24 POINTS!!!!!!!!!!!!!!!!!!Sarah, who has a mass of 55 kg, is riding in a car at 20 m/s. She sees a cat crossing the street and slams on the brakes! Her seatbelt stops her from flying forward, bringing her to rest in 0.5 seconds. How much force did the seatbelt put on Sarah?

Answers

Answer 1
Answer:

F = (mass)(acceleration) = ma

m = 55 kg

Vi = 20 m/s

t = 0.5 s

Vf = 0 m/s (since she was put to rest)

a=(Vf-Vi)/t

a=(0-20)/5

a = 40 m/s^2 (decelerating)

F = ma = (55 kg)(40 m/s^2)

F = 2200 N

Hope this answer will be a good help for you.
Answer 2
Answer:  change of momentum =mv-mu=m(v-u)=55(0-20)=-1100
rate of change of momentum=-1100/0.5=-2200  this is equal to force applied.
so force=-2200 kg/m^2
negative sign shows force acts in opposite direction to motion.

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If angle ABE = 2n + 7 and angle EBF=4n-13,
find angle ABE.​

Answers

Answer:

The measure of angle ABE is 27°.

Explanation:

Consider the below figure attached with this question.

Given information: ∠ABE=2n+7 and ∠EBF=4n-13.

From the below figure it is clear that ∠ABE and ∠EBF are congruent.

m\angle ABE=m\angle EBF

2n+7=4n-13

Isolate variable terms on one side.

7+13=4n-2n

20=2n

Divide both sides by 2.

10=n

The value of n is 10.

We need to find the measure of ∠ABE.

\angle ABE=2(10)+7=20+7=27

Therefore, the measure of angle ABE is 27°.

The measure of angle ABE is 27°.

Since the angles are congruent, therefore, ∠ABE=2n+7 and ∠EBF = 4n-13 will be equated to each other.

This will be;

2n+7 = 4n-13

Collect like terms

4n-2n = 7+13

2n  = 20  

Divide both sides by 2.  

2n/2 = 20/2

n = 10  

Therefore, the value of n is 10.

Since angle ABE = 2n + 7

ABE = 2[10]  + 7

= 20 + 7 =  27°.  

Therefore, the measure of angle ABE is 27°

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Answers

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Explanation:

Answer:

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Answers

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Answer:

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