What is the sum of the first five terms of the geometric sequence in which a1=5 and r=1/5?

The Equation of life expectancy is x- 0.4(2) = 80.2.

What is Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

The life expectancy of a woman born in 1995 was 80.2 years.

The life expectancy increased 0.4 year every 5 years.

So, from 1995 to 2005 there are two times the life expectancy increase.

let the lifeexpectancy by x.

Thus, the equation is

x- 0.4(2) = 80.2

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Answer:

a. L - 0.4(2)= 80.2 or L - 80.2 = 0.4(2) or 80.2 + 0.4(2) = L

b. No; The equations must be equivalent. They may look different, but all equations can be rewritten as L= 80.2 + 0.4(2).

Step-by-step explanation:

To find the probability that exactly n cards are dealt before the first ace appears, we can use the concept of a geometric distribution. In a geometric distribution, we're interested in the number of trials (in this case, card draws) required for a success to occur (in this case, drawing an ace) for the first time.

The probability of drawing an ace in a single draw from a well-shuffled pack of 52 cards is 4/52 because there are 4 aces out of 52 cards.

So, the probability of drawing a non-ace in a single draw is (52 - 4)/52 = 48/52.

Now, let X be the random variable representing the number of cards drawn before the first ace appears. X follows a geometric distribution with parameter p, where p is the probability of success on a single trial.

P(X = n) = (1 - p)^(n - 1) * p

In this case, p is the probability of drawing an ace on a single trial, which is 4/52, and n is the number of cards drawn before the first ace.

So, the probability that exactly n cards are dealt before the first ace appears is:

P(X = n) = (1 - 4/52)^(n - 1) * (4/52)

Now, to find the probability that exactly k cards are dealt in all before the second ace appears, we need to consider two scenarios:

1. The first ace appears on the nth card, and the second ace appears on the kth card after that. This is represented by P(X = n) * P(X = k).

2. The first ace appears on the kth card, and the second ace appears on the nth card after that. This is represented by P(X = k) * P(X = n).

So, the total probability that exactly k cards are dealt before the second ace appears is:

P(X = n) * P(X = k) + P(X = k) * P(X = n)

You can calculate this probability using the formula for the geometric distribution with p = 4/52 as mentioned earlier for both P(X = n) and P(X = k).