MATHEMATICS HIGH SCHOOL

In which quadrant is the number –14 – 5i located on the complex plane?I
II
III
IV
In which quadrant is the number –14 – 5i located on the complex plane? I II III IV

Answers

Answer 1

Answer:

Answer:

III

Step-by-step explanation:

go 14 left and 5 down, and you're in the third quadrant

Answer 2

Answer:

Answer:

III (Third quadrant)

Step-by-step explanation:

Okay, in terms of complex numbers, the x axis is the imaginary scale while the y axis is the real scale. And this works just like a normal x and y axis! We can break down -14-5i into -5i and -14, and -5i is the imaginary number on the x axis, so we move five units to the left from the origin. -14 is the real number, so we then move down 14 units, and we end up with a coordinate that is in the III, or third, quadrant. Hope this helps! :)

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If 3 1/2 pounds of bananas cost $.98, how much would one pound cost?

Answers

The way you would find how much one pound costs is divide .98 by 3 1/2. 3 1/2 in decimal form is 3.5 so .98 ÷ 3.5 = .28

So one pound of bananas would cost $0.28

Hope that helped!

98/3.5=28 centsratio and proportion3.5/98=1/xcross multiplyx= 28 cents

How does multiplication relate to time conversion?

Answers

that would first be a conversion factor is a number used to change one set of units to another, by multiplying or dividing. when a conversion is necessasry

What is the problem of this solving?!

Answers

This question can be solved primarily by L'Hospital Rule and the Product Rule.

$y= \lim_(x \to 0) (x^2cos(x)-sin^2(x))/(x^4)$

I) Product Rule and L'Hospital Rule:

$y= \lim_(x \to 0) ([2xcos(x)-x^2sin(x)]-2sin(x)cos(x))/(4x^3)$

II) Product Rule and L'Hospital Rule:

$y= \lim_(x \to 0) ([-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)])/(12x^2) \n y= \lim_(x \to 0) (2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x))/(12x^2)$

III) Product Rule and L'Hospital Rule:

$]y= \alpha + \beta \n \n \alpha =\lim_(x \to 0) (-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)])/(24x) \n \beta = \lim_(x \to 0) (4sin(x)cos(x)+4sin(x)cos(x))/(24x) \n \n y = \lim_(x \to 0) (-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x))/(24x)$

IV) Product Rule and L'Hospital Rule:

$y = \phi + \varphi \n \n \phi = \lim_(x \to 0) (-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)])/(24x) \n \varphi = \lim_(x \to 0) ([2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)])/(24x)$

V) Using the Definition of Limit:

$y= (-6*1-4*1-2*1+8*1^2)/(24) \n y= (-4)/(24) \n \boxed {y= (-1)/(6) }$

Barney and Betty break into a parking meter with $5.05 in dimes and quarters in it, and agree that Barney get all the dimes, and Betty will get all the quarters. Barney ends up with five more coins than Betty. How much money did each get?

Answers

so remember that a quarter=25 cents and a dime=10 cents so
represent q=# of quarters
d=# of dimes

so barney gets dimes so replace barney with d and betty with q
barney get 5 more coins than betty
d=5+q
total=5.05=0.25q+0.10d since each is worth 0.25 and 0.10 so we have
d=5+q and 5.05=0.25q+0.10d
subsitue (5+q) for d
5.05=0.25q+0.10(5+q)
distribute
5.05=0.25q+0.50+0.10q
add like terms
5.05=0.35q+0.50
subtract 0.50 from both sides
4.55=0.35q
divide both sides by 0.35
13=q
subsitute
d=5+q
d=5+13
d=18

barney got 18 coins and betty got 13 coins

Jeremy wants to buy a new computer. The saleswoman says that he can make a down payment and then pay for the computer in installments.Here's a formula that describes this scenario:

x=t-yz

x = Amount down
y = Money each month
z = Number of months
t = Total price

Rewrite the formula to solve for the amount of money Jeremy must pay each month.

Answers

Answer: $y=(t-x)/(z)$

Step-by-step explanation:

Given: A formula that describes this scenario:

$x=t-yz$

where, x = Amount down

y = Money each month

z = Number of months

t = Total price

To solve the formula for the amount of money Jeremy must pay each month i.e. y, first subtract t on both sides of the equation, we get,

$x-t=-yz\n\n\Rightarrow\ yz=t-x$

Now, divide z on both sides, we get

$y=(t-x)/(z)$

The correct answer is:

$y=(-x+t)/(z)$

Explanation:

We want to solve for the amount of money he pays each month. This is represented by y in the equation. This means we want to isolate y in the equation:

x = t - yz

We first want to subtract t from each side:

x - t = t - yz - t

x - t = -yz

Now we want to cancel the negative sign and z. We can isolate both of these at the same time; divide both sides by -z: