Which of the following transitions will require the most thermal energy?a)1 g of ice at –15 °C to 1 g of ice at –5 °C
b)1 g of ice at –5 °C to 1 g of water at 5 °C
c)1 g of water at 5 °C to 1 g of water at 15 °C
d)1 g of water at 15 °C to 1 g of water at 25 °C

Answers

Answer 1

Answer: Here, 1 g of ice at –5 °C to 1 g of water at 5 °C will require the most thermal energy 'cause it will require some extra energy (latent heat = 80 Cal/gm for this case) for changing the phase from 0 C ice to 0 C water.

In short, Your Answer would be Option B

Hope this helps!

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When the compound Na2S forms what happens to the Na and S ions

Answers

nothing, ATOMS lose or gain electrons to become IONS
Two Na ATOMS lose 1 electron each and 1 S ATOM gains 2 electrons

Since sodium ions each have a single positive charge (lacking one electron in its valence orbital) and sulfur ions each have a 2- charge (having two extra electrons in its valence orbital), the compound Na2S forms when two sodium ions are ironically bound to a central sulfur.

Stephen and andy are sitting next to each other on a bench. according to the law of universal gravitational there should be a gravitational force between them. why don't they feel this force?A.) Universal Gravitational only applies to objects that are far from earth's surface

B.) The gravitational force is balanced out by the force of friction.

C.) The gravitational force between them is extremely small.

D.) The gravitational attraction is balanced by an equal and opposite gravitational repulsion

Answers

Answer:

C.) The gravitational force is balanced out by the force of friction.

Answer:

C. The gravitational force between them is extremely small.

Explanation:

The force of gravity is based off of the mass and distance of two objects. Stephen and Andy don't have large enough masses to feel an effect.

The park has added two more cars to the already existing roller coaster. If the park wants to maintain the speed of the roller coaster with the addition of the cars, what must it do? A) Increase the height a point A. B) Increase the heights at point A and B. C) Reduce the number of hills and dips in the course. D) Increase the friction between the wheels and the track.

Answers

D because friction will slow it down going up hills (for safety reasons) and you go really fast going down.

Answer:

Decrease the friction between the wheels and the track.

Explanation:

Decrease the friction between the wheels and the track. Friction opposes motion. If the amount of friction is decreased, the speed of the cars should increase.

This answer is for the question on usa testprep

Which salt would be the most soluble in ice water?

Answers

Answer:

the answer to the question is calcium

Final answer:

Calcium chloride is the most soluble salt in ice water due to its ability to lower the freezing point of water more than other salts.

Explanation:

When it comes to solubility in ice water, the most soluble salt would be the one that can lower the freezing point of water the most. Sodium chloride (NaCl) and its analogs calcium chloride (CaCl₂) and magnesium chloride (MgCl₂) are often used to melt ice on roads and sidewalks because they have lower freezing points than pure water. Among these salts, calcium chloride would be the most soluble in ice water. The group 2 metal salts, such as calcium chloride, dissociate to yield three particles per formula unit and provide a larger depression of the freezing point compared to sodium chloride, which dissociates to yield only two particles per formula unit.

Learn more about solubility in ice water here:

brainly.com/question/34720471

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On a weather map places that have the same temperature are joined with lines called

Answers

Those lines are called the "isotherms".

"iso..." means "same" (like "isometric" exercises")

"therm" means heat or temperature (like "thermal" underwear for camping)

Three resistors (R1 = 120 Ohms, R2 = 330 Ohms, and R3 = 240 Ohms) and an ideal inductor (L = 1.6 mH) are connected to a battery (V = 9 V) through a switch as shown in the figure below.The switch has been open for a long time before it is closed at t = 0. At what time t0, does the current through the inductor (I3) reach a value that is 63% of its maximum value?

Answers

The time at which the current through the inductor reaches 63% of the maximum current is 4.85 $\mu$ s

What is current?

The current is defined as the flow of the charge in the circuit is is the rate of flow of the charge.

At t=0 s there is no current in the circuit because the switch is not closed and the circuit is not complete. The current across the LR circuit increases exponentially, when the switch is closed, and becomes steady after a certain time.

Given that

The value of resistor is .120 ohm

The value of resistor is .330 ohm

The value of resistor is .240ohm

The value of the inductor is .1.6 mh

The voltage applied across the circuit is .9 V

To determine the value of effective resistance of this circuit we need to look at the circuit from inductor’s side i.e., from inductor’s side the resistors is connected in series with the parallel combination of resistors

The effective resistance of the circuit is:

$R_(eff)=R_a+(R_1* R_2)/(R_1+R_2)$ …… (1)

Here, $R{eff$ is the effective resistance of the circuit. Now substituting the values.

$R_(eff)=240+(120* 330)/(120+330)=328\ ohm$

The current through the inductor is:

$i=i_o(1-e^{(tR_(eff))/(L)})$ ...... (2)

Here, is the current across the inductor, io is the maximum current in the circuit and L is the inductance across the inductor.

The current across the inductor is equal to the 63% of the maximum current in the circuit.

The current across the inductor is:

i=0.63io

Substitute 0.63io for 328 ohm , for 1.6 mH and for L in equation (2).

$0.63 i_o=i_o(1-e^(-t(328))/(1.6)})$

Simplify the above expression.

$e^((-2.05*10^6))=0.37$

Taking natural log on both sides and simplify.

$t=4.85* 10^(-6)\ s$

$t=4.85 \mu s$

Thus, the time at which the current through the inductor reaches 63% of the maximum current is $t=4.85 \mu s$

To know more about current follow

brainly.com/question/24858512

The time at which the current through the inductor reaches 63% of the maximum current is $\fbox{\begin\n4.85 \mu s\end{minispace}}$ or $\fbox{\begin\n4.85 * {10^( - 6)}\,{\text{s}}\end{minispace}}$ .

Further Explanation:

At $t = 0\,{\text{s}}$ there is no current in the circuit because the switch is not closed and the circuit is not complete. The current across the LR circuit increases exponentially, when switch is closed, and becomes steady after certain time.

Given:

The value of resistor is $120\,\Omega$ .

The value of resistor is $330\,\Omega$ .

The value of resistor is $240\,\Omega$ .

The value of the inductor is $1.6\,{\text{mH}}$ .

The voltage applied across the circuit is $9\,{\text{V}}$ .

Concept:

To determine the value of effective resistance of this circuit we need to look at the circuit from inductor’s side i.e., from inductor’s side the resistors ${R_3}$ is connected in series with the parallel combination of resistors ${R_1}$ and ${R_2}$ .

The effective resistance of the circuit is:

$\fbox{\begin\n{R_(eff)} = {R_3} + \frac{{{R_1} * {R_2}}}{{{R_1} + {R_2}}}\end{minispace}}$ …… (1)

Here, ${R_(eff)}$ is the effective resistance of the circuit.

Substitute the $120\,\Omega$ for ${R_1}$ , $330\,\Omega$ for ${R_2}$ and $240\,\Omega$ for ${R_3}$ in equation (1).

$\begin{aligned}{R_(eff)}&=240\,\Omega+\frac{{\left( {120\,\Omega } \right) * 330\,\Omega }}{{120\,\Omega +330\,\Omega }} \n&=328\,\Omega\n \end{aligned}$

The current through the inductor is:

$\fbox{\begin\ni = {i_0}\left( {1 - {e^{ - \frac{{t{R_(eff)}}}{L}}}} \right)\end{minispace}}$ ...... (2)

Here, $i$ is the current across the inductor, ${i_0}$ is the maximum current in the circuit and $L$ is the inductance across the inductor.

The current across the inductor is equal to the 63% or times of the maximum current in the circuit.

The current across the inductor is:

$i = 0.63{i_0}$

Substitute $0.63{i_0}$ for $i$ , $328 \Omega$ for ${R_(eff)}$ and $1.6\,{\text{mH}}$ for $L$ in equation (2).

$0.63{i_0} = {i_0}\left( {1 - {e^{ - \frac{{t\left( {328\Omega } \right)}}{{\left( {1.6\,{\text{mH}}} \right)}}}}} \right)$

Simplify the above expression.

${e^{ - \left( {2.05 * {{10}^6}} \right)t}}= 0.37$

Taking natural log on both sides and simplify.

$\begin{aligned}t&=4.85\, * {10^( - 6\,)}\,{\text{s}} \n&=4.85\mu \text{s}}\n\end{aligned}$

Thus, the time at which the current through the inductor reaches 63% of the maximum current is $\fbox{\begin\n4.85 \mu s\end{minispace}}$ or $\fbox{\begin\n4.85 * {10^( - 6)}\,{\text{s}}\end{minispace}}$ .

Learn more:

1. Conservation of energy brainly.com/question/3943029

2. Average translational energy brainly.com/question/9078768

3. The motion of a body under friction brainly.com/question/4033012

Answer Details:

Grade: Middle School

Subject: Physics

Chapter: Current Electricity

Keywords:

Resistor circuit, LR circuit, current, current across inductor, time constant, 4.85 microsecond, 4.85 microsec, 4.85 micros, 4.85*10-6 s, 4.85*10^6 s, 4.85*10-6 sec, 4.85*10^6 sec.

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