Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?

Answers

Answer 1
Answer:

Answer:

\cos (a-b)=\cos a \cos b+\sin a \sin b

Step-by-step explanation:

 Given : \cos (180^(\circ)-q)=-\cos q

We have to write which identity we will use to prove the given statement.

Consider \cos (180^(\circ)-q)=-\cos q

Take left hand side of given expression \cos (180^(\circ)-q)

We know

\cos (a-b)=\cos a \cos b+\sin a \sin b

Comparing , we get, a= 180° and b = q

Substitute , we get,

\cos (180^(\circ)-q)=\cos 180^(\circ)  \cos (q)+\sin q \sin 180^(\circ)

Also, we know \sin 180^(\circ)=0 and \cos 180^(\circ)=-1

Substitute, we get,

\cos (180^(\circ)-q)=-1\cdot \cos (q)+\sin q \cdot 0

Simplify , we get,

\cos (180^(\circ)-q)=-\cos (q)

Hence, use difference identity to  prove the given result.

Answer 2
Answer: cos (180° - q) = -cos q
First you would use the sum and difference formula of 
cos(a – b) = cos(a)cos(b) + sin(a)sin(b) because you have a difference inside the parentheses for cosine.

Hope this helps.

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Were these answers right? It not explain why please xx it's meant to be in12 hour clock

Answers

The answers are both correct, but perhaps incomplete.

I see 'X's marked next to the two answers.  If those mean that
your answers were marked 'wrong', then I think the problem is this:

-- The top one should have been "10:00 AM".

-- The bottom one should have been "10:39 PM".

The current (I) in an electrical conductor varies inversely as the resistance (R) of the conductor. The current is 6 amperes when the resistance is 722 ohms. What is the current when the resistance is 768 ohms? Round your answer to two decimal places if necessary.

Answers

Answer:

The current is 5.64 Ampere when resistance is  768 ohms .

Step-by-step explanation:

As given

The current (I) in an electrical conductor varies inversely as the resistance (R) of the conductor.

Thus

I \propto (1)/(R)

I=(k)/(R)

Where k is the constant of proportionality .

The current is 6 amperes when the resistance is 722 ohms.

I = 6 amperes

R = 722 ohms

Put all the values in the formula

6=(k)/(722)

k = 6 × 722

k = 4332

As given

when the resistance is 768 ohms .

R = 768 ohms

K = 4332

Put in the formula I=(k)/(R) .

I=(4332)/(768)

I = 5.64 Ampere

Therefore the current is 5.64 Ampere when resistance is  768 ohms .

Basically, this is Ohm's Law:
V=RI where V is the tension in volts;
You have that V=722×6=4332 Volts
Using this value for V you have that:
4332=768×I
So I=5.64 A

HELP ME LOOK AT THE PICTURE

Answers

Part A
Choice 2- The difference between 2 and -1 is -3.

Part B
Martha's total score is -2

44 is 22% of what number

Answers

You can find this by the proportion 44/x=22/100, which is 200, so 44 is 22 percent of 200
Look at it like this 44=.22 x n for instance, beacuse 44 is 22% of (of implying multiplication) some number
Now simplify to 44=.22n
Divide 44 by .22 and theres your answer
N=... Well, ill let you figure that on your own

A Geometry student says I got lost in that lesson I wrote down that AD/AB eQUALS AC/ab but I have no idea where comes from

Answers

Answer:

AD/AB = AB/AC

Step-by-step explanation:

If we take two triangules in that figure: ABC and ABD, both are triangles rectangles. We need to use the definition of cosine, with the angle in th A corner, we called ∅.

For the ABC triangle: cos(∅) = adjacent cathetus/hypotenuse = AD/AB

For the ABD triangle: cos(∅) = adjacent cathetus/hypotenuse = AB/AC

Then:

cos(∅) = AD/AB = AB/AC

The average reading score on a certain test is given by y=0.150x +255.34 where x is the number of years past 1970 . In what year would the average reading score be 259.24 if this model was accurate

Answers

Answer:

The average was 259.24 in 1996.

Step-by-step explanation:

In order to find the year that the average, "y", is 259.24 we need to apply this value on the given expression, as done below:

259.24 = 0.15*x + 255.34\n0.15*x = 259.24 - 255.34\n0.15*x =3.9\nx = (3.9)/(0.15)\nx = 26

The average was 259.24 after 26 years, therefore it was in 1996.