A sphere fits snugly inside a cube with 2.4 m. edges. What is the approximate volume of the space between the sphere and cube to the nearest tenth?

Answers

Answer 1
Answer: Area of cube = s*s*s = 2.4 * 2.4 * 2.4 = 13.824 m³

Since the sphere is snugly fit in the cube, so the diameter of the sphere is equal to the length of the cube.

d = 2.4m, radius, r = d/2 = 2.4/2 = 1.2 m

Volume of sphere = (4/3)πr³

                                 = (4/3)*π*1.2*1.2*1.2 = 2.304π

                                 ≈ 2.304*3.1416 ≈ 7.2382 m³

Volume of space between sphere and cube = Volume of cube - Volume of sphere

                                                     = 13.824 m³ - 7.2382 m³ = 6.5858 m³

Volume ≈ 6.6 m³      to the nearest tenth

Hope this helps.

Related Questions

Enter the symbol (<, >, or =) that correctly completes this comparison.0.147 0 0.174
Melinda goes bowling on saturday afternoons.She bowls three games and pays for shoe rental.Define a variable and write an expression to represent the total cost Melinda pays.Then find the total cost if one Game cost
Please help! ASAP correct answer will get brainliest!!!
Identify the initial amount a and the growth factor b in the exponential function. A(x) = 680 • 4.3x
ree heights: Cherry trees in a certain orchard have heights that are normally distributed with mean μ = 119 inches and standard deviation σ = 17 inches. Use the TI-84 PLUS calculator to answer the following. Round the answers to at least four decimal places. (a) What proportion of trees are more than 130 inches tall? (b) What proportion of trees are less than 90 inches tall? (c) What is the probability that a randomly chosen tree is between 95 and 105 inches tall? Part: 0 / 30 of 3 Parts Complete Part 1 of 3 What proportion of trees are more than 130 inches tall? The proportion of trees that are more than 130 inches tall is .

HELP PLS Could use some assistance ​

Answers

Answer:C

Step-by-step explanation:

A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded. The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B: 4.90 hrs < μ1 - μ2 < 17.50 hrs
What does the confidence interval suggest about the population means?

A. The confidence interval includes 0 which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
C. The confidence interval includes only positive values which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Answers

This question is not complete, I got the complete one from google as below:

A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded.

The summary statistics are as follows.

Type A                                   Type B

x1 = 76.3 hrs                       x2 = 65.1 hrs

s1 = 4.5 hrs                          s2 = 5.1 hrs

n1 = 11                                  n2 = 9

The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B:

4.90 hrs < μ1 - μ2 < 17.50 hrs

What does the confidence interval suggest about the population means?

A. The confidence interval includes 0 which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

C. The confidence interval includes only positive values which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Answer:

Option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

Step-by-step explanation:

The 98% confidence interval for the difference in mean drying times of the two types of paints is (4.90, 17.50). This implies that Type A takes between 4.90 and 17.50 hours more to dry than type B paint.

Thus, option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

A segment has endpoints A (-1, 1) and B (8, 4) .If the segment is divided into four equal parts, the coordinates of the point closest to point A are _____?

Answers

Answer:

fafafsghdjdbdbdgsysvdve. wwmsk

326 divided by 53 sender

Answers

26 divided by 53 equals 6 with a remainder of 8.

To solve 326 divided by 53 using long division, let's go step by step:

         6

  ------------

53 | 326

1. First, we divide 53 into 32. The largest multiple of 53 that fits into 32 is 0. So, we bring down the next digit from 326, which is 6.

         6

  ------------

53 | 326

    -

2. We now have 326. We divide 53 into 326, which gives us 6. The quotient is written above the line.

         6

  ------------

53 | 326

    - 318

3. We subtract 318 from 326, which gives us 8.

         6

  ------------

53 | 326

    - 318

    -----

         8

4. We have a remainder of 8. Since there are no more digits to bring down, we have our final result.

Therefore, 326 divided by 53 equals 6 with a remainder of 8.

Learn more about division here

brainly.com/question/13683748

#SPJ6

Answer: 6.150943396

6.15 if rounded

Step-by-step explanation:

Find the lcm of 2,3,7 and tell me how u got ur answerif its CORRECT with ur reasoning ill give brainlest

Answers

Answer:

42

Step-by-step explanation:

help!!!! It’s missing and I forgot to do but I need the answers 1-4 thank you so much your a life saver

Answers

1. No solution
2. y= -3x/4-5/2
3. x=8+y
4 I can’t really see it