A space vehicle deploys its re-entry parachute when it's traveling at a vertical velocity of -150 meters/second (negative because the parachute is going down.) It comes to rest at 0 meters/second after 30 seconds. What's the average acceleration of the shuttle during this time span?

Answers

Answer 1

Answer: Acceleration, in physics, is the rate of change of velocity of an object with respect to time. An object's acceleration is the net result of any and all forces acting on the object, as described by Newton's Second Law.
a = change in velocity / change in timea = 0 - (-150) / 30 - 0a = 5 m/s2

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The more particles a substance has at a given temperature, the more thermal energy it has.
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What is the value of current when the voltage is 8 volts

Answers

That depends on the resistance between the ends of the voltage.

A disk-shaped space station 175 m in diameter spins uniformly about an axis perpendicular to the plane of the disk through its center. How many rpm (rev/min) must this disk make so that the acceleration of all points on its rim is g/2?

Answers

The angular velocity of the disk must be 2.25 rpm

Explanation:

The centripetal acceleration of an object in circular motion is given by

$a=\omega^2 r$

where

$\omega$ is the angular velocity

r is the distance of the object from the axis of rotation

For the space station in this problem, we have

$a=(g)/(2)=(9.8)/(2)=4.9 m/s^2$ is the centripetal acceleration

The diameter of the disk is

d = 175 m

So the radius is

$r=(175)/(2)=87.5 m$

So, a point on the rim has a distance of 87.5 m from the axis of rotation. Therefore, we can re-arrange the previous equation to find the angular velocity:

$\omega = \sqrt{(a)/(r)}=\sqrt{(4.9)/(87.5)}=0.237 rad/s$

And this is the angular velocity of any point along the disk. Converting into rpm,

$\omega=0.236 (rad)/(s)\cdot (60 s/min)/(2\pi rad/rev)=2.25 rpm$

Learn more about circular motion:

brainly.com/question/2562955

#LearnwithBrainly

According to Jean Piaget, unrealistic idealism often occurs in adolescence as a result of __________.

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According to Jean Piaget, unrealistic idealism often occurs in adolescence as a result of egocentrism. Egocentrism is defined as the inability to understand or comprehend any point of view other than their own. Piaget claimed that adolescents are egocentric and are only seeing the world only from their personal point of view.

Answer:

Ego-centrism

Explanation:

dont make it hard to your self lol

Our Sun is all of the following EXCEPT ____.a. part of a binary system
c. a yellow star
b. a main sequence star
d. of average absolute magnitude

Answers

Answer:

part of a binary system

Explanation:

Sun is a yellow star, it is a G-type main sequence star. It is yellow dwarf star. It is white but from our earth, it appears yellow. So it is a yellow star.

As mentioned, yes it is a main sequence star.

It is our main part of solar system so it appears to be huge for our earth, however it stands medium in the size among all other billions of stars in the universe.

Sun is solo star, It has no companion star associated with it (as with other stars which have one or more companion star with them making binary or tertiary etc system).

A) Part of a binary system. There is no evidence to suggest that the Sun has a companion star.

Two strings of equal length are stretched out with equal tension. The second string is four times as massive as the first string. If a wave travels down the first string with velocity v , how fast does a wave travel down the second string?

Answers

It travels at a velocity of "4v"

A 5.0 g lead bullet is fired into a fence post. The initial speed of the bullet is 210 m/s, and when it comes to rest, half its kinetic energy goes into heating the bullet. How much does the bullet's temperature increase?

Answers

Given the data from the question, the bullet's temperature increases by 85.5 °C

How to determine the kinetic energy

Mass (m) = 5 g = 5 / 1000 = 0.005 g
Velocity (v) = 210 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.005 × 210²

KE = 110.25 J

How to determine the increase in temperature

Kinetic energy (KE) = 110.25 J
Heat (Q) = ½KE = ½ × 110.25 = 55.125 J
Mass (M) = 5 g
Specific heat capacity of lead (C) = 0.129 J/gºC

Change in temperature (ΔT) =?

Q = MCΔT

Divide both side by MC

ΔT = Q / MC

ΔT = 55.125 / (5 × 0.129)

ΔT = 85.5 °C

Thus, the temperature increase is 85.5 °C

Learn more about heat transfer:

brainly.com/question/6363778

5g = 0.005 kg
So KE=1/2 0.005 kg * 210m/s^2 = 110 J.
Now the specific heat capacity of lead is 126 J/kgK, so the temperature change= 55 J / 0.005 * 126 J/kgK=87.3015873 K. Which, if normal thermal conditions, the bullet would have a temperature of around 360,451587 Kelvin or, simplified, 107.3 degrees celsius.

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