\;of\;element)/(mass\;of\lcompound)\;*\;100

Mass of nitrogen in the compound has been:

Number of Nitrogen atoms = 2

Mass of 1 nitrogen atom = 14 g/mol

Mass of 2 nitrogen atom = 28 g/mol

Mass of compound = 96 g/mol

% Composition of nitrogen = \rm (28)/(96)\;*\;100

% Composition of nitrogen = 29.166 %

The % composition of nitrogen is 29.166% ~ 29.2%. Thus option 2 is correct.

For more information about the percent composition, refer to the link:

brainly.com/question/17505281


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