Solve the potential energy at point B
PE = mgh
Where m is the mass
G is the acceleration due to gravity 9.8 m/s2
H is the height
PE = ( 1.5 kg) ( 9.8 m/s2) (0.5 m)
PE = 7.35 J
Solve the velocity using the
KE = 0.5mv^2
Where ke is the kinetic energy
M is the mass
V is the velocity
Since all energy is converted to KE
So KE = PE
7.35 = 0.53(1.5) v^2
V = 3.13 m/s
The velocity of the ball at position A is equal to 3.13 m/s.
Given the following data:
Mathematically, potential energy is given by this formula:
Where:
Substituting the given parameters into the formula, we have;
P.E = 7.35 Joules.
Assuming there’s no air resistance, the potential energy would be equal to kinetic energy.
V = 3.13 m/s.
Read more on potential energy here: brainly.com/question/1242059
Summarize it!
c The
Time Elapsed: 45
D
-0.5 m
10 m
15 m
20 m
0.5 m
I. 0.5 m
Answer:
cbccfggssdaffzftyrd
Answer:c
Explanation:
Given
Alice launches with horizontal velocity
Tom simply drops straight down from the edge
Time taken by both the person is same as they have same initial vertical velocity i.e. zero so the time taken to reach the ground is zero.
Although Alice will travel more horizontal distance compared to Tom.
Thus option c is correct
Is my answer right?? Plzz help
29 million people in the U.S.
Horsepower= 746 W
The above is the info you will need. This is what I have done so far, but it can NOT be right:
98.3*10^15Btu/year(1 year/365 days) = 0.269315*10^15 Btu/day (0.269315*10^15Btu/day)/291 million = (0.2693*10^15 Btu/day)/291*10^6 ~0.00092548109*10^5 Btu/day = 925,481.09Btu/day
925,481.09Btu/day*(1day/24hour) = 38561.71 Btu/hour ~ 38561.7Btu/hour
1horsepower = 746 W
1 W = 3.412Btu/hr38561.7Btu/hr*(1 W/3.412 Btu/hr) ~ 11301.3 W*(1 hp/746 W) = 15.149 hp
B) increases; increases
C) decreases; increases
D) decreases; decreases
C) decreases; increases