Prove the Pythagorean Theorem using similar triangles. The Pythagorean Theorem states that in a right triangle, the sum of the squares of the lengths of the legs of the triangle equals the squared length of the hypotenuse. Be sure to create and name the appropriate geometric figures.

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Answer 1

Answer: For the answer to the question above asking to prove the Pythagorean Theorem using similar triangles. The Pythagorean Theorem states that in a right triangle,
A right triangle consists of two sides called the legs and one side called the hypotenuse (c²) . The hypotenuse (c²) is the longest side and is opposite the right angle.

⇒ α² + β² = c²

"In any right triangle ( 90° angle) , the sum of the squared lengths of the two legs is equal to the squared length of the hypotenuse."

For example: Find the length of the hypotenuse of a right triangle if the lengths of the other two sides are 3 inches and 4 inches.
c2 = a2+ b2
c2 = 32+ 42
c2 = 9+16
c2 = 15
c = sqrt25
c=5

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The same sample of 25 seniors from the urban school district with the mean and standard deviation N(450, 100). A 95% confidence interval for µ for the population of seniors with a margin of error of ± 25 is used. What is the smallest sample size we can take to achieve this same margin of error?26

45

50

62

69

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I have some notes here that might help you answer the problem in your own:

The formula to calculate a minimum sample size is as follows:

n = [z*s/E]^2

Where n is the sample size, z is the z value for the level of confidence chosen, s is the estimated standard deviation and E is the allowable error.

I hope my answer has come to your help. God bless and have a nice day ahead!

the probability of getting an even number (but not 0) is 4/10using a game spinner. the denominator of the probability is

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Answer: The total number of outcomes.

Step-by-step explanation:Apex

10 because the ratio is 4/10 and the bottom number is the denominator

Determine which transformation occurred:M(4, -1), A(-2, 2), T(-5, -3)
M'(-4,1), A'(2,-2), T'(5, 3)

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Answer:

Reflection over both y and x axes

Step-by-step explanation:

So we can see that all points have become their negative. If this only applied to x coordinates, this would have been a relfection over the y axis. If it only applied to x, it would be a reflection over the x. But since it applies to both, the answer is that it was a reflection over both axes.

Answer:

Rotation

Step-by-step explanation:

See below. Hope it helps:)

Tai resized a photograph that was 8 inches by 10 inches so that it would fit on a 4 inch by 4 inch page. Find the maximum dimensions of the reduced photograph. An explanation wold be great, please. Thank you so much!

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ok so it has to be max 4 inches when resized since the max size is 4 inches

10 is max of original so
they have to be shrunk in same ratio so find ratio of shrink
10 times ratio=4
divide both sides by 10
ratio=4/10=2/5
so multiply the measuremet by 2/5 to find new dimention

8 times 2/5=16/5=3 and 1/5=3.2

new dimentions is 4 by 3.2 inches

R + 11 + 8r= 29
Show answer

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Answer:

r=2

Step-by-step explanation:

r + 8 r + 11 = 29

( 1 + 8 ) r + 11 = 29 9 r + 11 = 29

Now we can isolate and solve for r while always keeping the equation balanced: First, subtract 11 from each side of the equation:

9 r + 11 − 11 = 29 − 11

9 r + 0 = 18

9 r = 18

Now we can divide each side of the equation by 9 to get

r : 9 over 9 = 18 under 9

1 r = 2

r = 2

Answer: r = 2

Steps:

r + 8r + 11 = 29

9r + 11 = 29

9r + 11 - 11 = 29 - 11

9r = 18

r = 2

plz mark brainliest

Please Help ASAP!!!!

Answers

Answer:

$m\angle M = 98\degree$

Step-by-step explanation:

As we know that:

Sum of the measure of all interior angles of a triangle is always 180°.

$\therefore (3x-16)\degree+(x+6)\degree+ x\degree = 180\degree\n\therefore (5x-10)\degree = 180\degree\n5x-10 = 180\n5x = 180 + 10\n5x = 190\nx= (190)/(5)\nx= 38\n\because m\angle M = (3x-16)\degree\n\therefore m\angle M = (3* 38 -16)\degree\n\therefore m\angle M = (3* 38 -16)\degree\n\therefore m\angle M = (114 -16)\degree\n\therefore m\angle M = 98\degree$

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